英文:
Date parsing in Go
问题
我正在尝试解析由tar生成的时间戳，例如'2011-01-19 22:15'，但无法理解time.Parse的奇怪API。
以下代码会产生'parsing time "2011-01-19 22:15": month out of range'的错误提示：
package main
import (
"fmt"
"time"
)
func main () {
var time , error = time.Parse("2011-01-19 22:15","2011-01-19 22:15")
if error != nil {
fmt.Println(error.String())
return
}
fmt.Println(time)
}
英文:
I'm trying to parse a timestamp as produced by tar such as '2011-01-19 22:15' but can't work out the funky API of time.Parse.
The following produces 'parsing time "2011-01-19 22:15": month out of range'
package main
import (
"fmt"
"time"
)
func main () {
var time , error = time.Parse("2011-01-19 22:15","2011-01-19 22:15")
if error != nil {
fmt.Println(error.String())
return
}
fmt.Println(time)
}
答案1
得分: 39
按照Go time package 文档中的说明进行操作。
> 标准时间的格式为：
>
>
> > Mon Jan 2 15:04:05 MST 2006 (MST 表示
> > GMT-0700)
>
> 这对应的Unix时间为 1136243045。（可以将其理解为 01/02 03:04:05PM '06 -0700。）
> 如果要定义自己的格式，可以按照自己的方式编写。
例如，
package main
import (
"fmt"
"time"
)
func main() {
t, err := time.Parse("2006-01-02 15:04", "2011-01-19 22:15")
if err != nil {
fmt.Println(err)
return
}
fmt.Println(time.SecondsToUTC(t.Seconds()))
}
输出结果: Wed Jan 19 22:15:00 UTC 2011
英文:
Follow the instructions in the Go time package documentation.
> The standard time used
> in the layouts is:
>
>
> > Mon Jan 2 15:04:05 MST 2006 (MST is
> > GMT-0700)
>
> which is Unix time 1136243045. (Think
> of it as 01/02 03:04:05PM '06 -0700.)
> To define your own format, write down
> what the standard time would look like
> formatted your way.
For example,
package main
import (
"fmt"
"time"
)
func main() {
t, err := time.Parse("2006-01-02 15:04", "2011-01-19 22:15")
if err != nil {
fmt.Println(err)
return
}
fmt.Println(time.SecondsToUTC(t.Seconds()))
}
Output: Wed Jan 19 22:15:00 UTC 2011
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