如何让我的对角线从星号框的左下方开始打印？

huangapple
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英文:

how do I get my diagonal line to start printing from the bottom left of my asterik box?

问题

我正在编写一个代码，用于练习创建方法并在主方法中调用这些方法。我在输出方面遇到了问题，输出结果与预期不符。代码应该根据输入的数字9创建一个方框。以下是我的代码输出：

  1. *********
  2. *+      *
  3. * +     *
  4. *  +    *
  5. *   +   *
  6. *    +  *
  7. *     + *
  8. *      +*
  9. *********

我无法弄清楚如何使斜线“+”从方框的左下角开始，到达右上角。我的代码如下：

  1. public static void main(String[] args) {
  2.     System.out.print(boxWithMinorDiagonal(9));
  3. }
  5. public static int boxWithMinorDiagonal(int n) {
  6.     for (int col = 1; col <= n; col++) {
  7.         for (int row = 1; row <= n; row++) {
  8.             if (row == 1 || col == 1 || row == n || col == n) {
  9.                 System.out.print("*");
  10.             } else if (col == row) {
  11.                 System.out.print("+");
  12.             } else {
  13.                 System.out.print(" ");
  14.             }
  15.         }
  16.         System.out.println();
  17.     }
  18.     return n;
  19. }

我认为我需要让行（row）和列（col）从左下角开始，从那里开始斜线，但我不确定我需要在for循环中做哪些更改，以使行和列从左下角开始。

英文:

I am making a code that is to practice for creating methods and calling them in the main method. I am having trouble with an output that is not exactly how it is supposed to look like. The code is supposed to create a box based on the input 9. This is the output of my code:

  1. *********
  2. *+      *
  3. * +     *
  4. *  +    *
  5. *   +   *
  6. *    +  *
  7. *     + *
  8. *      +*
  9. *********

I can't figure out how to get the "+" diagonal to start from the bottom left of the box to the top right. my code is this:

  1.  public static void main(String[] args)
  2.    {
  3.    System.out.print(boxWithMinorDiagonal(9));
  4.    }
  5.    
  6.    public static int boxWithMinorDiagonal(int n){
  7.       for (int col = 1; col &lt;= n; col++) {
  8.          for (int row = 1; row &lt;= n; row++) {
  9.              if(row == 1 || col == 1 || row == n || col == n){
  10.                System.out.print(&quot;*&quot;);
  11.               }
  12.              else if (col == row){
  13.              System.out.print(&quot;+&quot;);
  14.              }
  15.             else{
  16.             System.out.print(&quot; &quot;);
  17.             }
  18.        
  19.          
  21.       }
  22.        System.out.println();
  23.       }
  24.       return n;
  25.       }

I think I need to get the row and col to start from the bottom left, which would start the diagonal from there, but am not exactly sure what I would need to change in my for loops to get the row and col to start from the bottom left.

答案1

得分: 1

现在，如果例如 col 为 1 且 row 为 1，或者 col 为 2 且 row 为 2，你会绘制一个星星。

制作一个表格，列出应该在从左下到右上方向上产生星星的行/列组合，然后尝试找出其中的规律，可以用数学运算的方式来表示，以返回一个布尔值。

提示：col + row == something 可能是你想要查看的内容。

英文:

Right now you draw a star if e.g. the col is 1 and the row is 1, or the col is 2 and the row is 2.

Make a table of which row/col combos should produce a star for bottom-left to top-right, then try to find a pattern in this you can put in terms of a mathematical operation that returns a boolean.

HINT: col + row == something might be something you want to check out.

答案2

得分: 0

只需更改这部分代码：else if (col == n-row+1){ System.out.print(&quot;+&quot;);}
那么你的代码将变为：

  1. {
  2.     System.out.print(boxWithMinorDiagonal(9));
  3. }
  5. public static int boxWithMinorDiagonal(int n){
  6.     for (int col = 1; col <= n; col++) {
  7.         for (int row = 1; row <= n; row++) {
  8.             if(row == 1 || col == 1 || row == n || col == n){
  9.                 System.out.print(&quot;*&quot;);
  10.             }
  11.             else if (col == n-row+1){
  12.                 System.out.print(&quot;+&quot;);
  13.             }
  14.             else{
  15.                 System.out.print(&quot; &quot;);
  16.             }
  17.         }
  18.         System.out.println();
  19.     }
  20.     return n;
  21. }

然后你将获得以下输出：

  1. *********
  2. *      +*
  3. *     + *
  4. *    +  *
  5. *   +   *
  6. *  +    *
  7. * +     *
  8. *+      *
  9. *********
  10. 9
英文:

just change this part :else if (col == n-row+1){ System.out.print(&quot;+&quot;);}
So your code will be :

  1.     {
  2.         System.out.print(boxWithMinorDiagonal(9));
  3.     }
  5.     public static int boxWithMinorDiagonal(int n){
  6.         for (int col = 1; col &lt;= n; col++) {
  7.             for (int row = 1; row &lt;= n; row++) {
  8.                 if(row == 1 || col == 1 || row == n || col == n){
  9.                     System.out.print(&quot;*&quot;);
  10.                 }
  11.                 else if (col == n-row+1){
  12.                     System.out.print(&quot;+&quot;);
  13.                 }
  14.                 else{
  15.                     System.out.print(&quot; &quot;);
  16.                 }
  20.             }
  21.             System.out.println();
  22.         }
  23.         return n;

and you'll get this:

  1. *********
  2. *      +*
  3. *     + *
  4. *    +  *
  5. *   +   *
  6. *  +    *
  7. * +     *
  8. *+      *
  9. *********
  10. 9

huangapple
  • 本文由 发表于 2020年10月28日 08:08:13
  • 转载请务必保留本文链接：https://go.coder-hub.com/64564665.html
  • java
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