Assertj: 如何通过对象内容比较两个对象列表?

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英文:

Assertj: How to compare 2 objects list by objects content?

问题

以下是翻译好的部分:

给定以下(快速且不完整)代码:

class Pair{
    int x;
    int y;
}

List l1 = Arrays.asList(new Match(1,2), new Match(1,3), new Match(2,3));
List l2 = Arrays.asList(new Match(1,2), new Match(1,3), new Match(2,3));

我该如何比较这些列表的内容?
到目前为止,我所使用的所有方法都是检查对象本身是否相等,而不是对象的值:

assertThat(l1).isEqualTo(l2);
assertThat(l1).containsAll(l2);
assertThat(l1).containsExactly(values);
assertThat(l1).containsExactlyElementsOf(iterable);

我是否需要为 Match 类实现 equals() 方法?

这可能是正确的方法吗?

for (int i = 0; i < l1.size(); i++){
    assertThat(l1.get(i)).usingRecursiveComparison().isEqualTo(l2.get(i));
}
英文:

Given the following (quick and missing) code:

class Pair{
int x;
int y;
}

List l1 = Arrays.asList(new Match(1,2), new Match(1,3), new Match(2,3));
List l2 = Arrays.asList(new Match(1,2), new Match(1,3), new Match(2,3));

How can I compare the content of the lists?
Everything I used so far checked if the objects themselves were equal and not the objects value:

assertThat(l1).isEqualTo(l2);
assertThat(l1).containsAll(l2);
assertThat(l1).containsExactly(values);
assertThat(l1).containsExactlyElementsOf(iterable);

Must I implement equals() method for Match class?

May this be the correct way?

for (int i = 0; i &lt; l1.size(); i++){
    assertThat(l1.get(i)).usingRecursiveComparison().isEqualTol2.get(i));
}

答案1

得分: 14

尝试使用 usingRecursiveFieldByFieldElementComparator(recursiveConfiguration),它可以对所有可迭代的断言进行递归比较。

例如:

public class Person {
  String name;
  boolean hasPhd;
}

public class Doctor {
  String name;
  boolean hasPhd;
}

Doctor drSheldon = new Doctor("Sheldon Cooper", true);
Doctor drLeonard = new Doctor("Leonard Hofstadter", true);
Doctor drRaj = new Doctor("Raj Koothrappali", true);

Person sheldon = new Person("Sheldon Cooper", false);
Person leonard = new Person("Leonard Hofstadter", false);
Person raj = new Person("Raj Koothrappali", false);
Person howard = new Person("Howard Wolowitz", false);

List<Doctor> doctors = list(drSheldon, drLeonard, drRaj);
List<Person> people = list(sheldon, leonard, raj);

RecursiveComparisonConfiguration configuration = RecursiveComparisonConfiguration.builder()
                                                                                 .withIgnoredFields("hasPhd")
                                                                                 .build();

// 断言成功,因为两个列表按顺序包含相等的项目。
assertThat(doctors).usingRecursiveFieldByFieldElementComparator(configuration)
                   .contains(sheldon);

有关更详细的解释,请参阅 https://assertj.github.io/doc/#assertj-core-recursive-comparison-for-iterable

英文:

Give a try to usingRecursiveFieldByFieldElementComparator(recursiveConfiguration), it enables recursive comparison to all iterable assertions.

Ex:

public class Person {
  String name;
  boolean hasPhd;
}

public class Doctor {
  String name;
  boolean hasPhd;
}

Doctor drSheldon = new Doctor(&quot;Sheldon Cooper&quot;, true);
Doctor drLeonard = new Doctor(&quot;Leonard Hofstadter&quot;, true);
Doctor drRaj = new Doctor(&quot;Raj Koothrappali&quot;, true);

Person sheldon = new Person(&quot;Sheldon Cooper&quot;, false);
Person leonard = new Person(&quot;Leonard Hofstadter&quot;, false);
Person raj = new Person(&quot;Raj Koothrappali&quot;, false);
Person howard = new Person(&quot;Howard Wolowitz&quot;, false);

List&lt;Doctor&gt; doctors = list(drSheldon, drLeonard, drRaj);
List&lt;Person&gt; people = list(sheldon, leonard, raj);

RecursiveComparisonConfiguration configuration = RecursiveComparisonConfiguration.builder()
                                                                                 .withIgnoredFields(&quot;hasPhd&quot;)
                                                                                 .build();

// assertion succeeds as both lists contains equivalent items in order.
assertThat(doctors).usingRecursiveFieldByFieldElementComparator(configuration)
                   .contains(sheldon);

See https://assertj.github.io/doc/#assertj-core-recursive-comparison-for-iterable for a more detailed explanation.

答案2

得分: 6

你应该重写 equals()hashCode() 方法。

英文:

You should override equals() and hashCode()

答案3

得分: 2

是的,因此经过进一步的研究,我建议:

for (int i = 0; i < l1.size(); i++){
    assertThat(l1.get(i)).usingRecursiveComparison().isEqualTo(l2.get(i));
}

你可以阅读详细信息:

https://assertj.github.io/doc/#assertj-core-recursive-comparison

英文:

Yes, so after further researching I would recommend:

for (int i = 0; i &lt; l1.size(); i++){
    assertThat(l1.get(i)).usingRecursiveComparison().isEqualTol2.get(i));
}

You can read the details:

https://assertj.github.io/doc/#assertj-core-recursive-comparison

答案4

得分: 1

使用<a href="https://joel-costigliola.github.io/assertj/index.html">AssertJ</a>:

assertThat(actualModel)
    .usingRecursiveComparison()
    ...各种其他选项()
    .isEqualTo(expectedModel);
英文:

Using <a href="https://joel-costigliola.github.io/assertj/index.html">AssertJ</a>:

assertThat(actualModel)
                    .usingRecursiveComparison()
                    ...variousOtherOptions()
                    .isEqualTo(expectedModel);

答案5

得分: 0

@vincentdep 是正确的。如果你正在使用 Java 14 或更高版本,你可以使用 record 类:

public record Pair(int x, int y){};

List l1 = Arrays.asList(new Pair(1,2), new Pair(1,3), new Pair(2,3));
List l2 = Arrays.asList(new Pair(1,2), new Pair(1,3), new Pair(2,3));

assertThat(l1).isEqualTo(l2);
assertThat(l1).containsAll(l2);
英文:

@vincentdep is correct. If you are using Java 14 or above, you can use a record class:

public record Pair(int x, int y){};

List l1 = Arrays.asList(new Pair(1,2), new Pair(1,3), new Pair(2,3));
List l2 = Arrays.asList(new Pair(1,2), new Pair(1,3), new Pair(2,3));

assertThat(l1).isEqualTo(l2);
assertThat(l1).containsAll(l2);

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  • 本文由 发表于 2020年10月24日 05:10:51
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