英文:
Scanner returning unwanted information when trying to use int = input.nextInt in leap year class
问题
import java.util.Scanner;
public class LeapYearCheck{
public static void main(String args[]){
System.out.print("Please enter a leap year:");
Scanner input = new Scanner(System.in);
int year = input.nextInt();
if (year<=1582){
System.out.println("An input of 1582 or less is not valid."); // 1582年或之前的输入无效。
}
else if (year%400==0){
System.out.println(year + " is a leap year."); // 是闰年。
return;
}
else if (year%4==0 && year%100!=0){
System.out.println(year + " is a leap year."); // 是闰年。
return;
}
else{
System.out.println(year + " is not a leap year."); // 不是闰年。
}
}
}
英文:
I'm trying to write a program to check if a year entered by the user is a leap year. I thought what I had below was fine (though I do wish it would return to System.out.print("Please enter a leap year:"); when a year <= 1582 is entered, I'm not sure how to do that), but when I enter a number higher than 1582 I get the following:
run:
Please enter a leap year:1600
java.util.Scanner[delimiters=\p{javaWhitespace}+][position=4][match valid=true][need input=false][source closed=false][skipped=false][group separator=\,][decimal separator=\.][positive prefix=][negative prefix=\Q-\E][positive suffix=][negative suffix=][NaN string=\Q�\E][infinity string=\Q∞\E] is a leap year.
BUILD SUCCESSFUL (total time: 1 second)
I don't understand why it's printing all of this out, I only want the number that the user entered. I'm new to programming so there is nothing readily obvious about this to me. Thanks, and here's my code:
import java.util.Scanner;
public class LeapYearCheck{
public static void main(String args[]){
System.out.print("Please enter a leap year:");
Scanner input = new Scanner(System.in);
int year = input.nextInt();
if (year<=1582){
System.out.println("An input of 1582 or less is not valid.");
}
else if (year%400==0){
System.out.println(input + " is a leap year.");
return;
}
else if (year%4==0 && year%100!=0){
System.out.println(input + " is a leap year.");
return;
}
else{
System.out.println(input + " is not a leap year.");
}
}
}
答案1
得分: 1
System.out.println(year + "在这里添加任何额外的字符串"); 你的问题在于你试图通过打印 input 来打印扫描器本身。input 不是保存用户输入的变量，你定义了 year 来保存那个信息。
英文:
System.out.println(year+"any extra string here"); your problem is that you are trying to print the scanner itself by printing input. Input is not the variable that holds the user input, you defined year to hold that information
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