问题

我正在尝试弄清楚如何将补充方法的输出放入一个数组中，以便我可以显示结果。以下是我的一些代码：

public class BasicBioinformatics {

    public static char[] complement(char[] dna) {
        char[] result = new char[dna.length];
        for (int i = 0; i < dna.length; i++) {
            if (dna[i] == 'A') {
                result[i] = 'T';
            } else if (dna[i] == 'T') {
                result[i] = 'A';
            } else if (dna[i] == 'G') {
                result[i] = 'C';
            } else if (dna[i] == 'C') {
                result[i] = 'G';
            } else {
                return null;
            }
        }
        return result;
    }

    public static void main(String[] args) {
        String testData1 = "GCCTGTCGTAGCTTATC", testData2 = "GGCTGACGTAGCGTAAC";
        char[] result1 = complement(testData1.toCharArray());
        char[] result2 = complement(testData2.toCharArray());
        
        System.out.printf("%s <-- complement --> %s%n", testData1, new String(result1));
        System.out.printf("%s <-- complement --> %s%n", testData2, new String(result2));
    }
}

public class BasicBioinformatics {


public static char[] complement(char dna) {
	for(char d: dna())
		if(d == 'A') {
			d = 'T';
		}
		else if(d == 'T') {
		d = 'A';
	}
		else if(d == 'G') {
		d = 'C';
	}
		else if(d == 'C') {
		d = 'G';
	
		}
		else {
			return null; }
	}
	 
public static void main(String[] args) {
	String testData1 = "GCCTGTCGTAGCTTATC", testData2 = "GGCTGACGTAGCGTAAC";
	System.out.printf("%s <-- complement --> %s%n", testData1, complement(testData1));
	
}

答案1

得分: 1

你有一个名为 function complement(char dna) 的函数，但你试图输入一个 String。你可以改为使用以下代码：

System.out.printf("%s <-- 补码 --> %s%n", testData1, (complement(testData1.toCharArray())));