英文:
Java how to compare string, String compare problem
问题
我在Java中进行字符串比较时遇到了问题。我有两个几乎相似的字符串，但它们并不相等，因为一个包含了- (44)字符，另一个包含了- (8211)字符。有人可以帮我处理一下这种情况，使得这两个字符串相等吗？我在代码中尝试了以下内容，但没有成功：
cellValue.replaceAll("\u0045", "\u8211");
byte[] bytes = cellValue.getBytes(Charset.defaultCharset());
String cellValueUtf8 = new String(bytes, Charset.defaultCharset());
英文:
I have problem with string comparison in Java. I have 2 nearly similar strings, but they are not equal, because one contains - (44) char and another contains - (8211) char. Can someone help me with case, that this strings are equals. I tried this in code, but it doesn't work:
cellValue.replaceAll("\u0045", "\u8211");
byte[] bytes = cellValue.getBytes(Charset.defaultCharset());
String cellValueUtf8 = new String(bytes, Charset.defaultCharset());
答案1
得分: 0
String是常量；它们的值在创建后不能被更改。因此，String#replaceAll会返回一个新的String，即这个操作不会改变cellValue。此外，请注意，String#replaceAll的第一个参数是一个正则表达式。
您需要使用 String#replace，它会将给定字符串中所有出现的oldChar替换为newChar，而不是使用String#replaceAll。
将
cellValue.replaceAll("\u0045", "\u8211");
替换为
cellValue = cellValue.replace('\u0045', '\u8211');
以便将更改后的值赋给cellValue。
英文:
Strings are constant; their values cannot be changed after they are created. Thus, String#replaceAll returns a new String i.e. this operation doesn't change cellValue. Also, note that String#replaceAll takes a regex as the first parameter.
You need String#replace, which replaces all occurrences of oldChar in the given string with newChar, instead of String#replaceAll.
Replace
cellValue.replaceAll("\u0045", "\u8211");
with
cellValue = cellValue.replace('\u0045', '\u8211');
in order for the changed value to be assigned to cellValue.
答案2
得分: -1
我写了这个方法，它按照我预期的方式工作：
public static String normalizeDashChar(String toNormalize) {
char[] bytes = toNormalize.toCharArray();
for(int i = 0; i < bytes.length; i++) {
if(bytes[i] == (char)45) {
bytes[i] = (char)8211;
}
}
return new String(bytes);
}
英文:
I wrote this method, and it works as I expect:
public static String normalizeDashChar(String toNormalize) {
char[] bytes = toNormalize.toCharArray();
for(int i = 0; i < bytes.length; i++) {
if(bytes[i] == (char)45) {
bytes[i] = (char)8211;
}
}
return new String(bytes);
}
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