英文:
How to find words that are different between two Strings?
问题
我希望你一切安好。
我正在寻找一种简单的方法来比较两个字符串，并打印出两者之间不同的单词，例如我有：
String one = edittext1.getText().toString();
String two = editText2.getText().toString();
然后输出应该是，存在于 edittext1 中但不存在于 edittext2 中的单词。
英文:
I hope you are fine.
I am searching for a simple way to compare two Strings and print out the words which are unique between the two, for example I have :
String one = edittext1.getText().toString();
String two = editText2.getText().toString();
Then the output should be what is the words that exists in edittext1 and not exist in edittext2.
答案1
得分: -1
如果只是单词，您可以将字符串拆分为string[]，每个单元格将只包含一个单词，然后比较这些单词。操作如下：
String one = "this is first text example";
String two = "this is next text example";
String[] oneVals = one.split(" ");
String[] twoVals = two.split(" ");
int i = oneVals.length;
if (oneVals.length != twoVals.length) {
// 确定要执行什么操作
}
String wordsNotMatching = "";
for (int j = 0; j < i; j++) {
if ((!oneVals[j].equals(twoVals[j])))
wordsNotMatching += oneVals[j] + " ";
}
// wordNotMatching 将包含所有不同的单词。
英文:
if it's only words you can split the strings to string[] that each cell will contain 1 word only and then compare those words. Goes as follows:
String one = "this is first text example";
String two = "this is next text example";
String[] oneVals = one.split("\\ ");
String[] twoVals = two.split("\\ ");
int i = oneVals.length;
if(oneVals.length != twoVals.length)
{
// determine what to do
}
String wordsNotMatching = "";
for(int j=0; j<i; j++)
{
if((!oneVals[j].equals(twoVals[j])))
wordsNotMatching += oneVals[j] + " ";
}
// wordNotMatching will contain all different words.
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论