Finding the lowest and largest number in a nested loop

    int smallest = 0;
    int largest = 0;
    int num;
    for (int row=1; row<=5; row++)
    {
        System.out.println();
        System.out.println("Grades for student #" + row);
        
        num = (int)(Math.random()*50)+50;
        double total = 0;
        smallest = num;
        for (int col = 0; col<10; col++)
        {
            num = (int)(Math.random()*50)+50;
            System.out.print(num+ ", ");
            total += num*1.0;
        }
         
         System.out.println();
         double average = total/10;
          System.out.println("Average for student is " + 
         average);  
        if (num > largest) {
            largest = num;
        }
        if (num < smallest) {
            smallest = num;
        }
    }
  System.out.println("The largest score is:" + largest);
  System.out.println("The smallest score is : " + 
  smallest);

Trying to figure print out the lowest and largest score for random numbers generated in a loop for 5 students. The code is printing out the wrong number for lowest score.

The smallest and largest number are initialized with 0. They should be initialized with the first value instead.

You should put this part inside the nested loop.

    if (num > largest) {
        largest = num;
    }
    if (num < smallest) {
        smallest = num;
    }

Otherwise they are only comparing num of the last column of each row.

below is a code snippet of finding the largest and smallest value from a loop.you may adjust it with your requirement.

int minMax = 0;
int smallest = 0;
int largest = 0;

for(int i = 1; i <= totalNumbers; i++){
    System.out.print("Number " + i + ": ");
    int inputNumbers = console.nextInt();
    if(inputNumbers > largest){
        largest = inputNumbers;
    } else if (inputNumbers < smallest){
        smallest = inputNumbers;
   }
}
System.out.println();

System.out.println("Smallest = " + smallest);
System.out.println("Largest = " + largest);