英文:
Java - Escape double quotes only if not already escaped
问题
给定一个字符串作为输入，我想转义所有那些本应该被转义但实际上没有被转义的双引号。例如，对于给定的输入：
"<?xmlversion=\"1.0"encoding="UTF-8\"?>"，
输出应为："<?xmlversion=\"1.0\"encoding=\"UTF-8\"?>"。
我考虑使用正则表达式，但不太确定如何操作。如果有人能帮忙，我将不胜感激。
英文:
Given a String as input, I want to escape all those double quotes that should have escaped but they did not. For instance, given "<?xmlversion=\"1.0"encoding="UTF-8\"?>" as input, the output should be "<?xmlversion=\"1.0\"encoding=\"UTF-8\"?>". I was thinking of using Regex but was not fully sure how. I would appreciate if someone could help with that.
答案1
得分: 0
你可以在这里使用正则表达式替换：
<!-- 语言：java -->
String xml = "<?xmlversion=\\\"1.0\"encoding=\"UTF-8\\\"?>";
System.out.println(xml);
xml = xml.replaceAll("(?<!\\\\)\"", "\\\\\"");
System.out.println(xml);
这将输出：
<!-- 语言：xml -->
<?xmlversion=\"1.0"encoding="UTF-8\"?>
<?xmlversion=\"1.0\"encoding=\"UTF-8\"?>
这里使用的正则表达式模式是：
(?<!\\)"
这将匹配所有不在反斜杠前面的双引号，并将它们替换为\"。请注意，在Java的正则表达式语言中，我们必须对反斜杠进行双重转义。此外，文字双引号在Java字符串中变为\"。
英文:
You could using a regex replacement here:
<!-- language: java -->
String xml = "<?xmlversion=\\\"1.0\"encoding=\"UTF-8\\\"?>";
System.out.println(xml);
xml = xml.replaceAll("(?<!\\\\)\"", "\\\\\"");
System.out.println(xml);
This prints:
<!-- language: xml -->
<?xmlversion=\"1.0"encoding="UTF-8\"?>
<?xmlversion=\"1.0\"encoding=\"UTF-8\"?>
The regex pattern used here is:
(?<!\\)"
This will target all double quotations which are not preceded by a backslash, and replace them with \". Note that we have to double escape the backslashes within Java's regex language. Also literal double quote becomes \" in a Java string.
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