Java:Gson:fromJson:获取元素值

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英文:

Java: Gson: fromJson: Get element value

问题

以下是翻译好的内容:

我有一个 JSON 字符串

    string jsonString = "{
        \"Header\":{
            \"ID\": \"103\",
            \"DateTime\": \"2020-07-29 09:14:23.802-4:00 1\",
            \"PlazaID\": \"01\",
            \"Lane\": \"Lane 20\",
            \"IPAddr\": \"192.9.0.123\"
        },
        \"Body\": {
            \"EventMsg\": \"Status: Online\",
            \"EventNum\": \"99999\"
        }
    }";

我正试图使用 Gson 从上述 JSON 中获取 ID 的值但是它给了我一个 NullPointerException我的代码

    JsonObject jsonObject = new Gson().fromJson(jsonString, JsonObject.class );                                      
    //System.out.println("jsonObject: " + jsonObject.toString());
    String _ID = jsonObject.get("ID").getAsString();
我不确定我的代码哪里出错了非常感谢帮助

编辑
根据 @Arvind 的建议我尝试了他的代码但是我得到了这个错误

[![查看图片描述][1]][1]

根据 @Arvind 的建议这段代码有效

    String _ID = jsonObject.get("Header").getAsJsonObject().get("ID").getAsString();
英文:

I have a json string as:

string jsonString = "{"Header":{"ID": "103","DateTime": "2020-07-29 09:14:23.802-4:00 1","PlazaID": "01","Lane": "Lane 20","IPAddr": "192.9.0.123"},"Body": {"EventMsg": "Status: Online","EventNum": "99999"}}";

I am trying to get the value if ID from the above json by using Gson and it gives me NullPointerException. My code:

JsonObject jsonObject = new Gson().fromJson(jsonString, JsonObject.class );                                        
//System.out.println("jsonObject: " + jsonObject.toString());
String _ID = jsonObject.get("ID").getAsString();

I am not sure where the error in my code is. Any help is appreciated.

Edit:
As per @Arvind's suggestion, I tried his code and am getting this error:

Java:Gson:fromJson:获取元素值

As per @Arvind's suggestion, this works:

String _ID = jsonObject.get("Header").getAsJsonObject().get("ID").getAsString();

答案1

得分: 1

让我们首先美化你的 jsonString 以便更清晰地看到:

{
  "Header": {
    "ID": "103",
    "DateTime": "2020-07-29 09:14:23.802-4:00 1",
    "PlazaID": "01",
    "Lane": "Lane 20",
    "IPAddr": "192.9.0.123"
  },
  "Body": {
    "EventMsg": "Status: Online",
    "EventNum": "99999"
  }
}

注意 "ID" 位于 "Header" 内部,因此您需要以这种方式解析:

String _ID = jsonObject.getJsonObject("Header").get("ID").getAsString();

此外,避免使用 get(),因为有更好的便利方法:

String _ID = jsonObject.getJsonObject("Header").getString("ID");
英文:

Let's prettify your jsonString first for clarity:

{
  "Header": {
    "ID": "103",
    "DateTime": "2020-07-29 09:14:23.802-4:00 1",
    "PlazaID": "01",
    "Lane": "Lane 20",
    "IPAddr": "192.9.0.123"
  },
  "Body": {
    "EventMsg": "Status: Online",
    "EventNum": "99999"
  }
}

Notice that "ID" is inside "Header", so you'd have to parse it this way:

String _ID = jsonObject.getJsonObject("Header").get("ID").getAsString();

Also, avoid using get() since there are better convenience methods:

String _ID = jsonObject.getJsonObject("Header").getString("ID");

huangapple
  • 本文由 发表于 2020年10月20日 01:41:04
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