英文:
Conditional Operator in Java where I don't want the false Boolean to do anything
问题
我是一个极其初学的编程学生，正在学习Java编程。
在一个作业的一部分中，我有一个 for 循环，在一个字符串中查找特定的字符，如果找到了那个字符，它需要更新我稍后代码部分需要用到的计数器。根据这个作业的要求，我们只能使用 条件（三元）运算符。我已经能够使用 if 语句完成代码，但是正如我所说的，我需要使用条件运算符。
有没有办法让条件运算符的假语句什么都不做？或者我应该让它更新一些无关紧要的垃圾变量？
这个代码有效：
if (someString.charAt(i) == someChar) {
someInt++;
}
但是我尝试让下面的代码工作：
someString.charAt(i) == someChar ? someInt++ : （在这里填写什么）;
英文:
I am a extremely beginner programming student working with Java.
For a section of an assignment I have a for loop that looks for a specific character in a string, and if it finds that character, it needs to update my count for a later section of the code. For this particular assignment, we are required to only use the conditional (ternary) operator. I have been able to complete the code using an if statement, but like I said, I need to use a conditional operator.
Is there a way for the false statement from a conditional operator to do nothing? Or should I have it update some garbage variable that doesn't matter instead?
This works
if (someString.charAt(i) == someChar) {
someInt++;
}
But trying to get this working
someString.charAt(i) == someChar ? someInt++ : (this right here);
答案1
得分: 0
也许类似这样的代码可以帮助？
public int answer(String input, char match) {
int counter = 0;
for (final char character : input.toCharArray()) {
counter += character == match ? 1 : 0;
}
return counter;
}
英文:
Maybe something like this can help?
public int answer(String input, char match) {
int counter = 0;
for (final char character : input.toCharArray()) {
counter += character == match ? 1 : 0;
}
return counter;
}
答案2
得分: 0
public static int count(String str, char ch) {
return str.isEmpty() ? 0 : (str.charAt(0) == ch ? 1 : 0) + count(str.substring(1), ch);
}
英文:
public static int count(String str, char ch) {
return str.isEmpty() ? 0 : (str.charAt(0) == ch ? 1 : 0) + count(str.substring(1), ch);
}
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