英文:
Do-while doesn't loop back
问题
以下是翻译好的代码部分：
System.out.println("此程序将二进制值转换为其十进制对应值。\n");Scanner input = new Scanner(System.in);boolean invalidInput = true;do {try {System.out.print("（>）请输入要转换的值：");String numberToConvert = input.nextLine();long converted = Long.parseLong(numberToConvert, 2);System.out.println("（>）" + numberToConvert + " 的十进制值为：" + converted + "\n");invalidInput = false;} catch (Exception e) {System.out.println("（！）输入的值不是二进制，请重试。\n");input.next();}} while (invalidInput);
英文:
So I'm working on a that involves binary conversion etc. But my problem here is that I can't seem to make the do-while statement in my code to loopback whenever the catch block finishes executing. Here's my code.
System.out.println("This program converts a binary value to its decimal counterpart.\n");Scanner input = new Scanner(System.in);boolean invalidInput = true;do {try {System.out.print("(>) Enter the value to be converted: ");String numberToConvert = input.nextLine();long converted = Long.parseLong(numberToConvert, 2);System.out.println("(>) Decimal value of " + numberToConvert + " is : " + converted + "\n");invalidInput = false;} catch (Exception e) {System.out.println("(!) Entered value is non binary, please try again.\n");input.next();}} while (invalidInput);
答案1
得分: 1
System.out.println("此程序将二进制值转换为其十进制对应值。\n");Scanner input = new Scanner(System.in);boolean invalidInput = true;do {try {System.out.print("（>）请输入要转换的值：");String numberToConvert = input.nextLine();long converted = Long.parseLong(numberToConvert, 2);System.out.println("（>）" + numberToConvert + " 的十进制值为：" + converted + "\n");invalidInput = false;} catch (Exception e) {System.out.println("（！）输入的值非二进制，请重试。\n");}} while (invalidInput);
英文:
Remove input.next() from catch block and then try :-
System.out.println("This program converts a binary value to its decimal counterpart.\n");Scanner input = new Scanner(System.in);boolean invalidInput = true;do {try {System.out.print("(>) Enter the value to be converted: ");String numberToConvert = input.nextLine();long converted = Long.parseLong(numberToConvert, 2);System.out.println("(>) Decimal value of " + numberToConvert + " is : " + converted + "\n");invalidInput = false;} catch (Exception e) {System.out.println("(!) Entered value is non binary, please try again.\n");}} while (invalidInput);
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