如果一个字符串以Java数组中的任何一个值结尾

huangapple go评论73阅读模式
英文:

If a string ends with any value of an array Java

问题

I have an array<br>

    String[] Array = {"+", "-", "*", "/"}

and an EditText string<br>

    operation = (EditText) findViewById(R.id.operation);
So, I have a button where I want to add an if statement like: <br>

        Button.setOnLongClickListener(new View.OnLongClickListener() {
                    @Override
                    public boolean onLongClick(View v) {
                        if(operation.getText().toString().endsWith(Array.toString())){
                            prinln("Example"); }
                    }
                });

I don't know how to make this right. How to write the if statements where the String ends with any value of array and make it work
英文:

I have an array<br>

String[] Array = {&quot;+&quot;, &quot;-&quot;, &quot;*&quot;, &quot;/&quot;}

and an EditText string<br>

operation = (EditText) findViewById(R.id.operation);

So, I have a button where I want to add an if statement like: <br>

    Button.setOnLongClickListener(new View.OnLongClickListener() {
                @Override
                public boolean onLongClick(View v) {
                    if(operation.getText().toString().endsWith(Array.toString())){
                        prinln(&quot;Example&quot;); }
                }
            });

I don't know how to make this right. How to write the if statements where the String ends with any value of array and make it work

答案1

得分: 1

你需要遍历你的数组,这将取出数组中的每个字符串,并检查你的字符串是否以数组中的字符串"s"结尾。

for (String s: Array) {
    // 在这里处理你的操作
    if (yourString.endsWith(s)) {
        println(example);
    }
}
英文:

You need to loop through your array, this will take each of the string in the array and check if your String ends with the String 's' from the array

for (String s: Array) {
        //Do your stuff here
        if(yourString.endsWith(s)){
            println(example);
        }
    }

答案2

得分: 1

如果您真的不想使用循环您可以将数组的值保存为键将您想要的答案保存为值存储在一个映射中
然后直接使用这个映射

HashMap<char, String> operandMap = new HashMap<char, String>();
operandMap.put('+', "加法");
operandMap.put('-', "减法");
operandMap.put('*', "乘法");
operandMap.put('/', "除法");
operandMap.put('%', "取余");
println(operandMap.get(operation.getText().toString().charAt(operation.getText().toString().length - 1)));
英文:

If you really don't want to use a loop, you can save array values as keys and your desired answers as values in a map.
And then use the map directly.

HashMap&lt;char, String&gt;operandMap = new HashMap&lt;char,String&gt;(); 
operandMap.put(&#39;+&#39;,&quot;Addition&quot;);
operandMap.put(&#39;-&#39;,&quot;Subtraction&quot;);
operandMap.put(&#39;*&#39;,&quot;Multiplication&quot;);
operandMap.put(&#39;/&#39;,&quot;Division&quot;);
operandMap.put(&#39;%&#39;,&quot;Modulus&quot;);
println(operandMap.get(operation.getText().toString().charAt(operation.getText().toString().length-1)));

huangapple
  • 本文由 发表于 2020年10月18日 06:59:25
  • 转载请务必保留本文链接:https://go.coder-hub.com/64408153.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定