英文:
How to create JSON dynamically in java?
问题
以下是翻译好的内容：
我有一个CustomerEntity，其中包含getter和setter。示例customerEntity如下所示：
customerEntity =
{
"customerNumber": "1234",
"firstName": "Test",
"email": "test@gmail.com",
"id": "1",
"middleName": "doe",
"phone": "11111"
}
我有一个具有getter和setter的JsonProperty的Java类Attributes，如下所示：
Attributes =
{
"name": "string",
"value": "string"
}
我有一个列表，其中将包含来自CustomerEntity的随机元素，例如：
List<String> stringlist = { "firstName", "phone" }
我已经创建了一个Attributes类型的列表：
List<Attributes> Attributeslist = new ArrayList<>();
我想要创建包含stringlist中所有元素的Attributelist，例如在这里它将是：
```java
Attributeslist = [
{
"name": "firstName",
"value": "Test"
},
{
"name": "phone",
"value": "11111"
}
]
为此，我编写了以下代码，但是在previewattributes.setValue();中传递什么？因为该值将取决于下面for循环中的mystring。在这个示例中，它将是previewattributes.setValue(customerEntity.getFirstName());和previewattributes.setValue(customerEntity.getPhone());，但我该如何编写代码呢？
for (String mystring : stringlist) {
Attributes previewattributes;
previewattributes = new Attributes();
previewattributes.setName(mystring);
previewattributes.setValue(value在这里将是customerentity的值);
Attributeslist.add(previewattributes);
}
CustomerEntity:
@Entity
@Table(name = "Customer_tbl")
public class CustomerEntity implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@Column(name = "id")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long rowId;
@Column(name = "customer_number")
private String customerNumber;
public String getCustomerNumber() {
return customerNumber;
}
public void setCustomerNumber(String customerNumber) {
this.customerNumber = customerNumber;
}
}
<details>
<summary>英文:</summary>
I have a CustomerEntiy with getter and setter the sample customerEntity is
customerEntity =
{
"customerNumber": "1234",
"firstName": "Test",
"email": "test@gmail.com",
"id": "1",
"middleName": "doe",
"phone": "11111"
}
I have java class Attributes of JsonProperty with getter and Setters as below
Attributes =
{
"name": "string"
"value": "string"
}
I have a list which will contains random elements from CustomerEntiy for example:
```List<String> stringlist = { "firstName" , "phone"}```
I have created an List of type Attributes
```List<Attributes> Attributeslist = new ArrayList<>();```
I want to create Attributelist of all the elements in stringlist for Example here it would be:
Attributeslist =[
{
"name": "firstName"
"value": "Test"
},
{
"name": "phone"
"value": "11111"
}
]
For this i have written the code as below but what to pass in ```previewattributes.setValue();``` because that value would depends on what is ```mystring``` in below for loop. In this example it would be ```previewattributes.setValue(customerEntity.getFirstName());``` and ```previewattributes.setValue(customerEntity.getPhone());``` for different iteration but how do i code it??
for (String mystring : stringlist) {
Attributes previewattributes;
previewattributes = new Attributes();
previewattributes.setName(mystring);
previewattributes.setValue(value here would be of customerentity);
Attributeslist.add(previewattributes);
}
CustomerEntity:
@Entity
@Table(name = "Customer_tbl")
public class CustomerEntity implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@Column(name = "id")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long rowId;
@Column(name = "customer_number")
private String customerNumber;
public String getCustomerNumber() {
return customerNumber;
}
public void setCustomerNumber(String customerNumber) {
this.customerNumber = customerNumber;
}
}
</details>
# 答案1
**得分**: 1
**你可以在Java中使用反射。还有更简单的方法是将customerEntity存储在HashMap中，并从中提取。**
```java
HashMap<String, String> m = new HashMap<>();
m.put("customerNumber", customerEntity.getCustomerNumber());
m.put("firstName", customerEntity.getFirstName());
m.put("email", customerEntity.getEmail());
m.put("id", customerEntity.getId());
m.put("middleName", customerEntity.getMiddleName());
m.put("phone", customerEntity.getPhone());
在循环内部：
previewattributes.setValue(m.get(attribute));
英文:
You can make use reflection in Java.
Even more simple way is to store the customerEntity in HashMap and fetch from it.
HashMap<String,String> m=new HashMap<>();
m.put("customerNumber", customerEntity.getCustomerNumber());
m.put("firstName", customerEntity.getFirstName());
m.put("email", customerEntity.getEmail());
m.put("id", customerEntity.getId());
m.put("middleName", customerEntity.getMiddleName());
m.put("phone", customerEntity.getPhone());
And inside for loop:
previewattributes.setValue(m.get(attribute));
答案2
得分: 1
这是你要求的代码部分的翻译结果：
如果我理解你的意思正确，你有一个Customer Json数组，你想要分离一些属性，检查下面的代码
public static void main(String[] args) {
String jsonArray = "[\r\n" +
" {\r\n" +
" \"customerNumber\":\"1234\",\r\n" +
" \"firstName\":\"Test\",\r\n" +
" \"email\":\"test@gmail.com\",\r\n" +
" \"id\":\"1\",\r\n" +
" \"middleName\":\"doe\",\r\n" +
" \"phone\":\"11111\"\r\n" +
" },\r\n" +
" {\r\n" +
" \"customerNumber\":\"1235\",\r\n" +
" \"firstName\":\"Test2\",\r\n" +
" \"email\":\"test2@gmail.com\",\r\n" +
" \"id\":\"2\",\r\n" +
" \"middleName\":\"doe2\",\r\n" +
" \"phone\":\"2222\"\r\n" +
" }\r\n" +
"]";
List<String> requiredKeys = Arrays.asList("firstName", "phone");
JSONArray array = new JSONArray(jsonArray);
Iterator iterator = array.iterator();
JSONArray outputArray = new JSONArray();
while(iterator.hasNext()) {
JSONObject jsonObject = (JSONObject)iterator.next();
Iterator<String> keys = jsonObject.keys();
while(keys.hasNext()) {
String key = keys.next();
if(requiredKeys.contains(key)) {
JSONObject attribute = new JSONObject();
attribute.put("name", key);
attribute.put("value", jsonObject.get(key));
outputArray.put(attribute);
}
}
}
System.out.println(outputArray);
}
输出
[
{
"name":"firstName",
"value":"Test"
},
{
"name":"phone",
"value":"11111"
},
{
"name":"firstName",
"value":"Test2"
},
{
"name":"phone",
"value":"2222"
}
]
请注意，翻译结果中的代码部分已经按照原文的格式保留。
英文:
If I understood u correctly u have an Array of Customer Json in which u want some attribute separated , check below code
public static void main(String[] args) {
String jsonArray = "[\r\n" +
" {\r\n" +
" \"customerNumber\":\"1234\",\r\n" +
" \"firstName\":\"Test\",\r\n" +
" \"email\":\"test@gmail.com\",\r\n" +
" \"id\":\"1\",\r\n" +
" \"middleName\":\"doe\",\r\n" +
" \"phone\":\"11111\"\r\n" +
" },\r\n" +
" {\r\n" +
" \"customerNumber\":\"1235\",\r\n" +
" \"firstName\":\"Test2\",\r\n" +
" \"email\":\"test2@gmail.com\",\r\n" +
" \"id\":\"2\",\r\n" +
" \"middleName\":\"doe2\",\r\n" +
" \"phone\":\"2222\"\r\n" +
" }\r\n" +
"]";
List<String> requiredKeys = Arrays.asList("firstName" , "phone");
JSONArray array = new JSONArray(jsonArray);
Iterator iterator = array.iterator();
JSONArray outputArray = new JSONArray();
while(iterator.hasNext()) {
JSONObject jsonObject = (JSONObject)iterator.next();
Iterator<String> keys = jsonObject.keys();
while(keys.hasNext()) {
String key = keys.next();
if(requiredKeys.contains(key)) {
JSONObject attribute = new JSONObject();
attribute.put("name", key);
attribute.put("value", jsonObject.get(key));
outputArray.put(attribute);
}
}
}
System.out.println(outputArray);
}
}
output
[
{
"name":"firstName",
"value":"Test"
},
{
"name":"phone",
"value":"11111"
},
{
"name":"firstName",
"value":"Test2"
},
{
"name":"phone",
"value":"2222"
}
]
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