2D数组随机交换项

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英文:

2D Array item swap randomly

问题

我有一个枚举:

public enum Player
{
   X, O, NOBODY
}

我有一个用随机玩家项填充的数组:

Player [size][size] p;

示例矩阵:

[ X, NOBODY, NOBODY ]
[ NOBODY, O, O ]
[ X, X, NOBODY ]

我想随机将X或O元素与NOBODY元素交换,应该如何实现?

示例:

[ NOBODY, NOBODY, NOBODY ]
[ NOBODY, O, O ]
[ X, X, X ]
英文:

I have an enum:

public enum Player
{
   X, O, NOBODY
}

And I have this array filled with player items randomly:

Player [size][size] p;

Example matrix:

[ X, NOBODY, NOBODY ]
[ NOBODY, O, O ]
[ X, X, NOBODY ] 

I would like to swap an X or O element with a NOBODY element randomly, how can I do that?

Example:

[ NOBODY, NOBODY, NOBODY ]
[ NOBODY, O, O ]
[ X, X, X ] 








</details>


# 答案1
**得分**: 1

一个直接的方法是选择一个随机的X/O单元,以及一个随机的NOBODY单元,然后交换它们的值:

```java
// 类内的方法,包含数组
public void 交换值() {
    Random rand = new Random();
    int xoPos;
    int nobodyPos;

    do {
        xoPos = rand.nextInt(size*size);
        Player p = p[xoPos / size][xoPos % size];
    } while (Player.NOBODY.equals(p));

    do {
        nobodyPos = rand.nextInt(size*size);
        Player p = p[nobodyPos / size][nobodyPos % size];
    } while (!Player.NOBODY.equals(p));

    p[nobodyPos / size][nobodyPos % size] = p[xoPos / size][xoPos % size];
    p[xoPos / size][xoPos % size] = Player.NOBODY;
}

这里的策略是生成一个介于0和二维棋盘单元格总数减一之间的随机数。然后,我们使用整数除法和取模来确定这个单个值对应的二维坐标。

英文:

One straightforward approach would be to select a random X/O cell as well as a random NOBODY cell, and then swap their values:

// method inside class containing the array
public void swapValues() {
    Random rand = new Random();
    int xoPos;
    int nobodyPos;

    do {
        xoPos = rand.nextInt(size*size);
        Player p = p[xoPos / size][xoPos % size];
    } while (Player.NOBODY.equals(p));

    do {
        nobodyPos = rand.nextInt(size*size);
        Player p = p[nobodyPos / size][nobodyPos % size];
    } while (!Player.NOBODY.equals(p));

    p[nobodyPos / size][nobodyPos % size] = p[xoPos / size][xoPos % size];
    p[xoPos / size][xoPos % size] = Player.NOBODY;
}

The strategy here is to generate a single random number between 0 and one minus the total number of cells in the 2D board. Then, we use integer division and modulus to figure out to what 2D coordinates that single value corresponds.

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  • 本文由 发表于 2020年10月16日 12:21:07
  • 转载请务必保留本文链接:https://go.coder-hub.com/64382880.html
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