如何创建一个嵌套的 JSONObject

huangapple
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英文:

How to create a nested JSONObject

问题

以下是我的代码。我仍需要添加“studentInfo”字段。

  1. JSONObject jo = new JSONObject();
  2. jo.put("name", "ALEX JAMES");
  3. jo.put("id", "22284666");
  4. jo.put("age", "13");

要创建的JSON主体消息：

  1. {
  2.     "body": {
  3.         "studentInfo": {
  4.             "name": "ALEX JAMES",
  5.             "id": "22284666",
  6.             "age": "13"
  7.         }
  8.     }
  9. }
英文:

Below is my code. I still need to add the "studentInfo" field.

  1. JSONObject jo = new JSONObject();
  2. jo.put("name", "ALEX JAMES");
  3. jo.put("id", "22284666");
  4. jo.put("age","13")

JSON body message to be created:

  1. {
  2.     "body": {
  3.         "studentInfo": {
  4.             "name": "ALEX JAMES",
  5.             "id": "22284666",
  6.             "age": "13"
  7.         }
  8.     }
  9. }

答案1

得分: 2

可以嵌套对象

  1. JSONObject studentInfo = new JSONObject();
  2. studentInfo.put("name", "ALEX JAMES");
  3. studentInfo.put("id", "22284666");
  4. studentInfo.put("age", "13");
  6. JSONObject body = new JSONObject();
  7. body.put("studentInfo", studentInfo);
  9. JSONObject wrapper = new JSONObject();
  10. wrapper.put("body", body);
英文:

you can nest objects

  1. JSONObject studentInfo = new JSONObject();
  2. studentInfo.put("name", "ALEX JAMES");
  3. studentInfo.put("id", "22284666");
  4. studentInfo.put("age","13");
  6. JSONObject body = new JSONObject();
  7. body.put("studentInfo" , studentInfo);
  9. JSONObject wrapper = new JSONObject();
  10. wrapper.put("body" , body);

答案2

得分: 2

这个独立示例似乎可以实现你想要的功能：

  1. import org.json.JSONObject;
  3. class Main {
  4.   public static void main(String[] args) {
  5.     JSONObject jo = new JSONObject();
  7.     JSONObject body = new JSONObject();
  8.     jo.put("body", body);
  10.     JSONObject si = new JSONObject();
  11.     body.put("studentInfo", si);
  12.     si.put("name", "Alex James");
  13.     si.put("id", "22284666");
  14.     si.put("age", 13);
  16.     System.out.println(jo.toString(4));
  17.   }
  18. }

输出

  1. {"body": {"studentInfo": {
  2.     "name": "Alex James",
  3.     "id": "22284666",
  4.     "age": 13
  5. }}}

在repl.it上测试它。

英文:

This standalone example seems to do what you want:

  1. import org.json.JSONObject;
  3. class Main {
  4.   public static void main(String[] args) {
  5.     JSONObject jo = new JSONObject();
  7.     JSONObject body = new JSONObject();
  8.     jo.put("body", body);
  10.     JSONObject si = new JSONObject();
  11.     body.put("studentInfo", si);
  12.     si.put("name", "Alex James");
  13.     si.put("id", "22284666");
  14.     si.put("age", 13);
  16.     System.out.println(jo.toString(4));
  17.   }
  18. }

Output

  1. {"body": {"studentInfo": {
  2.     "name": "Alex James",
  3.     "id": "22284666",
  4.     "age": 13
  5. }}}

Test it on repl.it.

huangapple
  • 本文由 发表于 2020年10月15日 21:50:20
  • 转载请务必保留本文链接：https://go.coder-hub.com/64373063.html
  • java
  • json
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