算法或代码以打印代理的二叉树。

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英文:

Algorithm or code to print the binary tree of agents

问题

以下是您提供的代码的翻译部分:

我尝试在JADE(Java Agent DEvelopment Framework)中编写代码,以打印SMA中代理的二叉树。我希望使用原始算法按顺序遍历打印树:

  1. 遍历左子树,即调用Inorder(left-subtree)
  2. 访问根节点。
  3. 遍历右子树,即调用Inorder(right-subtree)

我的节点代理是:

class Noeud {
    private Integer value = null;
    private AID gauche = null;
    private AID droit = null;
    private AID pere = null;
}

在我的打印代理中,我使用CyclicBehaviour作为扩展。以下是我的代码:

public class ReceiveAffichageBehaviour extends CyclicBehaviour{     
@Override
public void action() {
    MessValueGauche();
    MessValue();
    MessValueDroit();
}

private void MessValueGauche() {
    MessageTemplate messageTemplate = MessageTemplate.and(
            MessageTemplate.MatchOntology(Constants.AFFICHAGE_VALUE_GAUCHE),
            MessageTemplate.MatchPerformative(ACLMessage.REQUEST)
    );
    ACLMessage receiveMsg = myAgent.receive(messageTemplate);
    if (receiveMsg != null) {
        String contenu = receiveMsg.getContent() + "(";
        ACLMessage message = new ACLMessage(ACLMessage.REQUEST);

        if (noeud.getGauche() == null) {
            message.setOntology(Constants.AFFICHAGE_VALUE);
            message.addReceiver(myAgent.getAID());
        } else {
            message.setOntology(Constants.AFFICHAGE_VALUE_GAUCHE);
            message.addReceiver(noeud.getGauche());
        }

        message.setContent(contenu);
        myAgent.send(message);

    } else {
        block();
    }
}

private void MessValue() {
    MessageTemplate messageTemplate = MessageTemplate.and(
            MessageTemplate.MatchOntology(Constants.AFFICHAGE_VALUE),
            MessageTemplate.MatchPerformative(ACLMessage.REQUEST)
    );
    ACLMessage receiveMsg = myAgent.receive(messageTemplate);
    if (receiveMsg != null) {
        String contenu = receiveMsg.getContent() + (noeud.getValue() == null ? "" : noeud.getValue().toString());
        ACLMessage message = new ACLMessage(ACLMessage.REQUEST);

        if (noeud.getDroit() == null){
            message.setOntology(Constants.AFFICHAGE_VALUE_DROIT);
            message.addReceiver(myAgent.getAID());
        } else if (noeud.getDroit().equals(receiveMsg.getSender())){
            message.setOntology(Constants.AFFICHAGE_VALUE_DROIT);
            message.addReceiver(noeud.getPere());
        } else {
            message.setOntology(Constants.AFFICHAGE_VALUE_GAUCHE);
            message.addReceiver(noeud.getDroit());
        }
        message.setContent(contenu);
        myAgent.send(message);

    } else {
        block();
    }
}

private void MessValueDroit() {
    MessageTemplate messageTemplate = MessageTemplate.and(
            MessageTemplate.MatchOntology(Constants.AFFICHAGE_VALUE_DROIT),
            MessageTemplate.MatchPerformative(ACLMessage.REQUEST)
    );
    ACLMessage receiveMsg = myAgent.receive(messageTemplate);
    if (receiveMsg != null) {
        String contenu = receiveMsg.getContent() + ")";
        ACLMessage message = new ACLMessage(ACLMessage.REQUEST);
        message.setContent(contenu);

        if (noeud.getDroit() == null && noeud.getGauche() == null ){
            if (noeud.getPere().equals(Constants.AID_RACINE)){
                message.setPerformative(ACLMessage.CONFIRM);
            } else {
                message.setOntology(Constants.AFFICHAGE_VALUE_GAUCHE);
            }
            message.addReceiver(noeud.getPere());
        }

        myAgent.send(message);

    } else {
        block();
    }
}

我不知道如何修复代码中的无限循环问题。谁能帮助我提供详细的算法,而不是一般性的算法?或者能否修复我的代码错误?谢谢!

英文:

I try to write code in jade (Java Agent DEvelopment Framework) to print the binary tree of agents in sma. I want to print tree inorder traversal with origin algorithm:

  1. Traverse the left subtree, i.e., call Inorder(left-subtree)
  2. Visit the root.
  3. Traverse the right subtree, i.e., call Inorder(right-subtree)

And my node agent is:

class Noeud {
    private Integer value = null;
    private AID gauche = null;
    private AID droit = null;
    private AID pere = null;
}

In my agent to print, I use CyclicBehaviour as extensions. With my code:

public class ReceiveAffichageBehaviour extends CyclicBehaviour{     
@Override
public void action() {
    MessValueGauche();
    MessValue();
    MessValueDroit();
}

private void MessValueGauche() {
    MessageTemplate messageTemplate = MessageTemplate.and(
            MessageTemplate.MatchOntology(Constants.AFFICHAGE_VALUE_GAUCHE),
            MessageTemplate.MatchPerformative(ACLMessage.REQUEST)
    );
    ACLMessage receiveMsg = myAgent.receive(messageTemplate);
    if (receiveMsg != null) {
        String contenu = receiveMsg.getContent() + "(";
        ACLMessage message = new ACLMessage(ACLMessage.REQUEST);

        if (noeud.getGauche() == null) {
            message.setOntology(Constants.AFFICHAGE_VALUE);
            message.addReceiver(myAgent.getAID());
        } else {
            message.setOntology(Constants.AFFICHAGE_VALUE_GAUCHE);
            message.addReceiver(noeud.getGauche());
        }

        message.setContent(contenu);
        myAgent.send(message);

    } else {
        block();
    }
}

private void MessValue() {
    MessageTemplate messageTemplate = MessageTemplate.and(
            MessageTemplate.MatchOntology(Constants.AFFICHAGE_VALUE),
            MessageTemplate.MatchPerformative(ACLMessage.REQUEST)
    );
    ACLMessage receiveMsg = myAgent.receive(messageTemplate);
    if (receiveMsg != null) {
        String contenu = receiveMsg.getContent() + (noeud.getValue() == null ? "" : noeud.getValue().toString());
        ACLMessage message = new ACLMessage(ACLMessage.REQUEST);

        if (noeud.getDroit() == null){
            message.setOntology(Constants.AFFICHAGE_VALUE_DROIT);
            message.addReceiver(myAgent.getAID());
        } else if (noeud.getDroit().equals(receiveMsg.getSender())){
            message.setOntology(Constants.AFFICHAGE_VALUE_DROIT);
            message.addReceiver(noeud.getPere());
        } else {
            message.setOntology(Constants.AFFICHAGE_VALUE_GAUCHE);
            message.addReceiver(noeud.getDroit());
        }
        message.setContent(contenu);
        myAgent.send(message);

    } else {
        block();
    }
}

private void MessValueDroit() {
    MessageTemplate messageTemplate = MessageTemplate.and(
            MessageTemplate.MatchOntology(Constants.AFFICHAGE_VALUE_DROIT),
            MessageTemplate.MatchPerformative(ACLMessage.REQUEST)
    );
    ACLMessage receiveMsg = myAgent.receive(messageTemplate);
    if (receiveMsg != null) {
        String contenu = receiveMsg.getContent() + ")";
        ACLMessage message = new ACLMessage(ACLMessage.REQUEST);
        message.setContent(contenu);

        if (noeud.getDroit() == null && noeud.getGauche() == null ){
            if (noeud.getPere().equals(Constants.AID_RACINE)){
                message.setPerformative(ACLMessage.CONFIRM);
            } else {
                message.setOntology(Constants.AFFICHAGE_VALUE_GAUCHE);
            }
            message.addReceiver(noeud.getPere());
        }

        myAgent.send(message);

    } else {
        block();
    }
}

I don't know to fix the infini loop in my code. Who can help me the detailed algorithm instead the general? Or could fix my bug in code? Thank you!

答案1

得分: 1

循环行为天生是无限的。如果不希望行为停止,请勿使用循环行为。只需使用SimpleBehaviour,并在希望将其从代理中移除时将finished布尔值设置为true。

英文:

A cyclicBehaviour is infinite by nature. Do not use a cyclic if you want the behaviour to stop.
Just use a simpleBehaviour and set the finished boolean at true when you want to remove it from the agent.

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  • 本文由 发表于 2020年10月14日 06:40:33
  • 转载请务必保留本文链接:https://go.coder-hub.com/64344147.html
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