import re
text = "I live, in India."
pattern = r"(\S+)|(\p{Punct})"
matches = re.finditer(pattern, text)
output = []
offsets = []
for match in matches:
    token = match.group(0)
    output.append(token)
    start = match.start()
    end = match.end()
    offsets.append((start, end))
print(output)
print(offsets)

import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Main {
    public static void main(String[] args) {
        Pattern pattern = Pattern.compile("\\b\\S+\\b|\\p{Punct}");
        Matcher matcher = pattern.matcher("I live, in India.");
        while (matcher.find()) {
            System.out.println(matcher.group() + " => " + matcher.start());
        }
    }
}

I => 0
live => 2
, => 6
in => 8
India => 11
. => 16

<details>
<summary>英文:</summary>
## [`Matcher#start`][1]
    import java.util.regex.Matcher;
    import java.util.regex.Pattern;
    
    public class Main {
    	public static void main(String[] args) {
    		Pattern pattern = Pattern.compile(&quot;\\b\\S+\\b|\\p{Punct}&quot;);
    		Matcher matcher = pattern.matcher(&quot;I live, in India.&quot;);
    		while (matcher.find()) {
    			System.out.println(matcher.group() + &quot; =&gt; &quot; + matcher.start());
    		}
    	}
    }
**Output:**
    I =&gt; 0
    live =&gt; 2
    , =&gt; 6
    in =&gt; 8
    India =&gt; 11
    . =&gt; 16
**Explanation of regex:**
 1. `\b` specifies [word boundary][2].
 2. `|` specifies `OR`.
 3. `\p{Punct}` specifies [punctuation][3].
 4. `\S+` specifies [one or more][4] non-whitespace character.
  [1]: https://docs.oracle.com/javase/7/docs/api/java/util/regex/Matcher.html#start()
  [2]: https://docs.oracle.com/javase/tutorial/essential/regex/bounds.html
  [3]: https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html
  [4]: https://docs.oracle.com/javase/tutorial/essential/regex/quant.html
</details>