英文:
Java string index out of bound , CharAt problem
问题
代码抛出一个错误:"String index out of bound : 1",以下是代码部分:
package inlamningsuppgift2;
import java.util.Random;
import java.util.Scanner;
import java.lang.Math;
public class inlamningsuppgift2del2 {
public static void main(String[] args) {
System.out.println("猜一个01-99之间的数字");
randomNumber();
}
public static void randomNumber() {
Scanner scanner = new Scanner(System.in);
Random random = new Random();
int value = Integer.valueOf(scanner.nextLine());
String str1 = Integer.toString(value);
String sa = String.format("%02d", value);
int randomNum = 10 * random.nextInt(9);
int randomNum2 = 1 * random.nextInt(9) + 1;
int wholeNum = randomNum + randomNum2;
String str2 = Integer.toString(randomNum + randomNum2);
String s = String.format("%02d", randomNum + randomNum2);
System.out.println("你猜的数字是:" + sa);
System.out.println("正确的数字是:" + s);
if (str2.charAt(0) == str1.charAt(0) && str2.charAt(1) == str1.charAt(1)) {
System.out.println("恭喜你,你以正确的顺序猜对了,赢得了1000美元!");
} else if (str1.charAt(0) == str2.charAt(1) && str1.charAt(1) == str2.charAt(0)) {
System.out.println("恭喜你,你猜对了数字,但顺序错误,赢得了500美元!");
} else if (str2.charAt(0) == str1.charAt(0) && str2.charAt(1) != str1.charAt(1)
|| str2.charAt(0) != str1.charAt(0) && str2.charAt(1) == str1.charAt(1)
|| str1.charAt(1) == str2.charAt(0) && str1.charAt(0) != str2.charAt(1)
|| str1.charAt(0) == str2.charAt(1) && str1.charAt(1) != str2.charAt(0)) {
System.out.println("恭喜你,你猜对了其中一个数字!");
} else {
System.out.println("抱歉,你猜错了,请再试一次");
}
}
}
任务说明是:“一个彩票程序生成一个01-99之间的双位数。如果用户按正确顺序猜出数字,则赢得1000美元。如果用户按错误顺序猜出正确的数字,例如16代替61,则赢得500美元。如果用户猜对其中一个数字,赢得100美元。”
当用户输入和/或randomNum大于等于10时,代码运行正常。然而,当它小于10时,会出现错误,因为值被解释为1个字符而不是2个字符,例如:09被解释为9,所以charAt(1)不存在。
如何修复这个问题?是否有办法使0被视为charAt(0),这样charAt(1)就可以计算0后面的数字,还是需要改变其他内容?
谢谢!
英文:
my code is throwing an error "String index out of bound : 1" , here is the code :
package inlamningsuppgift2;
import java.util.Random;
import java.util.Scanner;
import java.lang.Math;
public class inlamningsuppgift2del2 {
public static void main(String[] args) {
System.out.println("Guess a number between 01-99");
randomNumber();
}
public static void randomNumber () {
Scanner scanner = new Scanner(System.in);
Random random = new Random();
int value = Integer.valueOf(scanner.nextLine());
String str1 = Integer.toString(value);
String sa = String.format("%02d", value);
int randomNum = 10 * random.nextInt(9);
int randomNum2 = 1 * random.nextInt(9) +1;
int wholeNum = randomNum + randomNum2;
String str2 = Integer.toString(randomNum + randomNum2);
String s = String.format("%02d", randomNum + randomNum2);
System.out.println("You guessed :" + sa);
System.out.println("The correct number is : " + s);
if (str2.charAt(0) == str1.charAt(0) && str2.charAt(1) == str1.charAt(1)) {
System.out.println("Congratulations, you guessed the right number in the right order and won 1000$!");
}
else if (str1.charAt(0) == str2.charAt(1) && str1.charAt(1) == str2.charAt(0) ) {
System.out.println("Congratulations, you guessed the right number but in the wrong order and won 500$ !");
}
else if (str2.charAt(0) == str1.charAt(0) && str2.charAt(1) != str1.charAt(1)
|| str2.charAt(0) != str1.charAt(0) && str2.charAt(1) == str1.charAt(1)
|| str1.charAt(1) == str2.charAt(0) && str1.charAt(0) != str2.charAt(1)
|| str1.charAt(0) == str2.charAt(1) && str1.charAt(1) != str2.charAt(0)) {
System.out.println("Congratulations, you guessed one of the numbers right!");
}
else {
System.out.println("Sorry you guessed wrong, try again");
}
}
}
The assignment instructions are : "A lottery program generates a double digit number between 01-99. If the user guesses the number right in the right order, they win 1000$. If the user guesses the right number in the wrong order, example 16 instead of 61, they win 500$. If the user guesses one of the numbers right, they win 100$."
The code is working fine when user input and/or randomNum are 10 and above. However ,when it is below 10 , the error occurs because the value is read as 1 char instead of 2, example : 09 is read as 9 , so charAt(1) does not exist.
How can I fix this? Is there a way to make 0 count as charAt(0) so that charAt(1) counts the digits after the 0, or do I need to change something else?
Thanks!
答案1
得分: 2
正如我在评论中提到的:您有String sa = String.format("%02d",value);
,但在主代码中使用str1
。改用sa
,即使数字小于10,它也将有2个字符。
另一个选项是不使用字符串。这里是一个仅使用数学的版本。
public static void randomNumber() {
System.out.println("猜一个01-99之间的数字");
Scanner scanner = new Scanner(System.in);
Random random = new Random();
int value = Integer.valueOf(scanner.nextLine());
// TODO: 添加检查,要求 1 <= value <= 99
int randomNum = random.nextInt(98) + 1;
System.out.printf("你猜的是:%02d%n", value);
System.out.printf("正确的数字是:%02d%n", randomNum);
// 检查是否完全匹配
if (value == randomNum) {
System.out.println("恭喜你,你以正确的顺序猜对了数字,赢得了1000美元!");
return;
}
// 获取随机数字的个位和十位数字(对于个位数也适用)
int randOnes = randomNum % 10;
int randTens = randomNum / 10;
// 检查逆序匹配
if (value == (randOnes * 10 + randTens)) {
System.out.println("恭喜你,你猜对了数字,但顺序错误,赢得了500美元!");
return;
}
// 获取用户的个位和十位数字
int userOnes = value % 10;
int userTens = value / 10;
// 检查单个数字匹配
if (userOnes == randOnes || userOnes == randTens || userTens == randOnes || userTens == randTens) {
System.out.println("恭喜你,你猜对了其中一个数字!");
return;
}
System.out.println("抱歉,你猜错了,请再试一次");
}
英文:
As I mentioned in the comments: You have String sa = String.format("%02d", value);
but you use str1
in the main code. Use sa
instead which will have 2 chars even if the number is less than 10.
Another option is to not use strings. Here is a math only version.
public static void randomNumber () {
{
System.out.println("Guess a number between 01-99");
Scanner scanner = new Scanner(System.in);
Random random = new Random();
int value = Integer.valueOf(scanner.nextLine());
// TODO: add a check 1 <= value <= 99
int randomNum = random.nextInt(98) + 1;
System.out.printf("You guessed :%02d%n", value);
System.out.printf("The correct number is : %02d%n", randomNum);
// Check for exact match
if (value == randomNum) {
System.out.println("Congratulations, you guessed the right number in the right order and won 1000$!");
return;
}
// Get the digits of the random number (works for single digit numbers, too)
int randOnes = randomNum % 10;
int randTens = randomNum / 10;
// Check for reverse match
if (value == (randOnes * 10 + randTens)) {
System.out.println("Congratulations, you guessed the right number but in the wrong order and won 500$ !");
return;
}
// Get user's digits
int userOnes = value % 10;
int userTens = value / 10;
// Check for single digit match
if (userOnes == randOnes || userOnes == randTens || userTens == randOnes || userTens == randTens) {
System.out.println("Congratulations, you guessed one of the numbers right!");
return;
}
System.out.println("Sorry you guessed wrong, try again");
}
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