英文:
How to convert two lists into list of objects
问题
我有一个类
public class Person{private String name;private Integer age;}
我还有两个列表：
List<String> names = List.of("Mike", "Piter", "Jack");List<Integer> ages = List.of(18, 29, 30, 32);
如何从这两个列表中获取对象列表并使用流式 API？
List<Person> = ... // [{"name": "Mike", "age": 18}, {"name": "Piter", "age": 29}, {"name": "Jack", "age": 30}, {"name": null, "age": 32}]
英文:
I have a class
public class Person{private String name;private Integer age;}
And i also have two lists:
List<String> names = List.of("Mike", "Piter", "Jack");List<int> ages = List.of(18, 29, 30, 32);
How can i get the list of objects from this two lists and stream api?
List<Person> = ... // [{"name" :"Mike", "age": 18}, {"name" :"Piter", "age": 29},{"name" :"Jack", "age": 30}, {"name" :null, "age": 32}]
答案1
得分: 1
首先，List<int> ages 应该改为 List<Integer> ages。您可以使用 IntStream.range 方法：
IntStream.range(0, Math.max(names.size(), ages.size())).mapToObj(i -> new Person((i < names.size() ? names.get(i): null),(i < ages.size() ? ages.get(i): null))).collect(Collectors.toList());
英文:
First of all List<int> ages should be List<Integer> ages. You can use IntStream.range
IntStream.range(0, Math.max(names.size(), ages.size())).mapToObj(i -> new Person((i < names.size() ? names.get(i): null),(i < ages.size() ? ages.get(i): null))).collect(Collectors.toList());
答案2
得分: 0
如果您希望在年龄为低尺寸时也将其赋值为null，则使用int数据类型无法实现。
解决方案1：
如果值不存在，则将姓名或年龄都赋值为null。
您需要将年龄的类型更改为String。
List<String> names = List.of("Mike", "Piter", "Jack");List<String> ages = List.of("18", "29");List<Person> collect = null;if (names.size() > ages.size()) {collect = IntStream.range(0, names.size()).mapToObj(i -> new Person(names.get(i), (i < ages.size() ? ages.get(i) : null))).collect(Collectors.toList());} else {collect = IntStream.range(0, ages.size()).mapToObj(i -> new Person(i < names.size() ? names.get(i) : null, ages.get(i))).collect(Collectors.toList());}System.out.println(collect);
解决方案2：
如果值不存在，则将姓名赋值为null，将年龄赋值为-1。
List<String> names = List.of("Mike", "Piter", "Jack");List<Integer> ages = List.of(18, 29);List<Person> collect = null;if (names.size() > ages.size()) {collect = IntStream.range(0, names.size()).mapToObj(i -> new Person(names.get(i), (i < ages.size() ? ages.get(i) : -1))).collect(Collectors.toList());} else {collect = IntStream.range(0, ages.size()).mapToObj(i -> new Person(i < names.size() ? names.get(i) : null, ages.get(i))).collect(Collectors.toList());}System.out.println(collect);
英文:
If you want to assign null to the age also when it has low size then it can't achieve with int data type.
Solution 1:
assign null to both name or age if the value is not there
you need to change the type of age to String
List<String> names = List.of("Mike", "Piter", "Jack");List<String> ages = List.of("18", "29");List<Person> collect = null;if (names.size() > ages.size()) {collect = IntStream.range(0, names.size()).mapToObj(i -> new Person(names.get(i), (i < ages.size() ? ages.get(i) : null))).collect(Collectors.toList());} else {collect = IntStream.range(0, ages.size()).mapToObj(i -> new Person(i < names.size() ? names.get(i) : null, ages.get(i))).collect(Collectors.toList());}System.out.println(collect);
Solution 2:
assign null to name and -1 to age if the value is not there
List<String> names = List.of("Mike", "Piter", "Jack");List<Integer> ages = List.of(18, 29);List<Person> collect = null;if (names.size() > ages.size()) {collect = IntStream.range(0, names.size()).mapToObj(i -> new Person(names.get(i), (i < ages.size() ? ages.get(i) : -1))).collect(Collectors.toList());} else {collect = IntStream.range(0, ages.size()).mapToObj(i -> new Person(i < names.size() ? names.get(i) : null, ages.get(i))).collect(Collectors.toList());}System.out.println(collect);
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