英文:
how can I print these triangles side by side?
问题
public class MyClass {public static void main(String[] args) {for (int r = 1; r <= 10; r++) {// Draw the first trianglefor (int c = 1; c <= r; c++)System.out.print("*");for (int c = r + 1; c <= 10; c++)System.out.print(" ");System.out.print(" ");// Draw the second trianglefor (int c = 1; c <= (11 - r); c++)System.out.print("*");for (int c = (11 - r) + 1; c <= 10; c++)System.out.print(" ");System.out.print(" ");// Draw the third trianglefor (int c = 1; c <= (r - 1); c++)System.out.print(" ");for (int c = r; c <= 10; c++)System.out.print("*");System.out.print(" ");// Draw the fourth trianglefor (int c = 1; c <= (10 - r); c++)System.out.print(" ");for (int c = 10 - r + 1; c <= 10; c++)System.out.print("*");System.out.println();}}}
英文:
I'm given the code below that outputs two triangles like this. However I need to modify the code provided to output 4 triangles side by side to look like this I've messed around with it but get confused with all the nested loops? Any help would be awesome.
public class MyClass {public static void main(String[] args) {//for (int i=1; i <= 10; i++)for (int r=1; r<= 10; r++) {// Draw the triangle 1//for (int j =1; j <=i; j++)for (int c =1; c <=r; c++)System.out.print("*");for (int c=r+1; c<=10; c++)System.out.print(" ");System.out.print(" ");// Draw the trisngle 2for (int c = 1; c <= (11 - r); c++)System.out.print("*");for (int c = (11 - r) + 1; c <= 10; c++)System.out.print(" ");System.out.print(" ");System.out.println();} //end of for r} //end of static void main}
答案1
得分: 2
在Java 11+中，您可以将其简化为以下形式，使用动态数量的三角形和动态三角形大小。
static void printTriangles(int triangles, int size) {for (int i = 0; i < size; i++) {for (int j = 0; j < triangles; j++) {if (j % 2 == 0)System.out.print("*".repeat(i + 1) + " ".repeat(size - i));elseSystem.out.print("*".repeat(size - i) + " ".repeat(i + 1));}System.out.println();}}
Tests
printTriangles(2, 10);printTriangles(4, 10);printTriangles(7, 6);
Outputs
* ************ ************ ************ ************ ************ ************ ************ ************ ************ *
* ********** * ************ ********* ** ************ ******** *** ************ ******* **** ************ ****** ***** ************ ***** ****** ************ **** ******* ************ *** ******** ************ ** ********* ************ * ********** *
* ****** * ****** * ****** *** ***** ** ***** ** ***** ***** **** *** **** *** **** ******* *** **** *** **** *** ********* ** ***** ** ***** ** *********** * ****** * ****** * ******
英文:
In Java 11+, you can make it as simple as this, with dynamic number of triangles, and dynamic triangle size.
static void printTriangles(int triangles, int size) {for (int i = 0; i < size; i++) {for (int j = 0; j < triangles; j++) {if (j % 2 == 0)System.out.print("*".repeat(i + 1) + " ".repeat(size - i));elseSystem.out.print("*".repeat(size - i) + " ".repeat(i + 1));}System.out.println();}}
Tests
printTriangles(2, 10);printTriangles(4, 10);printTriangles(7, 6);
Outputs
* ************ ************ ************ ************ ************ ************ ************ ************ ************ *
* ********** * ************ ********* ** ************ ******** *** ************ ******* **** ************ ****** ***** ************ ***** ****** ************ **** ******* ************ *** ******** ************ ** ********* ************ * ********** *
* ****** * ****** * ****** *** ***** ** ***** ** ***** ***** **** *** **** *** **** ******* *** **** *** **** *** ********* ** ***** ** ***** ** *********** * ****** * ****** * ******
答案2
得分: 2
一个对 @Andreas的回答 的跟进，通过添加两种类型/线型来提供所需的三角形类型：
static String pattern(String left, int leftCount, String right, int rightCount) {return left.repeat(leftCount) + right.repeat(rightCount);}static void printTriangles(int triangles, int size) {for (int i = 0; i < size; i++) {for (int j = 0; j < triangles; j++) {String line = "";switch(j % 4) {case 0: line = pattern("*", i + 1, " ", size - i);break;case 1: line = pattern("*", size - i, " ", i + 1);break;case 2: line = pattern(" ", i + 1, "*", size - i);break;case 3: line = pattern(" ", size - i, "*", i + 1);break;};System.out.print(line);}System.out.println();}}
对于 Java 13+，可以使用更短的 switch：
static void printTrianglesJava13(int triangles, int size) {for (int i = 0; i < size; i++) {for (int j = 0; j < triangles; j++) {String line = switch(j % 4) {case 0 -> pattern("*", i + 1, " ", size - i);case 1 -> pattern("*", size - i, " ", i + 1);case 2 -> pattern(" ", i + 1, "*", size - i);case 3 -> pattern(" ", size - i, "*", i + 1);default -> "";};System.out.print(line);}System.out.println();}}
printTriangles(4, 10) 的输出结果：
* ********** ********** *** ********* ********* ***** ******** ******** ******* ******* ******* ********* ****** ****** *********** ***** ***** ************* **** **** *************** *** *** ***************** ** ** ******************* * * **********
英文:
A followup for @Andreas answer to provide required types of triangles by adding two more types/line patterns:
static String pattern(String left, int leftCount, String right, int rightCount) {return left.repeat(leftCount) + right.repeat(rightCount);}static void printTriangles(int triangles, int size) {for (int i = 0; i < size; i++) {for (int j = 0; j < triangles; j++) {String line = "";switch(j % 4) {case 0: line = pattern("*", i + 1, " ", size - i);break;case 1: line = pattern("*", size - i, " ", i + 1);break;case 2: line = pattern(" ", i + 1, "*", size - i);break;case 3: line = pattern(" ", size - i, "*", i + 1);break;};System.out.print(line);}System.out.println();}}
For Java 13+ a shorter switch may be used:
static void printTrianglesJava13(int triangles, int size) {for (int i = 0; i < size; i++) {for (int j = 0; j < triangles; j++) {String line = switch(j % 4) {case 0 -> pattern("*", i + 1, " ", size - i);case 1 -> pattern("*", size - i, " ", i + 1);case 2 -> pattern(" ", i + 1, "*", size - i);case 3 -> pattern(" ", size - i, "*", i + 1);default -> "";};System.out.print(line);}System.out.println();}}
Output of printTriangles(4, 10):
* ********** ********** *** ********* ********* ***** ******** ******** ******* ******* ******* ********* ****** ****** *********** ***** ***** ************* **** **** *************** *** *** ***************** ** ** ******************* * * **********
答案3
得分: 0
我在这里使用了两个计数器，在以下代码中：
public class Temp {public static void main(String[] args) {int countA = 1;int countB = 10;for (int r = 1; r <= 10; r++) {for (int i = 1; i <= 10; i++) {if (countA >= i) {System.out.print("*");} else {System.out.print(" ");}}System.out.print(" ");for (int i = 1; i <= 10; i++) {if (countB >= i) {System.out.print("*");} else {System.out.print(" ");}}System.out.print(" ");for (int i = 1; i <= 10; i++) {if (countA > i) {System.out.print(" ");} else {System.out.print("*");}}System.out.print(" ");for (int i = 1; i <= 10; i++) {if (countB > i) {System.out.print(" ");} else {System.out.print("*");}}countB--;countA++;System.out.println();}}}
英文:
I have used two counters here, in the following code
public class Temp {public static void main(String[] args) {int countA = 1;int countB = 10;for (int r=1; r<= 10; r++) {for (int i=1; i<= 10; i++) {if(countA >= i) {System.out.print("*");}else {System.out.print(" ");}}System.out.print(" ");for (int i=1; i<= 10; i++) {if(countB >= i) {System.out.print("*");}else {System.out.print(" ");}}System.out.print(" ");for (int i=1; i<= 10; i++) {if(countA > i) {System.out.print(" ");}else {System.out.print("*");}}System.out.print(" ");for (int i=1; i<= 10; i++) {if(countB > i) {System.out.print(" ");}else {System.out.print("*");}}countB--;countA++;System.out.println();}}}
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