英文:
How to open Deep Links in webview application
问题
我已经创建了我的 WebView 应用程序，并在 onCreate 方法中加载了我的主要 URL 到 WebView 中。然后我像这样实现了深链接：
我的清单文件：
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.ariagp.myapplication">
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" />
<uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE" />
<application
android:allowBackup="true"
android:icon="@mipmap/ic_launcher"
android:label="@string/app_name"
android:roundIcon="@mipmap/ic_launcher_round"
android:supportsRtl="true"
android:theme="@style/AppTheme">
<activity android:name=".MainActivity">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="https" android:host="mysitename.com" />
</intent-filter>
</activity>
</application>
</manifest>
现在当深链接被点击时，应用程序会在 WebView 的主页上打开。但我想要打开与深链接相关的页面。
而当应用程序自身打开时，使主页打开。有什么解决方案呢？
英文:
i have created my webview application and i loaded my main url in onCreate method to webview. then i implemented the deep links like this:
My Manifest:
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.ariagp.myapplication">
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" />
<uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE" />
<application
android:allowBackup="true"
android:icon="@mipmap/ic_launcher"
android:label="@string/app_name"
android:roundIcon="@mipmap/ic_launcher_round"
android:supportsRtl="true"
android:theme="@style/AppTheme">
<activity android:name=".MainActivity">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="https" android:host="mysitename.com" />
</intent-filter>
</activity>
</application>
</manifest>
Now when the deep links get clicked, the app will open on the webview homepage.
But I want to make the page related to the deep link open.
And when the app itself opens, make the home page open.
what is the solution?
答案1
得分: 1
当活动被启动时，在onNewIntent(Intent intent)方法中，从intent中获取数据（它应该是点击的URL - 深链接），该数据的类型为uri，然后在您已经实现的Web视图中加载该URL。
类似以下代码：
@Override
protected void onNewIntent(Intent intent) {
super.onNewIntent(intent);
Uri data = intent.getData();
webView.loadUrl(data.toString());
}
英文:
When the activity is launched, in the onNewIntent(Intent intent) method, get data from intent (it is supposed to be the url clicked - deep link) which has the type uri, and then load that url in the web view that you've implemented.
Something like below code:
@Override
protected void onNewIntent(Intent intent) {
super.onNewIntent(intent);
Uri data = intent.getData();
webView.loadUrl(data.toString());
}
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