英文:
does variable assigned to another variable changes( original variable changes ) does the second variable change?
问题
以下是您要求的翻译内容：
我制作了这段代码来计算 x^y，而不使用 math 类。我使用了一个变量 m，将其赋值为 x。当 x 在循环中改变其值时，变量 m 的值是否也会随之改变，因为它等于 x，还是保持与初始 x 相同？
package loops;import java.util.Scanner;public class XToPowerY {/*** @param args*/public static void main(String[] args) {Scanner sc = new Scanner(System.in);int x = sc.nextInt();int y = sc.nextInt();int m = x;for (int i = 0; i <= y - 2; i++) {x = x * m;}System.out.println(x);}}
英文:
I made this code to calculate x^y without using math class, I used a variable m which I put equal to x. When x changes its value in the loop, does the value of m also changes as it is equal to x or remains the same to initial x?
package loops;import java.util.Scanner;public class XToPowerY {/*** @param args*/public static void main(String[] args) {Scanner sc = new Scanner(System.in);int x = sc.nextInt();int y = sc.nextInt();int m = x;for (int i = 0; i <= y - 2; i++) {x = x * m;}System.out.println(x);}
}
答案1
得分: 2
m保持在x的初始值。如果在你的for循环中包括m = x;，它会发生变化。然而，请记住，Java只对基本数据类型行为如此。
英文:
m stays at the initial value of x. It would change, if you would include m = x; in your for-loop. Remember however, that Java only behaves this way with primitives.
答案2
得分: 1
使用调试器有助于您的情况 / 通过几次点击回答您的问题。
m 保持其值，因为您仅存储了 x 的值，而不是引用。
英文:
Using a debugger helps in your case / answers your question with a few clicks.
m keeps it value, since you store only the value of x not the reference.
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