如何从字符串中删除所有字符,直到一定范围内的字符为止?

huangapple go评论78阅读模式
英文:

How to remove all character from a string until a range of accepted characters?

问题

例如,我有一个字符串"0.01"。如何获得"1"

我尝试过:

String a = "0.01"
a = a.replaceAll(".", "");
a = a.replaceAll("0", "");

但是这不起作用,因为字符串可能是"0.0105",在这种情况下,我想保留"105"

我还尝试过:

String a = "0.01"
b = a.substring(s.indexOf("0")+3);

这也不起作用,因为字符串可能是"0.1",我想保留"1"

简而言之,我想要删除所有的0.,直到它以非零数开头。该字符串实际上是从Double转换而来的。我不能简单地对Double执行*100,因为它可以是0.1

英文:

For example, I have a string "0.01". How can I get "1"?

I had tried

String a = "0.01"
a = a.replaceAll(".", "");
a = a.replaceAll("0", "");

but this won't work as the string can be "0.0105" and in this case, I want to keep "105"

I also tried

String a = "0.01"
b = a.substring(s.indexOf("0")+3);

this also won't work as the string can be "0.1" which I want to keep "1"

In short, I want to remove all 0 or . until it starts with non-0. The string is actually converted from Double. I can't simply *100 with the Double as it can be 0.1

答案1

得分: 2

String a = "0.01";
String[] b = a.split("\\.");
a = b[0] + b[1];

int c = Integer.parseInt(a);

// You will get 1 as an integer. When you want to add something you can add and then return it to a string like:

c = c + 3;
String newa = String.valueOf(c);
System.out.println(newa);
英文:
	String a = "0.01";
	String[] b = a.split("\\.");
	a = b[0]+b[1];
	
	int c = Integer.parseInt(a);

You will get 1 as integer. When you want to add something you can add and then return to string like:

    c = c+3;		
	String newa = String.valueOf(c);
	System.out.println(newa);

答案2

得分: 2

只需执行:

System.out.println(Integer.valueOf(testCase.replace(".", "")));

原文出自YCF_L

英文:

Just do:

System.out.println(Integer.valueOf(testCase.replace(".", "")));

Credit to YCF_L

答案3

得分: 0

使用正则表达式 [1-9][0-9]*,它表示第一个数字为 1-9,然后后续的数字(可选的)为 0-9。从 Lesson: Regular Expressions 中了解更多关于正则表达式的内容。

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Main {
    public static void main(String[] args) {
        String str = "0.0105";
        Pattern pattern = Pattern.compile("[1-9][0-9]*");
        Matcher matcher = pattern.matcher(str);
        if (matcher.find()) {
            str = matcher.group();
        }

        System.out.println(str);
    }
}

输出:

105
英文:

Use the regex, [1-9][0-9]* which means the first digit as 1-9 and then subsequent digits (optional) as 0-9. Learn more about regex from Lesson: Regular Expressions.

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Main {
	public static void main(String[] args) {
		String str = "0.0105";
		Pattern pattern = Pattern.compile("[1-9][0-9]*");
		Matcher matcher = pattern.matcher(str);
		if (matcher.find()) {
			str = matcher.group();
		}

		System.out.println(str);
	}
}

Output:

105

huangapple
  • 本文由 发表于 2020年10月11日 00:43:11
  • 转载请务必保留本文链接:https://go.coder-hub.com/64295864.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定