英文:
How to remove all character from a string until a range of accepted characters?
问题
例如，我有一个字符串"0.01"。如何获得"1"？
我尝试过：
String a = "0.01"a = a.replaceAll(".", "");a = a.replaceAll("0", "");
但是这不起作用，因为字符串可能是"0.0105"，在这种情况下，我想保留"105"
我还尝试过：
String a = "0.01"b = a.substring(s.indexOf("0")+3);
这也不起作用，因为字符串可能是"0.1"，我想保留"1"
简而言之，我想要删除所有的0或.，直到它以非零数开头。该字符串实际上是从Double转换而来的。我不能简单地对Double执行*100，因为它可以是0.1。
英文:
For example, I have a string "0.01". How can I get "1"?
I had tried
String a = "0.01"a = a.replaceAll(".", "");a = a.replaceAll("0", "");
but this won't work as the string can be "0.0105" and in this case, I want to keep "105"
I also tried
String a = "0.01"b = a.substring(s.indexOf("0")+3);
this also won't work as the string can be "0.1" which I want to keep "1"
In short, I want to remove all 0 or . until it starts with non-0. The string is actually converted from Double. I can't simply *100 with the Double as it can be 0.1
答案1
得分: 2
String a = "0.01";String[] b = a.split("\\.");a = b[0] + b[1];int c = Integer.parseInt(a);// You will get 1 as an integer. When you want to add something you can add and then return it to a string like:c = c + 3;String newa = String.valueOf(c);System.out.println(newa);
英文:
String a = "0.01";String[] b = a.split("\\.");a = b[0]+b[1];int c = Integer.parseInt(a);
You will get 1 as integer. When you want to add something you can add and then return to string like:
c = c+3;String newa = String.valueOf(c);System.out.println(newa);
答案2
得分: 2
只需执行：
System.out.println(Integer.valueOf(testCase.replace(".", "")));
原文出自YCF_L。
英文:
Just do:
System.out.println(Integer.valueOf(testCase.replace(".", "")));
Credit to YCF_L
答案3
得分: 0
使用正则表达式 [1-9][0-9]*，它表示第一个数字为 1-9，然后后续的数字（可选的）为 0-9。从 Lesson: Regular Expressions 中了解更多关于正则表达式的内容。
import java.util.regex.Matcher;import java.util.regex.Pattern;public class Main {public static void main(String[] args) {String str = "0.0105";Pattern pattern = Pattern.compile("[1-9][0-9]*");Matcher matcher = pattern.matcher(str);if (matcher.find()) {str = matcher.group();}System.out.println(str);}}
输出:
105
英文:
Use the regex, [1-9][0-9]* which means the first digit as 1-9 and then subsequent digits (optional) as 0-9. Learn more about regex from Lesson: Regular Expressions.
import java.util.regex.Matcher;import java.util.regex.Pattern;public class Main {public static void main(String[] args) {String str = "0.0105";Pattern pattern = Pattern.compile("[1-9][0-9]*");Matcher matcher = pattern.matcher(str);if (matcher.find()) {str = matcher.group();}System.out.println(str);}}
Output:
105
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