Remove Alternate Elements from ArrayList in java 7

I have an array of String containing below elements

5.0,99,5.5,100,6.0,101

Now what I want to do I need to remove all the decimal value in string format like 5.0,5.5 and 6.0

so my final array should contain elements 99,100,101

so what I'd done so far is show in below code

public static String[] deleteElement(String[] str_array) {
		//String[] str_array = {"item1","item2","item3"};
		List<String> list = new ArrayList<String>(Arrays.asList(str_array));
		
		list.remove("5.0");
		list.remove("5.5");
		list.remove("6.0");
		return str_array = list.toArray(new String[0]);
	}

I have hardcoded the values which is quite bad practice as the values in future may be more than the current values, so I want a way to remove by using index.

I have tried to remove using remove(index) also, using even index positioning like 0,2,4,but what actually happening is, after deletion of 5.0 , elements are shifted left side, so 100 comes into the 2nd position, and in next iteration 100 deleted.

So is there any way where I can construct a generic function so if there are more elements in decimal value so it can also be deleted.

NOTE:
The string decimal values will always be residing on even index positioning.

You can go with the below approach, it worked fine for me !!

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

public class DecimalRemoval {
	public static void main(String[] args) {
		
		List<String> lst = Arrays.asList("5.0","99","5.5","100","6.0","101");
		List<String> resultant = new ArrayList<>(lst.size());
		
		for(String element: lst) {
			if(! element.contains("."))
				resultant.add(element);
		}
		
		System.out.println(resultant);
	}
}

Also attaching the screenshot from my workspace.

We have traversed the List from list.size() -1 to 0<br>
So that number arent pushed in front.<br>
when you traverse it from 0 to size of the list and then if you delete an element 1 element is skipped cause size() of the list decreases and i keeps incrementing.<br>
eg.["5.0","6.1","5.5","100","6.0","6.6"]
when you traverse form 0 to size() - 1<br>
i = 0 : <br>
5.0 is seen and removed and then the list is like ["6.1","5.5","100","6.0","6.6"] where now 6.1 is at 0 index.<br>

i = 1: <br>
5.5 is removed and then the list is like<br>
["6.1","100","6.0","6.6"] where now 100 is at 1 index.<br>

and so on.<br>

But when traverse from size-1 to 0 it will remove every single element without the fear of missing any decimal number.<br>
Try this on your own and you will get to know why it is working and why 0 to n-1 isn't working.

            String arr[] = {"5.0","99","5.5","100","6.0","101"};
            List<String> list = new ArrayList<String>(Arrays.asList(arr));
            for(int i = list.size() - 1 ; i >= 0 ; i--) {
            	String number = list.get(i);
            	if(number.contains(".")) {
            		list.remove(number);
            	}
            }
            
            for(String val : list) {
            	System.out.println(val);
            }

output:

99
100
101

The existing answers work but are more verbose than required:

list.removeIf(str -> str.contains("."));

You can also just stream the array and filter out the unwanted values.

String[] v = {"5.0","99","5.5","100","6.0","101"};
v = Arrays.stream(v)
        .filter(str->!str.contains("."))
        .toArray(String[]::new);


System.out.println(Arrays.toString(v));

Prints

[99, 100, 101]

</details>



# 答案5
**得分**: 1

一个简单的解决方案可以是：

 1. 实例化一个 `ArrayList<String>`。
 2. 遍历数组，如果元素不包含 `.`，则将其添加到列表中。
 3. 最后将列表转换为数组并返回。

**示例：**

```java
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

public class Main {
    public static String[] deleteElement(String[] str_array) {
        List<String> list = new ArrayList<>();
        for (String s : str_array) {
            if (!s.contains(".")) {
                list.add(s);
            }
        }

        return list.toArray(new String[0]);
    }

    public static void main(String[] args) {
        // 测试
        System.out.println(Arrays.toString(deleteElement(new String[] { "5.0", "99", "5.5", "100", "6.0", "101" })));
    }
}

输出：

[99, 100, 101]

另外，你也可以按照你已经在做的方式来实现，但这并不是一种高效的方式。因为你首先将所有元素添加到列表中，然后再移除不需要的元素，所以这种方式不如上面建议的方式高效。

public static String[] deleteElement(String[] str_array) {
    List<String> list = new ArrayList<String>(Arrays.asList(str_array));
    for (String s : str_array) {
        if (s.contains(".")) {
            list.remove(s);
        }
    }

    return list.toArray(new String[0]);
}

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

public class Main {
	public static String[] deleteElement(String[] str_array) {
		List<String> list = new ArrayList<>();
		for (String s : str_array) {
			if (!s.contains(".")) {
				list.add(s);
			}
		}

		return list.toArray(new String[0]);
	}

	public static void main(String[] args) {
		// Test
		System.out.println(Arrays.toString(deleteElement(new String[] { "5.0", "99", "5.5", "100", "6.0", "101" })));
	}
}

[99, 100, 101]

public static String[] deleteElement(String[] str_array) {
	List<String> list = new ArrayList<String>(Arrays.asList(str_array));
	for (String s : str_array) {
		if (s.contains(".")) {
			list.remove(s);
		}
	}

	return list.toArray(new String[0]);
}

答案6

得分: 0

对于Java 8用户，最佳解决方案是使用Java lambda表达式。

list.removeIf(element -> element.contains("."));

<details>
<summary>英文:</summary>

 **For Java 8 users ,
 Best solution would be using the Java lambda expressions**.

list.removeIf(element -> element.contains("."));

</details>