英文:
How To Change Every Other Value in An Array (Java)
问题
对于这个编程作业，我的教授要求我们使用 for 循环将数组中每隔一个数字替换为 100：
//-- (8) 使用下面的名为 grades 的数组。//-- 从索引 0 开始，使用 for 循环将每隔一个成绩改为 100。//-- 在进行更改之前和之后，使用 Printf 打印出数组在变化前和变化后的样子。int i;int g;int grades[] = { 87, 95, 65, 70, 77, 99, 0, 65, 25, 80, 90, 11 };System.out.println("\n(8) 变更前： " + Arrays.toString(grades));for (i = 0; i < grades.length; ++i){//FIXME: 对于每隔一个成绩（索引 0、2、4、6、8），将成绩改为 100}System.out.println("\n(8) 变更后：" + Arrays.toString(grades));
然而，我不确定如何实现这一点。我尝试了像这样的方法：grade[0] = 100; grade[2] = 100; 等等，但是我的教授希望我们假装程序不知道我们把这些数字放入数组中（如果这有意义的话）。我感谢你们能给我的任何帮助。
英文:
For this programming assignment, my professor wants us to replace every other number in this array into a 100 using a for loop:
//-- (8) Use the array called grades, below.//-- starting with index 0 use a for loop to change every other//-- grade to 100.//-- Printf what the array was BEFORE the changes, and AFTER then Changes.int i;int g;int grades[] = { 87, 95, 65, 70, 77, 99, 0, 65, 25, 80, 90, 11 };System.out.println ("\n(8) Before change: " + Arrays.toString(grades));for (i = 0; i < grades.length; ++i){//FIXME: For every other grade (index 0, 2, 4, 6, 8), change grade to 100}System.out.println ("\n(8) After change:" + Arrays.toString(grades));
However, I am not sure how to do this. I have tried something like this: grade[0] = 100; grade[2] = 100; etc., but my professor wants us to pretend the program doesn't know that we put in those numbers for the array (if that makes sense). I appreciate any help you guys can give me.
答案1
得分: 4
你可以通过调整 for 循环的参数来实现这一点：
for (i = 0; i < grades.length; i+=2) {grades[i] = 100;}
因此，在这里，每次迭代后，你将使用 i+=2 而不是 i++ 将 i 增加 2。
英文:
You can achieve this by playing with the for loop arguments:
for (i = 0; i < grades.length; i+=2) {grades[i]=100;}
So here, after each iteration, you will increment i by 2 by using i+=2 instead of i++.
答案2
得分: 1
使用循环。每次递增2而不是1。例如，
for (i = 0; i < grades.length; i += 2){grades[i] = 100;}
或者，如果你不能改变++i，只需：
for (i = 0; i < grades.length; ++i){grades[i] = 100;++i;}
或者
for (i = 0; i < grades.length; ++i){grades[i++] = 100;}
英文:
Use a loop. Increment by 2 instead of by 1. For example,
for (i = 0; i < grades.length; i += 2){grades[i] = 100;}
Or, if you can't change ++i just
for (i = 0; i < grades.length; ++i){grades[i] = 100;++i;}
or
for (i = 0; i < grades.length; ++i){grades[i++] = 100;}
答案3
得分: 1
可以甚至使用取模运算符。
for (i = 0; i < grades.length; ++i){if (i % 2 == 0) {grades[i] = 100;}}
英文:
Could even use the modulo operator
for (i = 0; i < grades.length; ++i){if (i % 2 == 0) {grades[i] = 100;}}
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