Using regex to validate password

This is my current code:

import java.util.*;
import java.util.regex.*;

public class TestClass {
    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        String password = scan.nextLine();
        if (password.length() >= 10) {
            if (Pattern.matches("[a-zA-Z]\\d{2}", password)) {
                System.out.println("Password is valid");
            }
        }
    }
}

Description

Password rules:

• A password must have at least ten characters.
• A password consists of only letters and digits.
• A password must contain at least two digits

This is the code that I've been trying for validating the password but It doesn't print my output.

I would use the following regex pattern to assert your requirements:

^(?!.*[^A-Za-z0-9])(?=.{10,}).*\\d.*\\d.*$

This pattern says to:

^                   from the start of the password
(?!.*[^A-Za-z0-9])  look ahead and assert that we do NOT see any non letters or digits
(?=.{10,})          look ahead and assert that password length be 10 or longer
.*\\d.*\\d.*        then match any pattern so long as two digits be present
$                   end of the password

I would probably just directly use String#matches here:

Scanner scan = new Scanner(System.in);
String password = scan.nextLine();
if (password.matches("(?!.*[^A-Za-z0-9])(?=.{10,}).*\\d.*\\d.*")) {
    System.out.println("Password is valid");
}

Note that we drop the ^ and $ anchors from the regex pattern when using it with String#matches because this method implicitly applies the pattern to the entire string input.