How to add 1 to each value in an array (in Java)?

Here's the prompt:
Loop through an integer array adding one to each element. Return the resulting array. The array may be of any length including 0.

Here's what I have so far:

public int[] add1toEach(int[] nums) {
  int[] array = new int[nums.length];
  for (int i = 0; i < nums.length; i++) {
    nums[i]++;
  }
  return array;
}

It works with add1toEach[] and add1toEach[-1] but that's it. How do I get it to spit out [7, 7, 3] if add1toEach[6, 6, 2] is the input?

The fact is that you aren't assigning the new added result to the array, nor are you adding it properly.

The proper code is:

    public static int[] add1toEach(int[] nums) {
        int[] array = new int[nums.length];
        for (int i = 0; i < nums.length; i++) {
          array[i]=nums[i]+1;
         }
        return array;
    }

What's happening here is that we add 1 to the item, then we assign the item to an identical array, but which the items are all empty. This happens to every single item of the array, as demonstrated in the statement in the for loop i < nums.length; i++.

This working example:

public class MyClass {
    public static void main(String args[]) {
      int[] nums = {1, 2, 3};
      int[] newnums = add1toEach(nums);
      for(int i = 0; i < newnums.length; i++){
          System.out.println(newnums[i]);
      }
    }
    public static int[] add1toEach(int[] nums) {
        int[] array = new int[nums.length];
        for (int i = 0; i < nums.length; i++) {
          array[i]=nums[i]+1;
         }
        return array;
    }
}

Produces

2
3
4

What you're code doing is it only returns the untouched int[] array.

Since you have set the length of your array, you just need to set values to your array with position array[i] to make the values assigned and intact position.

array[i]=nums[i]++;