问题

我正在尝试从公共字符串myString中移除输入字符串。

myString = "Hello"

removeS("el")将返回"Hlo"

以下是我的代码和其中的问题：不兼容的类型：java.lang.String无法转换为int，我的问题在于String result。我希望您使用substring()和indexOf()来解决我的问题，而不要使用除这些之外的任何其他工具。我该如何修复这个问题。

public class StringI
{
public String myString;

public String removeS(String s){

    myString = "Hello";
    
    int index = myString.indexOf(s);  // 使用indexOf()找到要移除的子字符串的索引
    if (index != -1) {  // 确保找到了要移除的子字符串
        String result = myString.substring(0, index) + myString.substring(index + s.length());  // 使用substring()进行字符串拼接
        return result;
    } else {
        return myString;  // 如果未找到要移除的子字符串，返回原字符串
    }
}

public static void main(String args[]){
    StringI n = new StringI();
    System.out.println(n.removeS("el"));  // 打印结果
}

}

<details>
<summary>英文:</summary>

I am trying to remove the input string from the public string myString

myString = &quot;Hello&quot;

removeS(&quot;el&quot;) will return &quot;Hlo&quot;

Heres my code below and the problem in it is incompatible types: java.lang.String cannot be converted to int in my String result. I would like it if you used substring() and indexOf() to solve my issue and not use any other power tools than those. How would I go about fixing this.

public class StringI
{
public String myString;

public String removeS(String s){

myString = "Hello";


String result = s.substring(myString);

return result;
}

public static void main(String args[]){

StringI n = new StringI();

n.removeS("el");

}

}

</details>


# 答案1
**得分**: 1

我们需要获取前半部分和后半部分，然后将它们拼接在一起，如下所示：

```java
String result = myString.substring(0, myString.indexOf(s)) + myString.substring(myString.indexOf(s) + s.length());

由于 .indexOf() 返回 s 的位置，我们可以使用 substring 从字符串的开头开始到该位置，然后使用另一个 substring 获取最后部分。

以下程序：

import java.util.Scanner;

public class Main {
    public static String removeS(String s) {
        String myString = "Hello";
        String result = myString.substring(0, myString.indexOf(s)) + myString.substring(myString.indexOf(s) + s.length(), myString.length());
        return result;
    }

    public static void main(String[] args) {
        System.out.println(removeS("el"));
    }
}

产生的输出结果为：

Hlo

String result = myString.substring(0, myString.indexOf(s))+myString.substring(myString.indexOf(s)+s.length());

import java.util.Scanner; 
 
 public class Main {
     public static String removeS(String s){
         String myString = "Hello";
         String result = myString.substring(0, myString.indexOf(s))+myString.substring(myString.indexOf(s)+s.length(), myString.length());
         return result;
     }
 public static void main(String[] args) {
    System.out.println(removeS("el"));
 }
}

Hlo

答案2

得分: 1

public class StringI
{
    public String myString;

    public String removeS(String s){
        myString = "Hello";
        
        // Before the `s`
        String part1 = myString.substring(0, myString.indexOf(s));
        // After the `s`
        String part2 = myString.substring(myString.indexOf(s) + s.length());

        return part1 + part2;
    }

    public static void main(String args[]){
        StringI n = new StringI();
        String result = n.removeS("el");
        
        System.out.println(result);
    }
}

public class StringI
{
    public String myString;

    public String removeS(String s){
        myString = "Hello";
        
        // Before the `s`
        String part1 = myString.substring(0, myString.indexOf(s));
        // After the `s`
        String part2 = myString.substring(myString.indexOf(s) + s.length());

        return part1 + part2;
    }

    public static void main(String args[]){
        StringI n = new StringI();
        String result = n.removeS("el");
        
        System.out.println(result);
    }
}

答案3

得分: -1

以下是翻译好的内容：

最简单的方法是-

public static void main(String[] args) {
    String myString = "Hello";
    String removeString = "el";
    System.out.println(myString.replace(removeString, ""));
}

public static void main(String[] args) {
    String myString = "Hello";
    String removeString="el";
    System.out.println(myString.replace(removeString,""));
}