Why do I get only the last object of an array in my Java code?

I don't understand why only the last object water of array drinksRange is shown after executing the code even if the value of moneyAmount is 150 or more

 public class Main {
 public static void main(String[] args) {
    System.out.println("Coffee-machine");

    Drink[] drinksRange = new Drink [4];

    drinksRange[0] = new Drink(Drink.name = "cappuccino", Drink.price = 150);
    drinksRange[1] = new Drink(Drink.name = "espresso", Drink.price = 80);
    drinksRange[2] = new Drink(Drink.name = "milk", Drink.price = 50);
    drinksRange[3] = new Drink(Drink.name = "water", Drink.price = 20);

    System.out.print("Insert money: ");
    int moneyAmount = new Scanner(System.in).nextInt();

        for (Drink i : drinksRange) {
            if (moneyAmount >= i.price) {
                System.out.println("You can buy " + i.name);
            }
        }
}

public class Drink {
  static String name;
  static int price;

 public Drink (String drinkName, int drinkPrice) {
  name = drinkName;
  price = drinkPrice;
  System.out.println(name + " - " + price);
 }
}

As a result I get this:

Coffee-machine
cappuccino - 150
espresso - 80
milk - 50
water - 20
Insert money: 150
You can buy water
You can buy water
You can buy water
You can buy water

Your fields

static String name;
static int price;

are static hence the last value will be the final value for all objects when u are calling Drink.[any static property] hence the arraylist only contains the drink as water and value 20.

Check the modified code below:

import java.util.Scanner;

public class SOTest {

    public static void main(String[] args) {
        System.out.println("Coffee-machine");

        Drink[] drinksRange = new Drink [4];

        drinksRange[0] = new Drink("cappuccino", 150);
        drinksRange[1] = new Drink("espresso",80);
        drinksRange[2] = new Drink("milk", 50);
        drinksRange[3] = new Drink("water", 20);

        System.out.print("Insert money: ");
        int moneyAmount = new Scanner(System.in).nextInt();

        for (Drink i : drinksRange) {
            if (moneyAmount >= i.price) {
                System.out.println("You can buy " + i.name);
            }
        }
    }
}

class Drink {
    String name;
    int price;

    public Drink (String drinkName, int drinkPrice) {
        name = drinkName;
        price = drinkPrice;
        System.out.println(name + " - " + price);
    }
}

Output:

Coffee-machine
cappuccino - 150
espresso - 80
milk - 50
water - 20
Insert money: 200
You can buy cappuccino
You can buy espresso
You can buy milk
You can buy water

static int price this is causing that bug<br>
whenever you write a static keyword it means there's only one copy of it. So the lastest value is picked which in your case is Drink.price = 20
eg.

Line 1    drinksRange[0] = new Drink(Drink.name = "cappuccino", Drink.price = 150)
Line 2    drinksRange[1] = new Drink(Drink.name = "espresso", Drink.price = 80)
Line 3    drinksRange[2] = new Drink(Drink.name = "milk", Drink.price = 50)
Line 4    drinksRange[3] = new Drink(Drink.name = "water", Drink.price = 20)

No doubt this makes an instance of Drink, So line 1 when executed drinksRange[0] has its own space in memory but the members in the class static String name,
static int price have independent memory in heap<br>
so when line 1 is executed name as cappuccino and price as 150<br>
when line 2 is executed name as espresso and price as 80<br>
when Line 3 is executed name as milk and price as 50<br>
when line 4 is executed name as water and price as 20<br>

So in order to have the output, you wanted just remove that static keyword and it will work fine.

The static variable gets memory only once in the class area at the time of class loading.

static String name;
static int price;

In your case you can't put it in your code it will take the last value "water" you have on your array

Put it like this then it will work correctly

String name;
int price;