你能告诉我为什么我会得到一个“字符串无法转换为整数”错误吗?

huangapple go评论62阅读模式
英文:

Can you tell me why I'm getting a "string cannot be converted to int" error

问题

以下是翻译好的部分:

我有一个作业,要求我计算下面代码中的内容。所有内容都正常工作 - 我只需要计算超过160小时的任何月工时,按正常小时费率的1.5倍支付。我的数学似乎是正确的,可以正确计算:

((hours - 160) * overtime) + (160 * hourlyRate)

但我不知道是否应该将这个if语句放在正确的方法中,或者它是否应该是一个if语句。在此之前,我的increase/decreasePay方法是有效的,并且它们需要保留。我删除了一些内容,以便阅读更容易。

HourlyWorker类:

public class HourlyWorker extends Employee {
    private int hours;
    private double hourlyRate;
    private double monthlyPay;
    private double overtime = (1.5 * hourlyRate);

    public HourlyWorker(String last, String first, String ID, double rate) {
        super(last, first, ID);
        hourlyRate = rate;
    }

    public void setHours(int hours) {
        this.hours = hours;
    }

    public int getHours() {
        return hours;
    }

    public void setHourlyRate(double rate) {
        this.hourlyRate = rate;
    }

    public double getHourlyRate() {
        return hourlyRate;
    }

    public double getMonthlyPay() {
        if (hours > 160) {
            monthlyPay = ((hours - 160) * overtime) + (160 * hourlyRate);
        } else {
            monthlyPay = hourlyRate * hours;
        }
        return monthlyPay;
    }

    public void increasePay(double percentage) {
        hourlyRate *= 1 + percentage / 100;
    }

    public void decreasePay(double percentage) {
        hourlyRate *= 1 - percentage / 100;
    }
}

我正在进行测试的部分:

public class TestEmployee2 {
    public static void main(String[] args) {
        Employee[] staff = new Employee[3];
        HourlyWorker hw1 = new HourlyWorker("Bee", "Busy", "BB1265", 10);

        hw1.setHours(200);
        staff[0] = hw1;

        System.out.println(staff[0].getMonthlyPay());
        staff[0].increasePay(10);
        System.out.println(staff[0].getMonthlyPay());
    }
}

输出是:

1600(初始月薪,包括40小时的加班和160小时的普通工时)
1760(月薪增加10%)

应该是:

2006
22
英文:

I have an assignment which asks for everything I have in the code below. That all works fine - I just need to calculate any monthly hours over 160 hours to be paid at 1.5 times the normal hourly rate. My math seems sound and calculates fine:

((hours - 160) * overtime) + (160 * hourlyRate)

But I dont know if I'm putting this if statement in the right method or if it even should be an if statement. My increase/decreasePay methods are working prior to this and they need to stay. I removed some things so it's easier to read.

HourlyWorker Class:

public class HourlyWorker extends Employee
{
private int hours;
private double hourlyRate;
private double monthlyPay;
private double overtime = (1.5 * hourlyRate);

public HourlyWorker(String last, String first, String ID, double rate)
{
   super(last, first, ID);
   hourlyRate = rate;
}

public void setHours(int hours)
{
   this.hours = hours;
}

public int getHours()
{
   return hours;
}

public void setHourlyRate(double rate)
{
   this.hourlyRate = rate;
}

public double getHourlyRate()
{
   return hourlyRate;
}


public double getMonthlyPay()
{
   if (hours > 160)
   {
      monthlyPay = ((hours - 160) * overtime) + (160 * hourlyRate);
   }
   else 
   {
      monthlyPay = hourlyRate * hours;
   }
   return monthlyPay;
}

public void increasePay(double percentage)
{
   hourlyRate *= 1 + percentage / 100;
}

public void decreasePay(double percentage)
{
   hourlyRate *= 1 - percentage / 100;
}

}

What I'm testing with:

public class TestEmployee2
{
   public static void main(String[] args)
   {
   Employee [] staff = new Employee[3];
      HourlyWorker hw1 = new HourlyWorker("Bee", "Busy", "BB1265", 10);
       
      hw1.setHours(200);    
      staff[0] = hw1;

   System.out.println(staff[0].getMonthlyPay());
   staff[0].increasePay(10);
   System.out.println(staff[0].getMonthlyPay());
}
}
Output is:
1600 (initial monthly rate, with 40 overtime hours and 160 regular hours)
1760 (10% increase to the monthlyPay)

Should be:
2006
22

06.6

答案1

得分: 1

正如@NomadMaker提到的,问题出在你的addArtist方法中。
你当前的方法:

public void addArtist(String artistName, String genre)
{
   this.artists.add(artist, genre); 
}

请记住,this.artists是一个可以存储Artist类型对象的列表。因此,你应该使用新参数创建一个新的艺术家对象。类似这样:

public void addArtist(String artist, String genre)
{
   this.artists.add(new Artist(artist, genre)); 
}

正如你可能猜到的,你没有一个接受两个参数(应该接受姓名和流派)的Artist构造函数。因此,你应该将这个构造函数添加到你的代码中:

public Artist(String name, String genre) {
 this.name = name;
 this.genre = genre;
}

错误解释:

artists是一个列表,当调用this.artist.add(artist, genre)时,你实际上在调用属于列表集合的一个方法,该方法具有这样的签名:add(int index, Artist artist)index将是放置艺术家的索引(如果顺序对你很重要的话)。

英文:

As @NomadMaker mentioned, the problem is in your addArtist method.
Your current method:

   public void addArtist(String artistName, String genre)
   {
      this.artists.add(artist, genre); 
   }

Remember that this.artists is a list which can store Objects of type Artist.
Therefore you should create a new artist with the new parameters. Something like:

public void addArtist(String artist, String genre)
   {
      this.artists.add(new Artist(artist, genre)); 
   }

As you might be guessing, you do not have a constructor of Artist with two parameters (should accept name, and genre). Therefore, you should add this constructor to your code:

public Artist(String name, String genre) {
 this.name = name;
 this.genre = genre;
}

Error explanation:

artists is a list, what you are doing when calling this.artist.add(artist, genre) is calling a method which belongs to the list collection that has this signature: add(int index, Artist artist) the index will be the index to place the artist (if the order matters for you).

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  • 本文由 发表于 2020年10月7日 07:24:06
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