你能告诉我为什么我会得到一个“字符串无法转换为整数”错误吗？

huangapple
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英文:

Can you tell me why I'm getting a "string cannot be converted to int" error

问题

以下是翻译好的部分：

我有一个作业，要求我计算下面代码中的内容。所有内容都正常工作 - 我只需要计算超过160小时的任何月工时，按正常小时费率的1.5倍支付。我的数学似乎是正确的，可以正确计算：

((hours - 160) * overtime) + (160 * hourlyRate)

但我不知道是否应该将这个if语句放在正确的方法中，或者它是否应该是一个if语句。在此之前，我的increase/decreasePay方法是有效的，并且它们需要保留。我删除了一些内容，以便阅读更容易。

HourlyWorker类：

  1. public class HourlyWorker extends Employee {
  2.     private int hours;
  3.     private double hourlyRate;
  4.     private double monthlyPay;
  5.     private double overtime = (1.5 * hourlyRate);
  7.     public HourlyWorker(String last, String first, String ID, double rate) {
  8.         super(last, first, ID);
  9.         hourlyRate = rate;
  10.     }
  12.     public void setHours(int hours) {
  13.         this.hours = hours;
  14.     }
  16.     public int getHours() {
  17.         return hours;
  18.     }
  20.     public void setHourlyRate(double rate) {
  21.         this.hourlyRate = rate;
  22.     }
  24.     public double getHourlyRate() {
  25.         return hourlyRate;
  26.     }
  28.     public double getMonthlyPay() {
  29.         if (hours > 160) {
  30.             monthlyPay = ((hours - 160) * overtime) + (160 * hourlyRate);
  31.         } else {
  32.             monthlyPay = hourlyRate * hours;
  33.         }
  34.         return monthlyPay;
  35.     }
  37.     public void increasePay(double percentage) {
  38.         hourlyRate *= 1 + percentage / 100;
  39.     }
  41.     public void decreasePay(double percentage) {
  42.         hourlyRate *= 1 - percentage / 100;
  43.     }
  44. }

我正在进行测试的部分：

  1. public class TestEmployee2 {
  2.     public static void main(String[] args) {
  3.         Employee[] staff = new Employee[3];
  4.         HourlyWorker hw1 = new HourlyWorker("Bee", "Busy", "BB1265", 10);
  6.         hw1.setHours(200);
  7.         staff[0] = hw1;
  9.         System.out.println(staff[0].getMonthlyPay());
  10.         staff[0].increasePay(10);
  11.         System.out.println(staff[0].getMonthlyPay());
  12.     }
  13. }

输出是：

  1. 1600（初始月薪，包括40小时的加班和160小时的普通工时）
  2. 1760（月薪增加10%）

应该是：

  1. 2006
  2. 22
英文:

I have an assignment which asks for everything I have in the code below. That all works fine - I just need to calculate any monthly hours over 160 hours to be paid at 1.5 times the normal hourly rate. My math seems sound and calculates fine:

((hours - 160) * overtime) + (160 * hourlyRate)

But I dont know if I'm putting this if statement in the right method or if it even should be an if statement. My increase/decreasePay methods are working prior to this and they need to stay. I removed some things so it's easier to read.

HourlyWorker Class:

  1. public class HourlyWorker extends Employee
  2. {
  3. private int hours;
  4. private double hourlyRate;
  5. private double monthlyPay;
  6. private double overtime = (1.5 * hourlyRate);
  8. public HourlyWorker(String last, String first, String ID, double rate)
  9. {
  10.    super(last, first, ID);
  11.    hourlyRate = rate;
  12. }
  14. public void setHours(int hours)
  15. {
  16.    this.hours = hours;
  17. }
  19. public int getHours()
  20. {
  21.    return hours;
  22. }
  24. public void setHourlyRate(double rate)
  25. {
  26.    this.hourlyRate = rate;
  27. }
  29. public double getHourlyRate()
  30. {
  31.    return hourlyRate;
  32. }
  35. public double getMonthlyPay()
  36. {
  37.    if (hours > 160)
  38.    {
  39.       monthlyPay = ((hours - 160) * overtime) + (160 * hourlyRate);
  40.    }
  41.    else 
  42.    {
  43.       monthlyPay = hourlyRate * hours;
  44.    }
  45.    return monthlyPay;
  46. }
  48. public void increasePay(double percentage)
  49. {
  50.    hourlyRate *= 1 + percentage / 100;
  51. }
  53. public void decreasePay(double percentage)
  54. {
  55.    hourlyRate *= 1 - percentage / 100;
  56. }
  58. }

What I'm testing with:

  1. public class TestEmployee2
  2. {
  3.    public static void main(String[] args)
  4.    {
  5.    Employee [] staff = new Employee[3];
  6.       HourlyWorker hw1 = new HourlyWorker("Bee", "Busy", "BB1265", 10);
  7.        
  8.       hw1.setHours(200);    
  9.       staff[0] = hw1;
  11.    System.out.println(staff[0].getMonthlyPay());
  12.    staff[0].increasePay(10);
  13.    System.out.println(staff[0].getMonthlyPay());
  14. }
  15. }
  16. Output is:
  17. 1600 (initial monthly rate, with 40 overtime hours and 160 regular hours)
  18. 1760 (10% increase to the monthlyPay)
  20. Should be:
  21. 2006
  22. 22

06.6

答案1

得分: 1

正如@NomadMaker提到的，问题出在你的addArtist方法中。
你当前的方法：

  1. public void addArtist(String artistName, String genre)
  2. {
  3.    this.artists.add(artist, genre); 
  4. }

请记住，this.artists是一个可以存储Artist类型对象的列表。因此，你应该使用新参数创建一个新的艺术家对象。类似这样：

  1. public void addArtist(String artist, String genre)
  2. {
  3.    this.artists.add(new Artist(artist, genre)); 
  4. }

正如你可能猜到的，你没有一个接受两个参数（应该接受姓名和流派）的Artist构造函数。因此，你应该将这个构造函数添加到你的代码中：

  1. public Artist(String name, String genre) {
  2.  this.name = name;
  3.  this.genre = genre;
  4. }

错误解释：

artists是一个列表，当调用this.artist.add(artist, genre)时，你实际上在调用属于列表集合的一个方法，该方法具有这样的签名：add(int index, Artist artist)，index将是放置艺术家的索引（如果顺序对你很重要的话）。

英文:

As @NomadMaker mentioned, the problem is in your addArtist method.
Your current method:

  1.    public void addArtist(String artistName, String genre)
  2.    {
  3.       this.artists.add(artist, genre); 
  4.    }

Remember that this.artists is a list which can store Objects of type Artist.
Therefore you should create a new artist with the new parameters. Something like:

  1. public void addArtist(String artist, String genre)
  2.    {
  3.       this.artists.add(new Artist(artist, genre)); 
  4.    }

As you might be guessing, you do not have a constructor of Artist with two parameters (should accept name, and genre). Therefore, you should add this constructor to your code:

  1. public Artist(String name, String genre) {
  2.  this.name = name;
  3.  this.genre = genre;
  4. }

Error explanation:

artists is a list, what you are doing when calling this.artist.add(artist, genre) is calling a method which belongs to the list collection that has this signature: add(int index, Artist artist) the index will be the index to place the artist (if the order matters for you).

huangapple
  • 本文由 发表于 2020年10月7日 07:24:06
  • 转载请务必保留本文链接：https://go.coder-hub.com/64235096.html
  • java
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