如何将向量的向量存储到Java的二维数组中

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英文:

How can I store vector of vectors into a 2d array in java

问题

以下是翻译好的内容:

在 Java 代码片段中

public class MatrixUsingVectors {

    public static void main(String[] args) {

        Scanner sc = new Scanner(System.in);
        Vector<Vector<Integer>> vec = new Vector<Vector<Integer>>();
        for (int i = 0; i < 3; i++) {
            Vector<Integer> op = new Vector<Integer>(3);
            for (int j = 0; j < 3; j++) {
                op.add(sc.nextInt());
            }
            vec.add(op);
        }
        System.out.println(vec);
        int[][] ar = new int[vec.size()][3];
        vec.copyInto(ar); // 这一行会抛出 ArrayStoreException 异常
        for (int[] c : ar) {
            System.out.println(c);
        }
    }
}
我想将向量 `vec` 的元素存储在名为 `ar` 的二维数组中
我需要帮助解决 `ArrayStoreException` 异常并且想要将 `vec` 的元素存储到 `ar`
请帮忙解决
英文:

The snippet in the java code is here:

public class MatrixUsingVectors {

	public static void main(String[] args) {
	
	Scanner sc= new Scanner(System.in);
	Vector&lt;Vector&lt;Integer&gt; &gt; vec= new Vector&lt;Vector&lt;Integer&gt; &gt;();
	for(int i=0;i&lt;3;i++)
	{
		Vector&lt;Integer&gt; op= new Vector&lt;Integer&gt;(3);
		for(int j=0;j&lt;3;j++)
		{
			op.add(sc.nextInt());
		}
		vec.add(op);
	}
	System.out.println(vec);
	int [][] ar= new int[vec.size()][3];
	vec.copyInto(ar);// this line throws ArrayStoreException
	for(int[] c: ar)
	{
		System.out.println(c);
	}
}
}

I want to store the elements of vector vec in a 2d array named ar.
I need help to deal with ArrayStoreException and want to store the elements of vec into ar.
Please help.

答案1

得分: 0

Vector是1维的。Array也是1维的。Vector.copyInto()方法接受一个i维数组作为参数。

如果你想要将一个Vector的Vectors复制到一个2维Array中,那么你需要通过2个维度来循环进行复制。

所以代码会是这样的:

Object[][] rows = new Object[vec.size()][];

for (int i = 0; i < vec.size(); i++)
{
    Vector<Object> vectorRow = ((Vector)vec.get(i));
    Object[] arrayRow = new Object[vectorRow.size()];
    vectorRow.copyInto(arrayRow);
    rows[i] = arrayRow;
}

我需要帮助处理ArrayStoreException异常

那是一个运行时异常。首先,你需要关注正确的算法来复制数据。然后,如果你想捕获异常,你可以在整个算法中添加try/catch块。

英文:

Vector is 1 dimensional. Array is 1 dimensional. The Vector.copyInto() method takes a i dimensional array as a parameter.

If you want to copy a Vector of Vectors into a 2 Array, then you need to loop through the 2 dimensions to do the copy

So the code would be something like:

Object[][] rows = new Object[vec.size()][];

for (int i = 0; i &lt; vec.size(); i++)
{
    Vector&lt;Object&gt; vectorRow = ((Vector)vec.get(i));
    Object[] arrayRow = new Object[vectorRow.size()];
    vectorRow.copyInto( arrayRow );
    rows[i] = arrayRow;
}

> I need help to deal with ArrayStoreException

That is a run time Exception. First you need to worry about the proper algorithm to copy the data. Then if you want to catch the exception you add a try/catch block to the entire algorithm.

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  • 本文由 发表于 2020年10月6日 22:28:46
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