英文:
Get substring using regex
问题
我有一些字符串，类似于：
- IND_FROM_ONE_TO_FIVE
- IND_FROM_FIVE_TO_TEN
- BS_FROM_ONE_TO_FIVE
- BS_FROM_FIVE_TO_TEN
- OP_FROM_ONE_TO_FIVE
- OP_FROM_FIVE_TO_TEN
我想从它们所有的字符串中剪切掉第一个“_”及其之前的内容，但保留之后的所有内容。
类似于：
- IND_FROM_ONE_TO_FIVE => FROM_ONE_TO_FIVE
- IND_FROM_FIVE_TO_TEN => FROM_FIVE_TO_TEN
- BS_FROM_ONE_TO_FIVE => FROM_ONE_TO_FIVE
- BS_FROM_FIVE_TO_TEN => FROM_FIVE_TO_TEN 等等。
我尝试过 /[^_]*/，但它返回 IND_FROM_ONE_TO_FIVE => _FROM_ONE_TO_FIVE（没有剪切第一个“_”）。
我应该如何在 Java 中实现这个？
英文:
I have some strings Like
1.IND_FROM_ONE_TO_FIVE
2.IND_FROM_FIVE_TO_TEN
3.BS_FROM_ONE_TO_FIVE
4.BS_FROM_FIVE_TO_TEN
5.OP_FROM_ONE_TO_FIVE
6.OP_FROM_FIVE_TO_TEN
And I want to cut from all of them everything before the first "" include ""!!!.
Something like :
1.IND_FROM_ONE_TO_FIVE => FROM_ONE_TO_FIVE
2.IND_FROM_FIVE_TO_TEN => FROM_FIVE_TO_TEN
3.BS_FROM_ONE_TO_FIVE => FROM_ONE_TO_FIVE
4.BS_FROM_FIVE_TO_TEN => FROM_FIVE_TO_TEN etc.
I have tried /[^_]*/ but it returns IND_FROM_ONE_TO_FIVE => _FROM_ONE_TO_FIVE (did not cut first "_")
How could I make it on java?
答案1
得分: 2
你可以在" is" 之前添加锚点，并且也可以匹配下划线。在替换中使用空字符串。
^[^_]*_
使用 replaceFirst 时可以省略锚点：
System.out.println("IND_FROM_ONE_TO_FIVE".replaceFirst("[^_]*_", ""));
输出：
FROM_ONE_TO_FIVE
英文:
You can prepend an anchor and match the underscore after is as well. In the replacement use an empty string.
^[^_]*_
Using replaceFirst you can omit the anchor:
System.out.println("IND_FROM_ONE_TO_FIVE".replaceFirst("[^_]*_", ""));
Output
FROM_ONE_TO_FIVE
答案2
得分: 1
Sure, here's the translated content:
你可以使用捕获组来提取你想要的子字符串。
^[^_]+_(.*)
我还尝试在Java上测试了结果。
import java.util.regex.*;
public class MyClass {
public static void main(String args[]) {
String mydata = "BS_FROM_FIVE_TO_TEN";
Pattern pattern = Pattern.compile("^[^_]+_(.*)");
Matcher matcher = pattern.matcher(mydata);
if (matcher.find())
{
System.out.println(matcher.group(1));
}
}
}
结果
FROM_FIVE_TO_TEN
英文:
You could use a capturing group to extract substring that you want to.
^[^_]+_(.*)
I also tried to test result on Java.
import java.util.regex.*;
public class MyClass {
public static void main(String args[]) {
String mydata = "BS_FROM_FIVE_TO_TEN";
Pattern pattern = Pattern.compile("^[^_]+_(.*)");
Matcher matcher = pattern.matcher(mydata);
if (matcher.find())
{
System.out.println(matcher.group(1));
}
}
}
Result
FROM_FIVE_TO_TEN
答案3
得分: 0
你可以使用匹配而不是替换：从此正则表达式（多行）中获取第一个且唯一的捕获组：^\d+\.[^_]+_(.*)$（https://regex101.com/r/Y3Ztv4/1）。
英文:
You can use matching rather than replacing: take the first and only capture from this regex (multiline): ^\d+\.[^_]+_(.*)$ (https://regex101.com/r/Y3Ztv4/1).
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