算法以创建X个日期

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英文:

Algorithm to create X number of dates

问题

目前我有一个字符串列表,表示以yyyyMM格式表示的日期,类似于这样:

  • 202008
  • 202009
  • 202010

我需要在这个列表中创建x个条目,每个条目的月份增加一,所以如果我要创建3个新条目,它们将如下所示:

  • 202011
  • 202012
  • 202101

目前我的想法是创建一个方法来选择最新的日期,解析字符串以分离月份和年份,如果月份小于12,则将月份值增加1,否则将其设置为1并增加年份。
然后我会将该值添加到列表中,并将其设置为最新的日期,重复x次。

我想知道的是是否有更优雅的解决方案,也许可以使用现有的日期库(我正在使用Java)。

英文:

Currently I have a list of Strings that represent a date in a yyyyMM format, something like this:

  • 202008
  • 202009
  • 202010

I need to create x number of entries in this list with each entry increasing the month by one, so if I were to create 3 new entries they would look like this:

  • 202011
  • 202012
  • 202101

Currently my idea is to create a method to pick the latest date, parse the String to separate month and year, increase the month value by 1 if it is < 12 otherwise set it to 1 and increase the year instead.
Then I would add that value to a list and set it as the most recent, repeating x number of times.

What I want to know is if there is a more elegant solution that I could use, maybe using an existing date library (I'm using Java).

答案1

得分: 2

YearMonthDateTimeFormatter

我建议您按照以下示例使用现代日期时间类来完成:

import java.time.YearMonth;
import java.time.format.DateTimeFormatter;
import java.util.ArrayList;
import java.util.List;

public class Main {
    public static void main(String[] args) {
        // 测试
        List<String> list = getYearMonths("202011", 3);
        System.out.println(list);

        // 奖励:在新行中打印获得列表的每个条目
        list.forEach(System.out::println);
    }

    public static List<String> getYearMonths(String startWith, int n) {
        List<String> list = new ArrayList<>();

        // 定义格式化器
        DateTimeFormatter formatter = DateTimeFormatter.ofPattern("uuuuMM");

        // 使用定义的格式化器解析年月字符串
        YearMonth ym = YearMonth.parse(startWith, formatter);

        for (int i = 1; i <= n; i++) {
            list.add(ym.format(formatter));
            ym = ym.plusMonths(1); // 增加一个月的YearMonth
        }
        return list;
    }
}

输出:

[202011, 202012, 202101]
202011
202012
202101

在**日期时间教程**中了解更多关于现代日期时间 API 的内容。

英文:

YearMonth And DateTimeFormatter

I recommend you do it using these modern date-time classes as shown below:

import java.time.YearMonth;
import java.time.format.DateTimeFormatter;
import java.util.ArrayList;
import java.util.List;

public class Main {
	public static void main(String[] args) {
		// Test
		List&lt;String&gt; list = getYearMonths(&quot;202011&quot;, 3);
		System.out.println(list);

		// Bonus: Print each entry of the obtained list, in a new line
		list.forEach(System.out::println);
	}

	public static List&lt;String&gt; getYearMonths(String startWith, int n) {
		List&lt;String&gt; list = new ArrayList&lt;&gt;();

		// Define Formatter
		DateTimeFormatter formatter = DateTimeFormatter.ofPattern(&quot;uuuuMM&quot;);

		// Parse the year-month string using the defined formatter
		YearMonth ym = YearMonth.parse(startWith, formatter);

		for (int i = 1; i &lt;= n; i++) {
			list.add(ym.format(formatter));
			ym = ym.plusMonths(1);// Increase YearMonth by one month
		}
		return list;
	}
}

Output:

[202011, 202012, 202101]
202011
202012
202101

Learn more about the modern date-time API at Trail: Date Time.

答案2

得分: 2

使用正确的日期时间对象:YearMonth

不要将日期存储为字符串在你的列表中。就像你使用 int 表示数字和 boolean 表示布尔值一样(我希望是这样的!),对于日期和时间,请使用正确的日期时间对象。在你的用例中,YearMonth 类是合适的选择。

就像将 int 格式化为带有千位分隔符或不带千位分隔符的格式,将 boolean 格式化为“是”或“否”一样,将你的 YearMonth 对象格式化为字符串也是微不足道的。所以在需要字符串时再进行格式化,而不是之前。

一个用于扩展 YearMonth 对象列表的方法如下:

public static void extendDateList(List<YearMonth> dates, int numberOfNewDates) {
    if (dates.isEmpty()) {
        throw new IllegalArgumentException("List is empty; don’t know where to pick up");
        // 或者可以从某个固定日期或当前月份开始
    } else {
        YearMonth current = Collections.max(dates);
        for (int i = 0; i < numberOfNewDates; i++) {
            current = current.plusMonths(1);
            dates.add(current);
        }
    }
}

让我们来试一试:

List<YearMonth> dates = new ArrayList<YearMonth>(List.of(
    YearMonth.of(2020, Month.AUGUST), 
    YearMonth.of(2020, Month.SEPTEMBER),
    YearMonth.of(2020, Month.OCTOBER)));

extendDateList(dates, 3);

System.out.println(dates);

输出结果是:

[2020-08, 2020-09, 2020-10, 2020-11, 2020-12, 2021-01]

格式化为字符串

我向你保证,你可以轻松地得到你想要的字符串。我建议使用上面显示的带有连字符的格式,原因有两点:(1)更易读,(2)它是 ISO 8601 格式,国际标准。无论如何,为了证明你可以得到你想要的格式,我使用格式化程序产生了无连字符格式的示例:

private static final DateTimeFormatter YEAR_MONTH_FORMATTER
        = DateTimeFormatter.ofPattern("uuuuMM");

现在将其转换为字符串列表只需要一行代码(如果你的编辑窗口足够宽):

List<String> datesAsStrings = dates.stream()
        .map(YEAR_MONTH_FORMATTER::format)
        .collect(Collectors.toList());
System.out.println(datesAsStrings);

输出结果是:

[202008, 202009, 202010, 202011, 202012, 202101]

链接

英文:

Use proper date-time objects: YearMonth

Don’t store your dates as strings in your list. Just as you use int for numbers and boolean for Boolean values (I hope!), use proper date-time objects for dates and times. For your use case the YearMonth class is appropriate.

And just as it’s easy to format an int into a format with or without thousand separators and a boolean into yes or no, for example, formatting your YearMonth objects into strings is trivial. So do that when you need a string, not before.

A method for extending such a list of YearMonth objects would be:

public static void extendDateList(List&lt;YearMonth&gt; dates, int numberOfNewDates) {
	if (dates.isEmpty()) {
		throw new IllegalArgumentException(&quot;List is empty; don’t know where to pick up&quot;);
		// Or may start from some fixed date or current month
	} else {
		YearMonth current = Collections.max(dates);
		for (int i = 0; i &lt; numberOfNewDates; i++) {
			current = current.plusMonths(1);
			dates.add(current);
		}
	}
}

Let’s try it out:

	List&lt;YearMonth&gt; dates = new ArrayList&lt;YearMonth&gt;(List.of(
			YearMonth.of(2020, Month.AUGUST), 
			YearMonth.of(2020, Month.SEPTEMBER),
			YearMonth.of(2020, Month.OCTOBER)));
	
	extendDateList(dates, 3);
	
	System.out.println(dates);

Output is:

> [2020-08, 2020-09, 2020-10, 2020-11, 2020-12, 2021-01]

Formatting into strings

I promised you you could easily have your strings. I would suggest using the format with a hyphen printed above for two reasons: (1) it’s more readable, and (2) it’s ISO 8601 format, the international standard. In any case, to demonstrate that you can have it just the way you want, I am using a formatter to produce the hyphen-less format that you used:

private static final DateTimeFormatter YEAR_MONTH_FORMATTER
		= DateTimeFormatter.ofPattern(&quot;uuuuMM&quot;);

Now converting to a list of strings is a one-liner (if your editor window is wide enough):

	List&lt;String&gt; datesAsStrings = dates.stream()
			.map(YEAR_MONTH_FORMATTER::format)
			.collect(Collectors.toList());
	System.out.println(datesAsStrings);

> [202008, 202009, 202010, 202011, 202012, 202101]

答案3

得分: 0

public static String[] addMonthsToDateString(String startDate, int monthsToAdd) {
    int year = Integer.valueOf(startDate.substring(0, 4));
    int month = Integer.valueOf(startDate.substring(4));
    int loopCount = ((month + monthsToAdd) - month);
    String[] stringDates = new String[loopCount];
    
    for (int i = 0; i < loopCount; i++) {
        stringDates[i] = new StringBuilder("").append(year)
                         .append(String.format("%02d", month)).toString();
        month++;
        if (month == 13) {
            year++;
            month = 1;
        }
    }
    return stringDates;
}

// Usage example:
String[] desiredDates = addMonthsToDateString("202008", 24);

for (String strg : desiredDates) {
    System.out.println(strg);
}

Console Output:

202008
202009
202010
202011
202012
202101
202102
202103
202104
202105
202106
202107
202108
202109
202110
202111
202112
202201
202202
202203
202204
202205
202206
202207
英文:

Since you're just dealing with strings you could just create a method to produce the string dates for you and return all those string dates in a String Array, like this:

public static String[] addMonthsToDateString(String startDate, int monthsToAdd) {
    // Break the string date down to integers Year and month.
    int year = Integer.valueOf(startDate.substring(0, 4));
    int month = Integer.valueOf(startDate.substring(4));
    // Calculate the number of iterations we need.
    int loopCount = ((month + monthsToAdd) - month);
    // Declare and initialize the String Array we will return.
    String[] stringDates = new String[loopCount];
    
    // Generate the required Date Strings
    for (int i = 0; i &lt; loopCount; i++) {
        stringDates[i] = new StringBuilder(&quot;&quot;).append(year)
                         .append(String.format(&quot;%02d&quot;, month)).toString();
        month++;
        if (month == 13) {
            year++;
            month = 1;
        }
    }
    return stringDates;
}

To use this method you would need to supply a string start date ("202008") and the integer number of months you want to list (24):

// Get the desired list of string dates:
String[] desiredDates = addMonthsToDateString(&quot;202008&quot;, 24);

// Display the string dates produced into the Console Window:
for (String strg : desiredDates) {
    System.out.println(strg);
}

The Console Window will display:

202008
202009
202010
202011
202012
202101
202102
202103
202104
202105
202106
202107
202108
202109
202110
202111
202112
202201
202202
202203
202204
202205
202206
202207

huangapple
  • 本文由 发表于 2020年10月6日 04:52:55
  • 转载请务必保留本文链接:https://go.coder-hub.com/64216046.html
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