英文:
For loop for progressively adding string padding?
问题
所以我对Java还不太熟悉，如果这个问题不好请原谅。
我尝试使用for循环来根据用户输入的值（在这种情况下为8）连续添加填充到一个字符串（在本例中为“*”）。因此，当输入为8时，会得到以下结果：
* --> 没有填充
* --> printf("%2s", "*");
* --> printf("%3s", "*");
* --> 等等。
*
*
*
* --> 最后会以输入值减1的偏移结束，所以在这个例子中是7。
除了逐个编写每个语句外，我不知道如何做到这一点，但这样就不是使用for循环了。这需要手动更改格式化的字符串，对吗？不能自动完成吗？
英文:
So im pretty new to java, sorry if this is a bad question.
Im trying to use a for loop to continuously add padding to a string (in this case “*”), dependent on a user inputted value. So an 8 would give me:
* --> no padding
* --> printf("%2s", "*");
* --> printf("%3s", "*");
* --> etc.
*
*
*
* --> ending with the input -1 offset, so 7 in this case.
I don't know how to do this other than writing each statement out, but then its not using a for loop.This requires manual changing of the formatted string right?, not something that can be automatic?.
答案1
得分: 1
可以按以下方式动态创建格式：
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("您想要多少填充：");
int padding = Integer.parseInt(scanner.nextLine());
System.out.printf("%" + padding + "s%n", "*");
// 使用此技巧的模式
for (int i = 1; i <= 10; i++) {
System.out.printf("%" + i + "s%n", "*");
}
}
}
**一个示例运行：**
您想要多少填充：8
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
英文:
You can create the format dynamically as shown below:
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("How much padding do you want: ");
int padding = Integer.parseInt(scanner.nextLine());
System.out.printf("%" + padding + "s%n", "*");
// A pattern using this trick
for (int i = 1; i <= 10; i++) {
System.out.printf("%" + i + "s%n", "*");
}
}
}
A sample run:
How much padding do you want: 8
*
*
*
*
*
*
*
*
*
*
*
答案2
得分: 0
public class Main{
public static void main(String[] args) {
for (int i=0; i<10; i++) {
IntStream.range(0, i).forEach((c)->System.out.print(" "));
System.out.println("*");
}
}
}
英文:
You could use:
public class Main{
public static void main(String[] args) {
for (int i=0; i<10; i++) {
IntStream.range(0, i).forEach((c)->System.out.print(" "));
System.out.println("*");
}
}
}
Per each i, you are printing the i times empty strings padding, postfixed by *.
Change the characters (" " or *) with whatever you wish.
答案3
得分: 0
"The "no padding" can be done using printf("%1s", "*").
Now look at the first parameter to printf in all the calls. It's just a string, with an incrementing number from 1 to 8. So build that string using string-concatenation:
printf("%" + i + "s", "*") // if i is 1 to 8
printf("%" + (i + 1) + "s", "*") // if i is 0 to 7
英文:
The "no padding" can be done using printf("%1s", "*").
Now look at the first parameter to printf in all the calls. It's just a string, with an incrementing number from 1 to 8. So build that string using string-concatenation:
printf("%" + i + "s", "*") // if i is 1 to 8
printf("%" + (i + 1) + "s", "*") // if i is 0 to 7
答案4
得分: 0
请尝试这个。
for (int i = 0; i < 8; ++i)
System.out.println(" ".repeat(i) + "*");
输出结果：
*
*
*
*
*
*
*
*
英文:
Try this.
for (int i = 0; i < 8; ++i)
System.out.println(" ".repeat(i) + "*");
output
*
*
*
*
*
*
*
*
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论