英文:
Vigenere Cipher Algorithm In Java - Decrypted Message to Plaintext
问题
import java.util.Scanner;
public class VigenereCipher {
public static void main(String arg[]) {
String message = "";
String keyword = "KISWAHILI";
Scanner sc = new Scanner(System.in);
System.out.println("Enter a message: ");
message = sc.nextLine();
char msg[] = message.toCharArray();
int msgLength = msg.length;
char key[] = new char[msgLength];
char decryptedText[] = new char[msgLength];
for (int i = 0, j = 0; i < msgLength; i++, j++) {
if (j == keyword.length()) {
j = 0;
}
key[i] = keyword.charAt(j);
}
// Decryption Code
for (int i = 0; i < msgLength; i++) {
decryptedText[i] = (char) (((msg[i] - key[i] + 26) % 26) + 'A');
}
System.out.println("Decrypted Message: " + String.valueOf(decryptedText));
System.out.println("Keyword: " + keyword);
System.out.println("Plaintext: " + String.valueOf(decryptedText));
}
}
英文:
I am currently trying to write the Vigenere Cipher algorithm in Java. I have to change the decrypted message to the plaintext but having trouble. Below is what I have so far.
When I run it, the message is not deciphered properly.
import java.util.Scanner;
public class VigenereCipher {
public static void main(String arg[]) {
String message = "";
String keyword = "KISWAHILI";
Scanner sc = new Scanner(System.in);
System.out.println("Enter a message: ");
message = sc.nextLine();
char msg[] = message.toCharArray();
int msgLength = msg.length;
char key[] = new char [msgLength];
char decryptedText[] = new char[msgLength];
for(int i = 0, j = 0; i < msgLength; i++, j++) {
if(j == keyword.length()) {
j = 0;
}
key[i] = keyword.charAt(j);
}
// Decryption Code
for(int i =0; i < msgLength; i++) {
decryptedText[i] = (char)(((key[i] + 26) % 26) + 'A');
}
System.out.println("Decrypted Message: " + message);
System.out.println("Keyword: " + keyword);
System.out.println("Plaintext: " + String.valueOf(decryptedText));
}
}
答案1
得分: 1
代码部分已翻译如下:
似乎在填充key
数组时需要跳过空格:
for (int i = 0, j = 0; i < msgLength; i++) {
if (msg[i] == ' ') {
key[i] = ' ';
} else {
key[i] = keyword.charAt(j++ % keyword.length());
}
}
System.out.println("关键消息: " + new String(key));
类似地,在解密循环中也需要考虑空格。并且解密需要进行修复:
for (int i = 0; i < msgLength; i++) {
char c = msg[i];
decryptedText[i] = c == ' ' ? c : (char)(((msg[i] - key[i] + 26) % 26) + 'A');
}
应用这些更改后,输出如下所示:
关键消息: KISW AH ILIKI SW AHILIKIS WAH ILI KISW AHILIKISW AHIL IKIS
加密消息: XQKP IZ IMWEB LK AUVZCXKW PHL VPE RIKD ASOZZSBZI TOIE ESTD
关键词: KISWAHILI
明文: NIST IS ABOUT TO ANNOUNCE THE NEW HASH ALGORITHM THAT WILL
英文:
It seems that whitespaces need to be skipped while populating key
array:
for (int i = 0, j = 0; i < msgLength; i++) {
if (msg[i] == ' ') {
key[i] = ' ';
} else {
key[i] = keyword.charAt(j++ % keyword.length());
}
}
System.out.println("Key Message: " + new String(key));
Similarly, it needs to be taken into account in the decrypting loop.
And decryption has to be fixed:<br/>
D<sub>i</sub> = (M<sub>i</sub> - K<sub>i</sub> + 26 ) mod 26
for (int i =0; i < msgLength; i++) {
char c = msg[i];
decryptedText[i] = c == ' ' ? c : (char)(((msg[i] - key[i] + 26) % 26) + 'A');
}
Upon applying these changes, the output is as follows:
Key Message: KISW AH ILIKI SW AHILIKIS WAH ILI KISW AHILIKISW AHIL IKIS
Encrypted Message: XQKP IZ IMWEB LK AUVZCXKW PHL VPE RIKD ASOZZSBZI TOIE ESTD
Keyword: KISWAHILI
Plaintext: NIST IS ABOUT TO ANNOUNCE THE NEW HASH ALGORITHM THAT WILL
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