英文:
How do I resolve this error using Paths.of?
问题
我尝试了许多提供的示例，但都没有成功。以下是我目前尝试的代码，在Eclipse中出现了错误，指出Paths.of（of的部分被红色下划线标出）处需要重命名。
String content;
try {
content = Files.readAllLines(Paths.of("C:", "Calcs.txt"));
} catch (IOException e1) {
e1.printStackTrace();
}
System.out.println(content);
英文:
I have been trying many of the examples provided and have yet to be successful. Here is the code I am currently trying, but getting an error in Eclipse on Paths.of (the of is underlined in red) that says: "rename in file".
String content;
try {
content = Files.readAllLines(Paths.of("C:", "Calcs.txt"));
} catch (IOException e1) {
e1.printStackTrace ();
}
System.out.println (content);
答案1
得分: 1
首先，如果返回类型是列表，是不可能将其赋值给字符串的。因此你必须这样写：
List<String> content;
其次，根据Java 8文档，该类中没有可用的of方法。你可以像这样使用get方法：
List<String> content = Files.readAllLines(Paths.get("C:", "Calcs.txt"));
另外，自Java 11起，Path类中存在一个method of。因此，你可以这样写：
List<String> content = Files.readAllLines(Path.of("C:", "Calcs.txt"));
英文:
First it is not possible, if you get a list as return type, to assign this to a string. So you must write:
List<String> content;
Second regarding to the Java 8 documentation there is no method of available for this class. You can use the method get like this:
List<String> content = Files.readAllLines(Paths.get("C:", "Calcs.txt"));
Otherwise there exists a method of in the Path class since Java 11. Therefore you can write something like that:
List<String> content = Files.readAllLines(Path.of("C:", "Calcs.txt"));
答案2
得分: 0
你可能正在寻找 Paths.get 方法：
String content;
try {
content = String.join("\n", Files.readAllLines(Paths.get("/home/hassan", "Foo.java")));
} catch (IOException e1) {
e1.printStackTrace();
}
英文:
You're probably looking for Paths.get:
String content;
try {
content = String.join("\n", Files.readAllLines(Paths.get("/home/hassan", "Foo.java")));
} catch (IOException e1) {
e1.printStackTrace ();
}
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