用输入的数字创建一个星号组成的正方形。

huangapple
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英文:

Create a Square of stars with an inputed number

问题

  1. System.out.print("请输入一个数字：");
  2. side = input.nextInt();
  3. for (int i = 0; i < side; i++) {
  4.     System.out.print("* ");
  5. }
  6. System.out.println();  // 换行
  8. for (int i = 0; i < side - 2; i++) {
  9.     System.out.print("* ");  // 左边的星号
  10.     for (int j = 0; j < side - 2; j++) {
  11.         System.out.print("  ");  // 中间的空格
  12.     }
  13.     System.out.println("* ");  // 右边的星号并换行
  14. }
  16. for (int i = 0; i < side; i++) {
  17.     System.out.print("* ");
  18. }

输入:

  1. 5

输出:

  1. * * * * * 
  2. *       * 
  3. *       * 
  4. *       * 
  5. * * * * *

你的代码存在问题，主要是在打印内部空心部分时没有正确的处理。上面给出的代码在输出上述所需的空心正方形方面是正确的。

英文:

I need a code to help me print a square of stars with an Integer input (in this case the number is 5)
the square must be empty on the inside.

for example:

Looking for this output

  1. * * * * *
  2. *       *
  3. *       *
  4. *       *
  5. * * * * *

what I get

  1. * * * * 
  2. *       
  3. *      
  4. *       
  5. * * * *

I am missing my right side of the square.

MY code:

  1. 	System.out.print(&quot;Please enter a number: &quot;);
  2. 	side = input.nextInt();
  3. 	for (int i = 0; i &lt; side - 1; i++) {
  4. 		System.out.print(&quot;* &quot;);
  6. 	}
  7. 	for (int i = 0; i &lt; side; i++) {
  8. 		System.out.println(&quot;*&quot;);
  9. 	}
  10. 		
  11. 	for (int i = 0; i &lt; side; i++) {
  12. 		System.out.print(&quot;* &quot;);
  14. 	}
  16. }

input

5

output

  1. * * * * 
  2. *       
  3. *      
  4. *       
  5. * * * *

答案1

得分: 1

你可以使用嵌套的 for 循环来实现这个。

  1. for (int i = 0; i < side; i++) {
  2.     for (int j = 0; j < side; j++) {
  3.         if (i == 0 || i == side - 1 || j == 0 || j == side - 1) {
  4.             System.out.print("* ");
  5.         } else {
  6.             System.out.print("  ");
  7.         }
  8.     }
  9.     System.out.println();
  10. }

如果是第一行/列或者最后一行/列，打印 * ；否则打印两个空格。

英文:

You can do this with a nested for loop.

  1. for (int i = 0; i &lt; side; i++) {
  2.     for (int j = 0; j &lt; side; j++) {
  3.         if (i == 0 || i == side - 1 || j == 0 || j == side - 1) {
  4.             System.out.print(&quot;* &quot;);
  5.         } else {
  6.             System.out.print(&quot;  &quot;);
  7.         }
  8.     }
  9.     System.out.println();
  10. }

Print a * if it is either first row/column or last row/column; otherwise print two spaces.

答案2

得分: 1

  1. 使用一个时间复杂度为O(n)的单个For循环可以完成。
  3. public static void main(String[] args) {
  4.     System.out.print("请输入一个数字：");
  5.     Scanner scanner = new Scanner(System.in);
  6.     int number = scanner.nextInt();
  7.     if (number >= 3) {
  8.         String endPattern = new String(new char[number]).replace("
    使用一个时间复杂度为O(n)的单个For循环可以完成。
  10. public static void main(String[] args) {
  11.     System.out.print("请输入一个数字：");
  12.     Scanner scanner = new Scanner(System.in);
  13.     int number = scanner.nextInt();
  14.     if (number >= 3) {
  15.         String endPattern = new String(new char[number]).replace("\0", " *");
  16.         String midPattern = String.format("%-" + (number - 2) * 2 + "s  %s", " *", " *");
  18.         for (int i = 1; i <= number; i++) {
  19.             if (i == 1 || i == number) {
  20.                 System.out.print(endPattern);
  21.             } else {
  22.                 System.out.print(midPattern);
  23.             }
  24.             System.out.println();
  25.         }
  26.     }
  27. }
  28. ", " *");
  29.         String midPattern = String.format("%-" + (number - 2) * 2 + "s  %s", " *", " *");
  31.         for (int i = 1; i <= number; i++) {
  32.             if (i == 1 || i == number) {
  33.                 System.out.print(endPattern);
  34.             } else {
  35.                 System.out.print(midPattern);
  36.             }
  37.             System.out.println();
  38.         }
  39.     }
  40. }

输出（输入为3）

  1. 请输入一个数字：3
  2.  * * *
  3.  *   *
  4.  * * *

输出（输入为7）

  1. 请输入一个数字：7
  2.  * * * * * * *
  3.  *           *
  4.  *           *
  5.  *           *
  6.  *           *
  7.  *           *
  8.  * * * * * * *
  2. <details>
  3. <summary>英文:</summary>
  5. **It can be done using a single For Loop with a Complexity of O(n)**
  7. 	public static void main(String[] args) {
  8. 		System.out.print(&quot;Please Enter a Number &quot;);
  9. 		Scanner scanner = new Scanner(System.in);
  10. 		int number = scanner.nextInt();
  11. 		if(number &gt;= 3) {
  12. 			String endPattern = new String(new char[number]).replace(&quot;
  13. <details>
  14. <summary>英文:</summary>
  15. **It can be done using a single For Loop with a Complexity of O(n)**
  16. public static void main(String[] args) {
  17. System.out.print(&quot;Please Enter a Number &quot;);
  18. Scanner scanner = new Scanner(System.in);
  19. int number = scanner.nextInt();
  20. if(number &gt;= 3) {
  21. String endPattern = new String(new char[number]).replace(&quot;\0&quot;, &quot; *&quot;);
  22. String midPattern = String.format(&quot;%-&quot;+(number-2)*2+&quot;s  %s&quot;, &quot; *&quot;,&quot; *&quot;);
  23. for(int i=1; i&lt;= number; i++) {
  24. if(i==1 || i==number) {				
  25. System.out.print(endPattern);
  26. }
  27. else {
  28. System.out.print(midPattern);
  29. }
  30. System.out.println();
  31. }
  32. }
  33. }
  34. **Output (for input 3)**
  35. Please Enter a Number 3
  36. * * *
  37. *   *
  38. * * *
  39. **output (for input 7)**
  40. Please Enter a Number 7
  41. * * * * * * *
  42. *           *
  43. *           *
  44. *           *
  45. *           *
  46. *           *
  47. * * * * * * *
  48. </details>
  49. # 答案3
  50. **得分**: 0
  51. 你需要在中间的for循环结束后再添加一个额外的星号。可以通过嵌套第二个空格的for循环，然后打印星号来实现。
  52. ```java
  53. for (int i = 0; i < side; i++) {
  54. System.out.print("*");
  55. for (int j = 0; j < side; j++) {
  56. System.out.print("  ");
  57. }
  58. System.out.println("*");
  59. }
  60. &quot;, &quot; *&quot;);
  61. 			String midPattern = String.format(&quot;%-&quot;+(number-2)*2+&quot;s  %s&quot;, &quot; *&quot;,&quot; *&quot;);
  62. 			
  63. 			for(int i=1; i&lt;= number; i++) {
  64. 				if(i==1 || i==number) {				
  65. 					System.out.print(endPattern);
  66. 				}
  67. 				else {
  68. 					System.out.print(midPattern);
  69. 				}
  70. 				System.out.println();
  71. 			}
  72. 		}
  73. 	}
  75. **Output (for input 3)**
  77.     Please Enter a Number 3
  78.      * * *
  79.      *   *
  80.      * * *
  82. **output (for input 7)**
  84.     Please Enter a Number 7
  85.      * * * * * * *
  86.      *           *
  87.      *           *
  88.      *           *
  89.      *           *
  90.      *           *
  91.      * * * * * * *
  93. </details>
  97. # 答案3
  98. **得分**: 0
  100. 你需要在中间的for循环结束后再添加一个额外的星号。可以通过嵌套第二个空格的for循环，然后打印星号来实现。
  102. ```java
  103. for (int i = 0; i < side; i++) {
  104.     System.out.print("*");
  105.     for (int j = 0; j < side; j++) {
  106.         System.out.print("  ");
  107.     }
  108.     System.out.println("*");
  109. }
英文:

You need to add an extra star at the end of the middle for loop. This can be done by nested a second for loop of spaces followed by printing the star.

  1. for (int i = 0; i &lt; side; i++) {
  2.     System.out.print(&quot;*&quot;);
  3.     for (int j = 0; j &lt; side; j++) {
  4.         System.out.print(&quot;  &quot;);
  5.     }
  6.     System.out.println(&quot;*&quot;);
  7. }

huangapple
  • 本文由 发表于 2020年10月3日 02:33:05
  • 转载请务必保留本文链接：https://go.coder-hub.com/64176635.html
  • for-loop
  • java
  • loops
  • printing
  • square
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