排序二维整数数组 Java

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英文:

Sorting 2d Integers Array Java

问题

我有一个2D数组,大小为[2][10]。它被填充了随机数字。
请问有人可以帮助我如何对其进行排序吗?不知道为什么,但任何找到的使用Comparator来排序的方法都不适用于我。所以我正在尝试使用循环来排序它。它必须按列排序。

我试图创建一个临时数组并将值插入其中,但我不知道如何比较[0][0]和[0][1]的值。
我的尝试是使用两个for循环,并在其中进行比较:

for (int i = 0; i < arr4.length; i++) {
    for(int j = 0; j < arr4[i].length; j++) {
        if(arr4[i][j] > ???????)
            temparray = arr4[i][j];
    }
}

请帮帮我...

英文:

i have an 2d Array which is [2][10]. It is filled with random numbers.
Could someone please help me how to sort it? I dont know why but any found way to sort it with Comparator doesnt work for me. So im trying to do that in a loop. It has to be sorted by the column.

Im trying to play with creating a temporary array and inserting the value into it, but i dont know how to compare values: [0][0] and [0][1].
My try is do 2 for loops and inside it:

for (int i = 0; i < arr4.length; i++) {
    for(int j = 0; j < arr4[i].length; j++) {
        if(arr4[i][j] > ???????)
            temparray = arr4[i][j];
    }
}

Help me please...

答案1

得分: 1

  // 如果需要逐行排序,您需要按以下方式更新您的解决方案

  for (int i = 0; i < arr4.length; i++) {
        for(int j = 0; j < arr4[i].length-1; j++) {
            if(arr4[i][j] > arr4[i][j+1]){
              temparray = arr4[i][j];
              arr4[i][j] = arr4[i][j+1]
              arr4[i][j+1] = temparray  ;
              j=0;
          }
        }
     }

输入:

[1.0, 2.0]
[6.0, 4.0]
[5.0, 4.0]

输出:

[1.0, 2.0]
[4.0, 6.0]
[4.0, 5.0]
英文:

if you need to sort line by line you need to update your solution like this

  for (int i = 0; i &lt; arr4.length; i++) {
        for(int j = 0; j &lt; arr4[i].length-1; j++) {
            if(arr4[i][j] &gt; arr4[i][j+1]){
              temparray = arr4[i][j];
              arr4[i][j] = arr4[i][j+1]
              arr4[i][j+1] = temparray  ;
              j=0;
          }
        }
     }


input:
[1.0, 2.0]
[6.0, 4.0]
[5.0, 4.0]

output:

[1.0, 2.0]
[4.0, 6.0]
[4.0, 5.0]

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  • 本文由 发表于 2020年10月1日 23:52:32
  • 转载请务必保留本文链接:https://go.coder-hub.com/64158942.html
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