将一个具有两个单独字符串的对象添加到Java的ArrayList中。

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英文:

Adding an object that has two separate Strings to an ArrayList in Java

问题

我已经做了一些谷歌搜索并阅读了我的文本,但似乎只能找到如何将单个字符串添加到ArrayList元素中,例如:arrayList.add("添加这个新字符串");

因为每个元素都是一个对象,我需要在每个元素中存储两个字符串。例如,我有一个包含以下内容的txt文件:

在Java中编程:ITC206
IT Helpdesk:ITC232
网络伦理:ITC311

当我读取文件并将其添加到ArrayList中时,它告诉我列表中有3个元素,每行一个,每行包含两个字符串。

当我尝试添加新行时,我似乎无法添加两个单独的字符串,一个用于课程名称,一个用于课程代码。

我已经尝试过手动添加,即arrayList.add("IT", "ITC000");,但它会认为我试图指定元素,并告诉我无法将字符串("IT")转换为整数。

以下是我编写的代码。所有的代码都可以正常工作,直到我执行subjectList.add以将新行/元素添加到列表中。

public static void main(String[] args) {
    // 创建数组列表
    ArrayList<String> subjectList = new ArrayList<>();
    Scanner input = new Scanner(System.in); // 导入扫描仪
    
    // 从Subjects列表txt文件读取对象
    try (BufferedReader list = new BufferedReader (new FileReader("ListofSubjects.txt"))) {
        String listLine;
        while ((listLine = list.readLine()) != null) {
            subjectList.add(listLine);
        }
    } catch (IOException e) { // 捕获任何异常
    }
    
    // 获取新的学科名称和代码
    System.out.println("输入您的新学科名称:");
    String name = input.nextLine();
    System.out.println("输入您的新学科代码:");
    String code = input.nextLine();
    
    // 使用Subject类中的两个字符串参数构造Subject
    Subject newSubject = new Subject(name, code);
    
    subjectList.add(newSubject);
    // 我希望该元素包含名称和代码
    //与列表的其他行一样,但是出现错误
    
    System.out.println("列表大小? " + subjectList.size());
    System.out.println("列表现在有: " + subjectList.toString());

}

也许我不需要单独添加它们,但是我需要能够单独检查学科名称和代码,因此我认为如果它们是元素中的单独字符串,这将更容易实现。

英文:

I have done some googling and read through my texts but I can only seem to find how to add a single string to an element of an arrayList i.e. arrayList.add("adding this new string");

as each element is an object, I need to store two strings in each element.
For example I have a txt file with the below already stored:

> Programming in Java: ITC206
> IT Helpdesk: ITC232
> Cyber Ethics: ITC311

When I read the file and add it to an ArrayList it tells me I have 3 elements in the list, one for each line, each line consisting of two strings.

When I try and add a new line in, I can't seem to add two separate strings, one for the course name and one for the course code.

I have tried this manually i.e. arrayList.add(&quot;IT&quot;, &quot;ITC000&quot;); but it assumes I am trying to specify the element and tells me I can't convert the string ("IT") to an int.

below is the code I have written. all works fine until I hit the subjectList.add to add the new line/element to the list.

 public static void main(String[] args) {
    // create array list        
    ArrayList&lt;String&gt; subjectList = new ArrayList&lt;&gt;();
    Scanner input = new Scanner(System.in); // inport scanner
    
    //read objects from List of Subjects txt file
    try (BufferedReader list = new BufferedReader (new FileReader(&quot;ListofSubjects.txt&quot;))) {
        String listLine;
        while ((listLine = list.readLine()) != null) {
            subjectList.add(listLine);
        }
    } catch (IOException e) { // catch any exceptions 
    }
    
    //get new subject name and code 
    System.out.println(&quot;Enter the name of your new Subject: &quot;);
    String name = input.nextLine();
    System.out.println(&quot;Enter the code for your new Subject: &quot;);
    String code = input.nextLine();
    
    //Subject constructor with two string arg from Subject class
    Subject newSubject = new Subject(name, code);
    
    subjectList.add(newSubject); 
    // I want the element to hold both the name and code
    //like the other lines of the list but get error
    
       
    System.out.println(&quot;List Size? &quot; + subjectList.size());
    System.out.println(&quot;the list now has: &quot; + subjectList.toString());

}

Maybe I don't need to add these separately, however I need to be able to check the subject name, and the code separately, so figured this would be easier done if they are separate strings in the element.

答案1

得分: 0

你可以分别添加两个属性。

subjectList.add(newSubject.getName());
subjectList.add(newSubject.getCode());

或者如果你需要在一次调用中完成:

list.addAll(Arrays.asList(newSubject.getName(), newSubject.getCode()));

你也可以尝试仅为Subject对象创建一个List,但在需要改变方法以添加你的listLines时,需要改变你的方法。

List<Subject> subjectList = new ArrayList<>();
Scanner input = new Scanner(System.in); // 导入扫描器

// 从Subjects txt文件的列表中读取对象
try (BufferedReader list = new BufferedReader(new FileReader("ListofSubjects.txt"))) {
    String listLine;
    while ((listLine = list.readLine()) != null) {
        Subject subject = new Subject();
        subject.setName(listLine); // 或者setCode()
        subjectList.add(subject);
    }
} catch (IOException e) { // 捕获任何异常
}
英文:

You can add both attributes seperatly.

subjectList.add(newSubject.getName()); 
subjectList.add(newSubject.getCode());

Or if you need to do it in one call:

list.addAll(Arrays.asList(newSubject.getName(), newSubject.getCode()));

You could also try to create a List only for Subject objects, but when you need to change your approach to add your listLines.

List&lt;Subject&gt; subjectList = new ArrayList&lt;&gt;();
Scanner input = new Scanner(System.in); // inport scanner

//read objects from List of Subjects txt file
try (BufferedReader list = new BufferedReader (new FileReader(&quot;ListofSubjects.txt&quot;))) {
    String listLine;
    while ((listLine = list.readLine()) != null) {
        Subject subject = new Subject();
        subject.setName(listLine); // or setCode()
        subjectList.add(subject);
    }
} catch (IOException e) { // catch any exceptions 
}

答案2

得分: 0

问题在于您尝试混合您的列表包含的内容。

对于您从文件中读取的内容,您希望列表包含一个包含所有数据的单个 String

对于要添加的新主题,您希望添加一个自定义 Subject 类的对象。

您不能这样做*。您的列表要么是一个 List<String>,要么是一个 List<Subject>

我的建议是使用更明确的类型(因为您已经有一个 Subject 类),并使用 List<Subject>。首先,您必须更改 subjectList 的声明:

ArrayList<Subject> subjectList = new ArrayList<>();

这意味着您需要修改从文件中读取的代码,以便也构造 Subject 对象:

try (BufferedReader list = new BufferedReader(new FileReader("ListofSubjects.txt"))) {
    String listLine;
    while ((listLine = list.readLine()) != null) {
        String[] lineParts = listLine.split(":", 2);
        Subject subject = new Subject(lineParts[0].trim(), lineParts[1].trim());
        subjectList.add(subject);
    }
}

这样,在您的代码中稍后,您可以确保 subjectList 仅包含 Subject 对象,无论是从文件中读取还是后来添加的。

* 实际上在泛型出现之前,您是可以这样做的,但这是一个糟糕的想法,而且泛型等等是为了摆脱混合集合而引入的。

英文:

The issue is that you are trying to mix what your list contains.

For the stuff you read from the file you want the list to hold a single String with all data.

For the new subject you want to add an object of your custom Subject class.

You can't do that <sup>*</sup>. Your list is either a List&lt;String&gt; or a List&lt;Subject&gt;.

My suggestions is to have the more-explicit type (since you already have a Subject class) and use List&lt;Subject&gt;. First you must change the declaration of your subjectList:

ArrayList&lt;Subject&gt; subjectList = new ArrayList&lt;&gt;();

That means you'll need to modify the code that reads from the file to construct Subject objects as well:

try (BufferedReader list = new BufferedReader (new FileReader(&quot;ListofSubjects.txt&quot;))) {
    String listLine;
    while ((listLine = list.readLine()) != null) {
        String[] lineParts = listLine.split(&quot;:&quot;, 2);
        Subject subject = new Subject(lineParts[0].trim(), lineParts[1].trim());
        subjectList.add(subject);
    }
}

This way later on in your code you can be sure that subjectList contains Subject objects only, no matter if you read them from the file or added them later.

<sup>* actually you can and before generics that was even somewhat common, but it's a terrible idea and among other things generics were introduced to get rid of inter-mixed collections.</sup>

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  • 本文由 发表于 2020年9月30日 18:41:29
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