force pureconfig to use -dconfig.file application.conf file and not resource application.conf

I have the following application.conf file:

# App
tables = [
    "table_1",
    "talbe_2"
]

and the following scala code:

import pureconfig._
import pureconfig.generic.auto._
import com.typesafe.config.ConfigFactory
import pureconfig.generic.ProductHint

case class Configuration(tables: Array[String])

object Config {
  implicit def hint[A] = ProductHint[A](ConfigFieldMapping(CamelCase, CamelCase))

  val conf = ConfigSource.fromConfig(ConfigFactory.load("application.conf")).load[Configuration] match {
    case Right(conf) => conf
    case Left(failures) => throw new Exception(s"Unable to load the configuration ${failures.toList.mkString("\n")}")
  }
}

and to test the application.conf, I have this code:

object Test extends App {

  val res = Config.conf.tables
  println("hello")
}

when I drop application.conf in resources folder, it works. But It does not works when i use

-Dconfig.file=C:/Users/path/to/application.conf

It use the resources application.conf file despite the one in argument -Dconfig.file.
Do you have any idea?

The problem is the call

ConfigFactory.load("application.conf")

From scaladocs

> Loads an application's configuration from the given classpath resource
> or classpath resource basename, sandwiches it between default
> reference config and default overrides, and then resolves it.

You have to use

ConfigFactory.load()

which

> Loads a default configuration, equivalent to
> load(defaultApplication())

And defaultApplication supports config.file

> If the system properties config.resource, config.file, or config.url
> are set, then the classpath resource, file, or URL specified in those
> properties will be used rather than the default
> application.{conf,json,properties} classpath resources.