Throw error if strings are not double quoted while using jackson objectmapper deserialization

huangapple
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英文:

Throw error if strings are not double quoted while using jackson objectmapper deserialization

问题

  1. 我有一个JSON：
  3. {
  4.     "stringField" : 1234,
  5.     "booleanField": true,
  6.     "numberField": 1200.00
  7. }
  9. 我使用对象映射器将JSON反序列化为：
  11. @Data
  12. class SomeClass {
  13.     String stringField;
  14.     boolean booleanField;
  15.     float numberField;
  16. }
  18. 我希望对象映射器抛出错误，因为根据JSON规范，字符串字段的值必须用双引号括起来。如何让对象映射器抛出错误？
英文:

I have a JSON:

  1. {
  2.     "stringField" : 1234,
  3.     "booleanField": true,
  4.     "numberField": 1200.00
  5. }

I use object mapper to deserialize the json into:-

  1. @Data
  2. class SomeClass {
  3.     String stringField;
  4.     boolean booleanField;
  5.     float numberField;
  6. }

I would like the objectMapper to throw an error because, the values for String fields must be double quoted according to the json spec. How can i get objectMapper to throw an error?

答案1

得分: 1

你可以编写自定义的字符串反序列化器。（我假设你正在使用 Spring）

  1. @Configuration
  2. public class JacksonConfiguration {
  4.     @Bean
  5.     SimpleModule jacksonDeserializerConfiguration() {
  6.         SimpleModule module = new SimpleModule();
  7.         module.addDeserializer(String.class, new StdDeserializer<String>(String.class) {
  8.             @Override
  9.             public String deserialize(JsonParser parser, DeserializationContext context)
  10.                     throws IOException {
  11.                 if (!parser.hasToken(JsonToken.VALUE_STRING)) {
  12.                     // 抛出异常，你想要什么样的异常
  13.                     throw new RuntimeException("字符串不包含引号");
  14.                 }
  15.                 return StringDeserializer.instance.deserialize(parser, context);
  16.             }
  17.         });
  18.         return module;
  19.     }
  20. }
英文:

You can write custom string deserializer.(i assume you are using spring)

  1. @Configuration
  2. public class JacksonConfiguration {
  4.     @Bean
  5.     SimpleModule jacksonDeserializerConfiguration() {
  6.         SimpleModule module = new SimpleModule();
  7.         module.addDeserializer(String.class, new StdDeserializer&lt;String&gt;(String.class) {
  8.         @Override
  9.         public String deserialize(JsonParser parser, DeserializationContext context)
  10.                 throws IOException {
  11.              if (!parser.hasToken(JsonToken.VALUE_STRING)) {
  12.                 //throw ex what do u want
  13.                 throw new RuntimeException(&quot;String not include quote&quot;);
  14.             }
  15.             return StringDeserializer.instance.deserialize(parser, context);
  16.         }
  17.     });
  18.         return module;
  19.     }
  20. }

答案2

得分: 0

这应该可以解决你的问题。

  1. class SomeClass {
  2.     @JsonDeserialize(using=ForceStringDeserializer.class)
  3.     public String stringField;
  4.     public boolean booleanField;
  5.     public float numberField;
  6. }
  8. class ForceStringDeserializer extends JsonDeserializer<String> {
  9.     @Override
  10.     public String deserialize(JsonParser jsonParser, DeserializationContext deserializationContext) throws IOException {
  11.         if (jsonParser.getCurrentToken() != JsonToken.VALUE_STRING) {
  12.             throw deserializationContext.wrongTokenException(jsonParser, JsonToken.VALUE_STRING, "尝试将整数解析为字符串，但是这是被禁止的");
  13.         }
  14.         return jsonParser.getValueAsString();
  15.     }
  16. }
英文:

This should fix your issue.

  1. class SomeClass {
  2.     @JsonDeserialize(using=ForceStringDeserializer.class)
  3.     public String stringField;
  4.     public boolean booleanField;
  5.     public float numberField;
  6. }
  9. class ForceStringDeserializer extends JsonDeserializer&lt;String&gt; {
  10.     @Override
  11.     public String deserialize(JsonParser jsonParser, DeserializationContext deserializationContext) throws IOException {
  12.         if (jsonParser.getCurrentToken() != JsonToken.VALUE_STRING) {
  13.             throw deserializationContext.wrongTokenException(jsonParser, JsonToken.VALUE_STRING, &quot;Attempted to parse Integer to String but this is forbidden&quot;);
  14.         }
  15.         return jsonParser.getValueAsString();
  16.     }
  17. }

答案3

得分: 0

你只需要像这样设置 jackson objectmapper

  1. JsonFactory factory = new JsonFactory();
  2. factory.disable(JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES);
  3. ObjectMapper mapper = new ObjectMapper(factory)

这样在序列化/反序列化过程中应该会抛出错误。

英文:

You just need to setup jackson objectmapper like this

  1. JsonFactory factory = new JsonFactory();
  2. factory.disable(JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES);
  3. ObjectMapper mapper = new ObjectMapper(factory)

This should throw error during serialization/deserilaization

huangapple
  • 本文由 发表于 2020年9月28日 19:34:44
  • 转载请务必保留本文链接：https://go.coder-hub.com/64101409.html
  • jackson
  • java
  • objectmapper
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