英文:
Regex Extract number between multiple words combination
问题
需要根据多个词（LandLine|Mobile）从以下输入中提取手机号码。我无法提取所有3个号码。需要在给定词组之前和之后读取数字。请协助
词组：（LandLine|Mobile）
字符串行 = "我是Joe，我的座机号码是987654321，另一个号码123456789是我的手机，妻子的手机号码是776655881";
字符串模式 = "(Mobile|LandLine)([^\\d]*)(\\d{9})|" //正向读取
+ "(\\d{9})([^\\d]*)(Mobile|LandLine)"; //反向读取
模式 r = Pattern.compile(字符串模式, Pattern.CASE_INSENSITIVE);
匹配器 matcher = r.matcher(字符串行);
while (matcher.find()) {
System.out.println(字符串行.substring(matcher.start(), matcher.end()));
}
代码输出：
座机号码是987654321
123456789是我的手机和妻子手机
期望输出：
座机号码是987654321
123456789是我的手机
手机号码是776655881
英文:
Need to extract mobile numbers based on multiple words(LandLine|Mobile) scan from the below input. I am not able to extract all the 3 numbers. Need to read the number before and after the given words combination .Please assist
Words: (LandLine|Mobile)
String line = "i'm Joe my LandLine number is 987654321, another number 123456789 is my Mobile and wife Mobile number is 776655881";
String pattern = "(Mobile|LandLine)([^\\d]*)(\\d{9})|" //Forward read
+"(\\d{9})([^\\d]*)(Mobile|LandLine)"; //Backward read
Pattern r = Pattern.compile(pattern, Pattern.CASE_INSENSITIVE);
Matcher matcher = r.matcher(line);
while(matcher.find()) {
System.out.println(line.substring(matcher.start(), matcher.end()));
}
Code Output:
LandLine number is 987654321
123456789 is my Mobile and wife Mobile
Expected Output:
LandLine number is 987654321
123456789 is my Mobile
Mobile number is 776655881
答案1
得分: 2
以下是翻译好的内容：
这个模式 "(LandLine|Mobile)\\D*\\d{9}|\\d{9}.*?(LandLine|Mobile)" 似乎符合要求：
import java.util.Arrays;
import java.util.regex.MatchResult;
import java.util.regex.Pattern;
class Main {
public static void main(String[] args) {
var line = "我是 Joe，我的座机号码是 987654321，另一个号码 123456789 是我的手机，妻子的手机号码是 776655881";
var pattern = "(LandLine|Mobile)\\D*\\d{9}|\\d{9}.*?(LandLine|Mobile)";
var res = Pattern
.compile(pattern)
.matcher(line)
.results()
.map(MatchResult::group)
.toArray(String[]::new);
System.out.println(Arrays.toString(res));
}
}
输出：
<!-- language: none -->
[座机号码是 987654321, 123456789 是我的手机, 手机号码是 776655881]
这在 `.*?` 后面添加了惰性量词 `?`，同时进行了一些较小的语义优化，如使用 `\\D` 代替 `[^\\d]`。
英文:
The pattern "(LandLine|Mobile)\\D*\\d{9}|\\d{9}.*?(LandLine|Mobile)" seems to fit the bill:
import java.util.Arrays;
import java.util.regex.MatchResult;
import java.util.regex.Pattern;
class Main {
public static void main(String[] args) {
var line = "i'm Joe my LandLine number is 987654321, another number 123456789 is my Mobile and wife Mobile number is 776655881";
var pattern = "(LandLine|Mobile)\\D*\\d{9}|\\d{9}.*?(LandLine|Mobile)";
var res = Pattern
.compile(pattern)
.matcher(line)
.results()
.map(MatchResult::group)
.toArray(String[]::new);
System.out.println(Arrays.toString(res));
}
}
Output:
<!-- language: none -->
[LandLine number is 987654321, 123456789 is my Mobile, Mobile number is 776655881]
This adds a lazy quantifier ? to .*? along with some minor semantic optimizations like \\D instead of [^\\d].
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