用户输入到Java中的两个单独数组。

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英文:

User input to 2 separate arrays in Java

问题

我对Java语言完全不熟悉。我还在学习和练习,但在解决一个问题时,我遇到了困难。我想做的是每行添加2个元素到2个单独的数组中。第一个元素放入X数组,第二个元素放入Y数组。

public static void main (String[] args) throws IOException {
    BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
    int n = Integer.parseInt(reader.readLine());

    double[] X = new double[n];
    double[] Y = new double[n];

    String[] elem = reader.readLine().split(" ");
    for(int i = 0; i < n; i++) {

        X[i] = Double.parseDouble(elem[0]);
        Y[i] = Double.parseDouble(elem[1]);

    }

    System.out.println(Arrays.toString(X) + " " + Arrays.toString(Y));
}

输入:

3 4

1 1

2 3

其中第一列是X数组,第二列是Y数组。我多次尝试了代码,但仍然出现“Index 2 out of bounds for length 2”的错误。

英文:

I'm completely new to the Java language. I'm still learning and practicing it but while solving a problem, I got stuck at this. What I want to do is to add 2 elements per line into 2 separate arrays. The first element goes to the X array and the second element goes to the Y array.

public static void main (String[] args) throws IOException {
        BufferedReader reader =new BufferedReader(new InputStreamReader(System.in));
        int n = Integer.parseInt(reader.readLine());

        double[] X = new double[n];
        double[] Y = new double[n];

        String[] elem = reader.readLine().split(&quot; &quot;);
        for(int i = 0; i &lt; n; i++)
        {

                X[i] = Integer.parseInt(elem[n]);
                Y[i] = Integer.parseInt(elem[n]);

        }

        System.out.println(X, Y);
    }

input:

3 4

1 1

2 3

where the first column is array X and the second column is array Y. I played with code several times but it still gives me "Index 2 out of bounds for length 2".

答案1

得分: 1

你必须在 for 循环内部读取你的行。X[i] 对应于 elem[0]Y[i] 对应于 elem[1]。例如:

import java.io.*;
import java.util.*;
public class App {
    public static void main(String[] args) throws IOException {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        int n = Integer.parseInt(reader.readLine());

        double[] X = new double[n];
        double[] Y = new double[n];

        for (int i = 0; i < n; i++) {
            String[] elem = reader.readLine().split(" ");
            X[i] = Integer.parseInt(elem[0]);
            Y[i] = Integer.parseInt(elem[1]);
        }
        System.out.println(Arrays.toString(X));
        System.out.println(Arrays.toString(Y));
    }
}
英文:

You have to read your lines inside the for loop. X[i] corresponds to elem[0]; Y[i] corresponds to elem[1]. For example:

import java.io.*;
import java.util.*;
public class App {
    public static void main(String[] args) throws IOException {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        int n = Integer.parseInt(reader.readLine());

        double[] X = new double[n];
        double[] Y = new double[n];

        for (int i = 0; i &lt; n; i++) {
            String[] elem = reader.readLine().split(&quot; &quot;);
            X[i] = Integer.parseInt(elem[0]);
            Y[i] = Integer.parseInt(elem[1]);
        }
        System.out.println(Arrays.toString(X));
        System.out.println(Arrays.toString(Y));
    }
}

答案2

得分: 0

这部分不正确:

for(int i = 0; i &lt; n; i++)
{
        X[i] = Integer.parseInt(elem[n]);
        Y[i] = Integer.parseInt(elem[n]);

看起来应该是这样的:

for(int i = 0; (i - 1)&lt; n; i+= 2) // 每次迭代从elem中读取两个值,因此增加2。将检查条件改为i - 1,以修复奇数个条目的情况,否则会导致elem中在i/2 + 1位置上的ArrayOutOfBoundsException。
{
        X[i/2] = Integer.parseInt(elem[i]);
        Y[i/2] = Integer.parseInt(elem[i] + 1);

(此处我的回答中存在错误,已经进行了修正)

或者可以选择:

for(int i = 0; i &lt; n; i++)
{
  if (i % 2 == 0) X[i/2] = Integer.parseInt(elem[i]);
    else Y[i/2] = Integer.parseInt(elem[i]);
英文:

This part is not right:

    for(int i = 0; i &lt; n; i++)
    {
            X[i] = Integer.parseInt(elem[n]);
            Y[i] = Integer.parseInt(elem[n]);

It seems like it should be

    for(int i = 0; (i - 1)&lt; n; i+= 2) // adding two because you are reading two values from elem in every iteration. Changed check to i - 1 to fix case where an odd number of entries will cause an ArrayOutOfBoundsException in elem on i/2 + 1
    {
            X[i/2] = Integer.parseInt(elem[i]);
            Y[i/2] = Integer.parseInt(elem[i] + 1);

(There was a bug in my answer here. It has been fixed)

Alternatively:

for(int i = 0; i &lt; n; i++)
{
  if (i % 2 == 0) X[i/2] = Integer.parseInt(elem[i]);
    else Y[i/2] = Integer.parseInt(elem[i]);

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  • 本文由 发表于 2020年9月28日 06:12:33
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