英文:
How does this add up?
问题
Sure, here is the translated code:
public class Main{
public static void main(String args[]){
char a='3';
int b=011;
System.out.println(a+b);
}
}
The answer turns out to be 60 but I don't understand how.
Could anyone please explain.
Thanks in advance :)
英文:
<!-- language: lang-java -->
public class Main{
public static void main(String args[]){
char a='3';
int b=011;
System.out.println(a+b);
}
}
The answer turns out to be 60 but I don't understand how.
Could anyone please explain.
Thanks in advance 
答案1
得分: 3
首先，char + int 等于 int。因此，你将 char '3' 扩展为 int 51。其次，具有前导 0 的数字是八进制表示法。因此，011 是表示十进制 9 的另一种方式。51 + 9 = 60，或者
System.out.printf("%d + %d = %d%n", (int) a, b, a + b);
英文:
First, char + int is an int. So you're widening the char '3' to int 51. Second, numbers with a leading 0 are in octal. So 011 is another way to write decimal 9. 51 + 9 = 60, or
System.out.printf("%d + %d = %d%n", (int) a, b, a + b);
答案2
得分: 0
欢迎来到Stack Overflow！祝您旅途愉快！
当您将一个char和一个int相加时，结果将会是一个int。在这种情况下，char会被解释为其ASCII值，因此'3'对应的ASCII值是51。而011是一个八进制数，所以会被解释为1 * 8 + 1 = 9。因此，51 + 9 = 60。
英文:
welcome to stack overflow! Hope a good trip!
when you add a char and an int, it will output an int. In the situation, the char will be explained into its ASCII<https://www.ascii-code.com/> value, so '3' is 51. 011 is an octal number so it will be explained as 1 * 8 + 1 = 9. So, 51+9 = 60.
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