打印出具有给定输入参数的单词列表。

huangapple
go评论89阅读模式
英文:

Printing out a list of words with the given input parameters

问题

  1. public void drawL(int g, char h){
  2.         
  3.     int i = 1;
  4.     
  5.     while (i <= g){
  6.         
  7.         i += 1;
  8.         if(i == g){
  9.             
  10.             System.out.println(h);
  11.             System.out.println(h + "" + h);
  12.             System.out.println(h + "" + h + "" + h);
  13.             System.out.println(h + "" + h + "" + h + "" + h);
  14.             System.out.println(h + "" + h + "" + h + "" + h + "" + h);
  15.             
  16.         }
  17.         
  18.     }
  20. }
英文:

The return type is void and two input parameters which are int, char. I am using a while loop because I want to solve this problem with a while loop and the method will basically print out like a ladder.
Example: drawL(6, '@') will print

@

@@

@@@

@@@@

@@@@@

@@@@@@

But without those spaces in between so it would be smooshed. I've come up with this code but the problem is that if I input 5 or 4 or 7 any number then 6 it won't print out that many char with that integer so if it was 4,'@' then it would still print out those many @ above.

  1. public void drawL(int g, char h){
  2.         
  3.         int i = 1;
  4.         
  5.         while (i &lt;= g){
  6.             
  7.             i += 1;
  8.             if(i == g){
  9.                 
  10.                 System.out.println(h);
  11.                 System.out.println(h+&quot;&quot;+h);
  12.                 System.out.println(h+&quot;&quot;+h+&quot;&quot;+h);
  13.                 System.out.println(h+&quot;&quot;+h+&quot;&quot;+h+&quot;&quot;+h);
  14.                 System.out.println(h+&quot;&quot;+h+&quot;&quot;+h+&quot;&quot;+h+&quot;&quot;+h);
  15.                 
  16.             }
  17.             
  18.         }
  20.     }

答案1

得分: 1

你可能需要在这里使用嵌套的双重循环。外层循环将控制行数，内层循环将控制打印出多少个字符。

  1. public static void drawL(int g, char h) {
  2.     for (int i=0; i < g; ++i) {
  3.         for (int j=0; j <= i; ++j) {
  4.             System.out.print(h);
  5.         }
  6.         System.out.println();
  7.     }
  8. }
  10. public static void main(String[] args) {
  11.     drawL(6, '@');
  12. }

从上述对drawL()的调用的输出如下：

  1. @
  2. @@
  3. @@@
  4. @@@@
  5. @@@@@
  6. @@@@@@
英文:

You should probably use a nested double loop here. The outer loop will control the row, and the inner loop will control how many characters are printed.

  1. public static void drawL(int g, char h) {
  2.     for (int i=0; i &lt; g; ++i) {
  3.         for (int j=0; j &lt;= i; ++j) {
  4.             System.out.print(h);
  5.         }
  6.         System.out.println();
  7.     }
  8. }
  10. public static void main(String[] args) {
  11.     drawL(6, &#39;@&#39;);
  12. }

The output from the above call to drawL() was this:

  1. @
  2. @@
  3. @@@
  4. @@@@
  5. @@@@@
  6. @@@@@@

答案2

得分: 1

  1. 如果您坚持使用while循环，可以像这样做：
  3. class Main {
  4.     public static void drawL(int n) {
  5.         int i = 1;
  6.         while (i <= n) {
  7.             int j = 1;
  8.             while(j <= i) {
  9.                 System.out.print('@');
  10.                 j += 1;
  11.             }
  12.             i += 1;
  13.             System.out.println();
  14.         }
  16.     }
  18.     public static void main(String[] args) {
  19.         drawL(6);
  20.     }
  21. }
  23. 使用Java 8的stream库替代实现`drawL()`方法。
  25. import java.util.stream.IntStream;
  27. public static void drawL(int n) {
  28.     IntStream.rangeClosed(1, n).forEach(i -> {
  29.         IntStream.rangeClosed(1, i).forEach(j -> 
  30.             System.out.print('@'));
  31.         System.out.println();
  32.     });
  33. }
  35. 输出：
  37. @
  38. @@
  39. @@@
  40. @@@@
  41. @@@@@
  42. @@@@@@
英文:

If you insist on using while loops, you could do it like this:

  1. class Main {
  2.     public static void drawL(int n) {
  3.         int i = 1;
  4.         while (i &lt;= n) {
  5.             int j = 1;
  6.             while(j &lt;= i) {
  7.                 System.out.print(&#39;@&#39;);
  8.                 j += 1;
  9.             }
  10.             i += 1;
  11.             System.out.println();
  12.         }
  14.     }
  16.     public static void main(String[] args) {
  17.         drawL(6);
  18.     }
  19. }

Alternative implementation of drawL() using the Java 8 stream library.

  1. import java.util.stream.IntStream;
  3. public static void drawL(int n) {
  4.     IntStream.rangeClosed(1, n).forEach(i -&gt; {
  5.         IntStream.rangeClosed(1, i).forEach(j -&gt; 
  6.             System.out.print(&#39;@&#39;));
  7.         System.out.println();
  8.     });
  9. }

Output:

  1. @
  2. @@
  3. @@@
  4. @@@@
  5. @@@@@
  6. @@@@@@

答案3

得分: 0

可以使用“for循环”来解决这个问题：

  1. public class Main {
  2.     public static void main(String[] args) {
  3.         drawL(4,'@');
  4.         System.out.println();
  5.         drawL(5,'@');
  6.     }
  7.     public static void drawL(int g, char h){
  8.         for(int i = 0; i < g; i++) {
  9.             for(int j = 0; j < i+1; j++) {
  10.                 System.out.print(h);
  11.             }
  12.             System.out.println();
  13.         }
  14.     }
  15. }

输出结果：

  1. @
  2. @@
  3. @@@
  4. @@@@
  6. @
  7. @@
  8. @@@
  9. @@@@
  10. @@@@@
英文:

You can use for-loops to solve this:

  1. public class Main {
  2. 	public static void main(String[] args) {
  3. 		drawL(4,&#39;@&#39;);
  4. 		System.out.println();
  5. 		drawL(5,&#39;@&#39;);
  6. 	}
  7. 	public static void drawL(int g, char h){
  8. 		for(int i = 0; i &lt; g; i++) {
  9. 			for(int j = 0; j &lt; i+1; j++) {
  10. 				System.out.print(h);
  11. 			}
  12. 			System.out.println();
  13. 		}
  14. 	}
  15. }

Output:

  1. @
  2. @@
  3. @@@
  4. @@@@
  6. @
  7. @@
  8. @@@
  9. @@@@
  10. @@@@@

答案4

得分: 0

以下是翻译好的内容：

你也可以使用 String.repeat() 方法轻松实现这一点。

  1. drawL(6, '@');
  3. public static void drawL(int g, char h) {
  4.     for (int i = 1; i <= g; ++i) {
  5.         System.out.println(String.valueOf(h).repeat(i));
  6.     }
  7. }

或者使用 while 循环

  1. public static void drawL(int g, char h) {
  2.     int k = g;
  3.     while (k-- > 0) {
  4.         System.out.println(String.valueOf(h).repeat(g - k));
  5.     }
  6. }

两者都会输出

  1. @
  2. @@
  3. @@@
  4. @@@@
  5. @@@@@
  6. @@@@@@
英文:

You can also do it very easily using the String.repeat() method.

  1. drawL(6,&#39;@&#39;);
  3. public static void drawL(int g, char h) {
  4.     for (int i=1; i &lt;= g; ++i) {
  5.         System.out.println((h+&quot;&quot;).repeat(i));
  6.     }
  7. }

Or with a while loop

  1. public static void drawL(int g, char h) {
  2. 	int k = g;
  3.     while(k-- &gt; 0) {
  4.         System.out.println((h+&quot;&quot;).repeat(g-k));
  5.     }
  6. }

Both print

  1. @
  2. @@
  3. @@@
  4. @@@@
  5. @@@@@
  6. @@@@@@
  9. </details>

huangapple
  • 本文由 发表于 2020年9月26日 22:18:53
  • 转载请务必保留本文链接：https://go.coder-hub.com/64078731.html
  • java
  • while-loop
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