返回由字符串奇数索引位置的字符组成的字符串

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英文:

Returning a string made by odd index number of the string

问题

public class MeWhileLoop
{
    
    public int a, b;
    public String str;

    public String OddNumChar(){
        
        int index = 0;
        str = "Poland";
        String result = "";  // Initialize an empty string to store the result
        
        while(index < str.length()){
            if(index % 2 != 0){  // Check if the index is odd
                result += str.substring(index, index+1);  // Append the odd-indexed character to the result
            }
            index++;
        }
        
        return result;  // Return the string containing odd-indexed characters
    }

}
英文:

The Return type is a String and no Input parameters. I have to go through the instance variable called str and return a string that is put together by odd index number of the string.

i forgot to mention that it has to be a while loop

Example: str = "Poland"

     then the method should return &quot;oad&quot; because P is an even number, o is odd, l is even, a is odd, n is even, d is odd.

I so far have come up with this

public class MeWhileLoop
{
    
    public int a, b;
    public String str;

    public String OddNumChar(){
        
        int index = 0;
        str = &quot;Poland&quot;;
        while(index &lt; str.length()){
            
            System.out.println(str.substring(index, index+1));
            index++;
            
        }
        System.out.println();
        return str;
    }

}

I'm just stuck because the index+1 won't take out the odd letters or any letter at all and I have no clue why.

答案1

得分: 3

以下是翻译好的内容:

第一段代码:

如何考虑

    String res = "";

    // 从第二个字符开始,然后每次增加2
    for (int i = 1; i < str.length(); i += 2) {
        res += str.charAt(i);
    }

    return res;

第二段代码:

对于更大的字符串这可能具有更好的性能

    StringBuilder sb = new StringBuilder(str.length() / 2);

    for (int i = 1; i < str.length(); i += 2) {
        sb.append(str.charAt(i));
    }

    return sb.toString();

第三段代码:

如果出于某种原因确实需要使用 while 循环

    String res = "";

    int i = 1;
    while (i < str.length()) {
        res += str.charAt(i);
        i += 2;
    }

    return res;
英文:

How about:

String res = &quot;&quot;;

// start at second character and then increment by 2
for (int i = 1; i &lt; str.length(); i += 2) {
    res += str.charAt(i);
}

return res;

This might have better performance for larger strings:

StringBuilder sb = new StringBuilder(str.length() / 2);

for (int i = 1; i &lt; str.length(); i += 2) {
    sb.append(str.charAt(i));
}

return sb.toString();

If you really need while loop for some reason:

String res = &quot;&quot;;

int i = 1;
while (i &lt; str.length()) {
    res += str.charAt(i);
    i += 2;
}

return res;

huangapple
  • 本文由 发表于 2020年9月26日 04:30:33
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