英文:
Reverse array with for loop in Java
问题
以下是您提供的代码的翻译部分：
我想知道您是否可以帮助我处理这段代码。它应该颠倒数组的内容，但我得到了这个结果。是否有人知道如何修复这个问题？
import java.util.Arrays;public class Arrays7 {public static void main(String[] args) {// 编写一个Java程序来颠倒整数值的数组。int arr[] = { 1, 2, 3, 4, 5};int petlja[] = { 0, 0, 0, 0, 0 };/* arr[0] = petlja[4];arr[1] = petlja[3];arr[2] = petlja[2];arr[3] = petlja[1];arr[4] = petlja[0];*/for ( int i=4; i>0; i--) {for ( int j=0; j<4; j++) {petlja[j] = arr[i];}}System.out.println(Arrays.toString(petlja));}}
英文:
I was wondering if you can help me around this code. It should reverse content of array but I get this. Does anyone know how to fix this?
import java.util.Arrays;public class Arrays7 {public static void main(String[] args) {// Write a Java program to reverse an array of integer values.int arr[] = { 1, 2, 3, 4, 5};int petlja[] = { 0, 0, 0, 0, 0 };/* arr[0] = petlja[4];arr[1] = petlja[3];arr[2] = petlja[2];arr[3] = petlja[1];arr[4] = petlja[0];*/for ( int i=4; i>0; i--) {for ( int j=0; j<4; j++) {petlja[j] = arr[i];}}System.out.println(Arrays.toString(petlja));
答案1
得分: 1
你不需要嵌套循环 - 只需要一个循环来遍历数组，并将每个元素赋值给相应的“反转”数组：
for (int i = arr.length - 1; i >= 0; i--) {petlja[petlja.length - i] = arr[i];}
英文:
You don't need a nested loop - you need only one loop to go over the array and assign each element to the corresponding "reversed" array:
for (int i = arr.length - 1; i >= 0; i--) {petlja[petlja.length - i] = arr[i];}
答案2
得分: 0
你可以这样做：
for(int i = 0; i < array.length; i++) {petlja[i] = arr[array.length-i-1];}
示例输入/输出
输入
1, 2, 3, 4, 5
输出
5, 4, 3, 2, 1
英文:
You can do it like so:
for(int i = 0; i < array.length; i++) {petlja[i] = arr[array.length-i-1];}
Sample I/O
Input
1, 2, 3, 4, 5
Output
5, 4, 3, 2, 1
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