英文:
Retrieving a few fields from large response object
问题
我正在调用Google Directory API，并且只需要返回的一些字段。我对Java/Spring相对不熟悉，所以我正在尝试找出最佳的方法。我目前的请求是这样的：
restTemplate.exchange(url, HttpMethod.GET, req, Object, userKey);
我目前将其设置为Object，但不确定是否正确。当我只需要一些字段时，我不想映射出它返回的非常庞大的对象。是否有一种方法可以访问字段phone, organizations, locations？
res.getClass().getField("phones")对我不起作用。
为了说明对象的形状，我们可以考虑以下示例：
{
"phones": [{"type": "String", "number": "String"}],
"organizations": [{"title": "String"}],
"locations": [{"buildingId": "String"}]
}
英文:
I am making a call to Google Directory API and only need a few fields it is returning. I am fairly new to Java/Spring so I am trying to figure out what is the best way to go about this. I am making my request like this:
restTemplate.exchange(url, HttpMethod.GET, req, Object, userKey);
I currently have it as an Object, but not sure if this is correct. I do not want to map out the very large object it returns when I only need a few fields. Is there a way to access the fields, phone, organizations, locations ?
res.getClass().getField("phones") did not work for me.
For purposes we can consider the shape of the object:
{
phones: [type: String, number: String],
organizations: [title: String],
locations: [buildingId: String]
}
答案1
得分: 0
你可以将响应的 JSON 解析为 JsonNode。
ObjectMapper mapper = new ObjectMapper();
JsonNode jsonNode = mapper.readTree("【在这里填入你的 JSON】");
然后只获取你需要的字段。例如：
jsonNode.get("request").get("phones").get("type").asText()
或者只获取 phones 对象。
英文:
You can parse your response JSON as JsonNode.
ObjectMapper mapper = new ObjectMapper();
JsonNode jsonNode = mapper.readTree("[your JSON here]");
After that get only fields, which you need. For example:
jsonNode.get("request").get("phones").get("type").asText()
or just a phones object
答案2
得分: -1
你应该能够执行类似以下的操作。在这里，“User”是 com.google.api.services.admin.directory.model.User。
List<User> users = result.getUsers();
if (users == null || users.size() == 0) {
System.out.println("未找到用户。");
} else {
System.out.println("用户：");
for (User user : users) {
System.out.println(user.getName().getFullName());
}
}
英文:
You should be able to do something like below. Here "User" is com.google.api.services.admin.directory.model.User
List<User> users = result.getUsers();
if (users == null || users.size() == 0) {
System.out.println("No users found.");
} else {
System.out.println("Users:");
for (User user : users) {
System.out.println(user.getName().getFullName());
}
}
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