英文:
Which of the following describes the return type and parameters of the Scanner method nextLine?
问题
以下是翻译好的内容：
问题是：下面哪个描述了Scanner方法nextLine的返回类型和参数？
我相当确定nextLine没有参数。我不确定的是返回类型是String还是void。哪个是正确的？
英文:
The question is: Which of the following describes the return type and parameters of the Scanner method nextLine?
I am pretty sure there are no parameters for nextLine. What I'm not sure of is if the return type is a String or void. Which one is it?
答案1
得分: 1
你可以查看一下javadoc：
public String nextLine()
这个公共方法没有参数，返回一个字符串。
英文:
You can take a look at the javadoc:
public String nextLine()
The public method has no parameters and return a String.
答案2
得分: 0
Scanner.nextLine()没有参数，返回一个字符串。
考虑以下代码：
import java.util.Scanner;
public class ScannerEx {
public static void main (String [] args) {
Scanner scanner = new Scanner(System.in);
String input = scanner.nextLine();
System.out.println(input);
}
}
如果我输入：
foobar
它将打印：
foobar
如果它是void类型，那么它将不返回任何内容。不仅不会有输出，还会出现编译错误。
英文:
Scanner.nextLine() has no parameters, and returns a String.
Consider this code:
import java.util.Scanner;
public class ScannerEx {
public static void main (String [] args) {
Scanner scanner = new Scanner(System.in);
String input = scanner.nextLine();
System.out.println(input);
}
}
If I enter:
foobar
It will print
foobar
If it was void, then it would return nothing. Not only would there be no output, but there would be a compilation error.
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